last day (17 days later) » 

02:45
Hello, please ask me what your concerns are.
check this link out, this is what i want to do:
i want that new point, is ur answer in my OP doing that?
02:48
Yes, my solution should work.
for starters, what are the things you need to know when solving a problem like this?
You want a calculator for trig. functions
evaluating cosine, sine, etc.
do i have to work with matrices?
Not necessarily, my answer doesn't have matrices
in ur answer, what is r?
02:50
Matrices can simplify things down though
r is the distance from the pivot to your point you are rotating
for example, x = rcos(angle)
given in the general r^2=x^2+y^2 using Pythagorean theorem
you started with substitutions, x = rcos(angle)
My method is particularly simple
what do we do with that distance?
i want to know ur train of thought behind all of htis
02:52
Multiply it after we rotate
rotating won't affect distance from origin/pivot
Get it?
I solved mine similar to De Moivres' method
y = rsin(agnle) is doing the same thing?
yes, rotating with the distance part factored out
very easy with a calculator
so if my angle is 45degrees, i use: x = rcos(45)?
Sort of
x1 is x prime?
02:56
We use x = r*cos(45+rotation)
x1 is first x coordinate
x1+y1=A?
for A, x1=4, y1=5
how do we get r?
find distance from (4,5) using Pythagorean theorem
or distance formula
(4,5) and (4,1)?
02:58
distance would be r = 4
ok just making sure
np
This place can really be nice, private tutors for free and all (except the tutorers here are very smart)
to calculate x1 = 4cos(45 + pi/4)?
i bet they are smart, this stuff is so new to me, im used to geometry
Um, wait
and x1 is the point we looking for?
03:00
x1 = 0*cos(stuff)
distance from A to (4,5) = 0
Are we talking about B?
er, I mean C?
nooo dont confuse me
hah
A = 4,5, B = 4,1
x1 = 4 * cos(45 + pi/4)?
03:02
we are comparing the distance to the pivot point
that is, the point we are rotating around
hmmm
x != x1?
we comparing B to x1?
yup
wait, slow down
Imagine trying to rotate (0,0) around (0,0)
The distance from pivot is r = 0
right, so there should be no change afterwards
so x has to = x1?
03:05
mhm...
that is just for A
For B, we have d = 4
and (from stuff), theta = 270
say we want to rotate it 30 degrees
so we now have: theta = 300
angle = theta?
the symbol
yeah
for our new x value, we have x = 4*cos(300)
but then....
we have to remember to add 4 to our x
because we rotated it around ("4",5)
so it is x=4*cos(300)+4
what i did was : x = 4 * cos(45) = 2.101, x1 = 4 * cos (45 + pi/4) = -.92088, x is not x1
plug into calculator
well, you have to actually find the old angle
which you can use trigonometry for
i got 3.9116
03:09
That is probably right for mine
but I rotated it 30 degrees
that 1 is urs, but now im confused
one second
When I said x=x1, I was talking about "A"
all i know is (4,5) to (4,1) = 4, the rotation is 45degrees
A=(4,5)
right...
i dont know what to do from there
03:11
but what do you want to rotate around what?
4,5 rotate 45degrees
a-b
how do i start?
You want to rotate (4,1) around (4.5) by 45 degrees
there we go yes
We know d = 4
we know the angle/theta is 270 (from some trigonometry or looking at a graph)
oh, wait
how did u get 270?
03:13
let me tell you how I found it
0 degrees equals right
90=up
180=right...
270=down
180= left?
yeah, my bad
:3
270 is down
and 360 = right
We see that 4,1 is directly down, below 4,5
so 270 degrees
quadrant IV?
03:14
If its somewhere else, trigonometry, something I can't explain
No, note quadrants, just where 4,1 is in relation to 4,5
so we know it's 270
yes
r=4
isnt it in 0-90?
4,5 and 4,1 are in the first quadrant where 0->90
03:15
Um, I believe we just proceed as follows:
hmm so i have to know more stuff to understand how u got 270?
no, we are looking at 4,1
no, no, no
look at 4,1 on a graph
look at 4,5 on the same graph.
4,1 is simply directly below 4,5
If I leave randomly, its because my mom said so and its late...
is that wrong? it looks like 4, -1
are we reversing y?
(-y , x) (x, y)?
why in the graph is 4, 1 located below the x axis tho?
03:18
(4,1) is below (4,5), do you get that much?
that's really all we need to know it is 270 degrees
ok deal
:D and we have d=4
that'l be homework for me, so continuing on
03:19
ok, this part gets tricky if you don't really pay attention
You can rejoin this room later and I'll receive notifications btw
Look at the x values for (4,1) and (4,5)
ok np, kk
The x values are the same, so we say x=0
The y values are 4 less, so y=-4
03:21
yeah
we know 0=4*cos(270)
and - 4=4*sin(270)
That is simply our x/y values and plugging in the knowns/found
Our new x value will be x1=4*cos(270+45)
our new y value will be y1=4*sin(270+45)
2.666766240158
y = 2.98053305823
03:23
ok
and that's it?
wait, you messed up
Set your calculator to degrees mode
oops :D
x = 2.82842712475
don't do y, I don't have time
03:25
2.82842712475 is the amount right of (4,5)
y = -2.82842712475
ok
-2.82842712475 is the amount down from (4,5)
So our new point should be (4+2.82842712475 ,5-2.82842712475)
Put that into your calculator and your done
03:26
yes?
got it
ty :D
its that easy. (not sure what that means)
note that it will simply be harder to find the angle if it is not up/down, left/right
true
can we go over that tomorrow?
if u have time :D
Ask someone else on that topic, I have to go for tonight (don't ask it on this site, they'll downvote you like crazy)
I always find time
okay :D thanks again
03:28
If you leave messages here, I will respond.
Ta Ta for now!

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