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01:24
@mhchem mathrm{5 mol} is ok, right?
@Tanuj no login is there, you'll always be given the values of the critical constants
@AvatarShiny kthanx
@AvatarShiny Kindly turn your comments into an answer on that meta post
@AvatarShiny i have the 11th edition but still the same page number xD
@AvatarShiny Also, I left like 5 comments on 5 of your other questions
do have a look when you've time
@GaurangTandon really? I Didn't get any pings will do so
01:41
4 actually @AvatarShiny
@AvatarShiny yep, do so whenever you get some free time
@GaurangTandon Did that
@AvatarShiny yep, viewing
02:15
@AvatarShiny Why's that related in any way dude?
02:31
@GaurangTandon being nice to newbies
@AvatarShiny well, i think beerhunter is talking about a different issue; and the question you linked to was about being nice to "new askers/posters"
02:55
@GaurangTandon Yeah he's talking about how PhD people are subtly insulting others , be nice is related
@AvatarShiny fine, as you think
I deleted it just now :P
@AvatarShiny hehe
03:34
Hi
oxygen is electron withdrawing group or electron donating group in organic chemistry.
@Fawad as in COOH it is EWG but as in OH or OR it is EDG group
@GaurangTandon in benzoic acid EDG
So if oxygen can make resonance it is EDG and if it cannot form resonance it is EWG ?
@Fawad EWG
@Fawad nope
do you have some introductory book on +M/-M?
this is standard teaching
04:31
@GaurangTandon I have indeed been asked the same question without any values in the jee mains based paper
@GaurangTandon and for finkelstein , you're talking about fluoride acting as a leaving group , which is possible , but not feasible. $F^{-}$ is the weakest leaving group among all halogens .
@GaurangTandon Try for yourself, but I don’t think so. The space will be ignored; a thin space can be added using \;. codecogs.com/eqneditor is useful for testing.
Hey guys can you talk me through on how to decide the critical volumes , temperatures of certain gases , without knowing the values of critical constants ?
04:48
@Tanuj See virial equation
@AvatarShiny I know , but what about this chat.stackexchange.com/transcript/message/43046557#43046557
@Tanuj You can derive anything from that
I've not been given any values for any critical constants
@Tanuj Dipole moment
Not sure tho
@AvatarShiny Ah , now that sounds interesting ! Tell me more about it , how would Dipole moment play a part ?
04:52
@Tanuj Hydrogen bonding more so
Uhm okay , so if H2O has more extensive hydrogen bonding than NH3 , how would the critical volumes compare ?
@Tanuj tc would be higher for the H20
So would pc
@AvatarShiny Can you run me through the reason why it would be so ?
Attractive forces help in fusion
@AvatarShiny okay so here is my question , does extensive H bonding make a gas liquify easily ?
05:10
Yeah
0
Q: Why is veiled abuse tolerated?

BeerhunterThis, anecdotally, seems to come from the more academically orientated users. For some reason, protection of the Sacred Brotherhood of Chemists involves the odd poke at the new initiate. We were all there once, but the PhD/post-doc crowd like to laud their "knowledge" over less experienced pra...

@AvatarShiny so , water gets liquified even at higher temperatures than NH3 , so it must have higher critical temperature
@AvatarShiny But how to decide for $P_c$ and $V_c$
¯\_(ツ)_/ ¯
You can always ask on main
@AvatarShiny Alright man :) Thanks for the help though ! I've come a long way on this , didn't know what logic could be applied , but I have a way now
Dunz
Felt like that would be it
oh okay
06:04
@Tanuj sorry bro, I had read your question as "how to calculate" by mistake; my bad :(
@GaurangTandon It's alright man , any ideas now ?
@pentavalentcarbon actually pu{5 mol} works just fine, I stopped using \mathrm at all :P
@Tanuj yes that is very reasonable
@Tanuj you want to compare T_c,V_c, P_c for H2O and NH3?
@GaurangTandon I got the idea about $T_c$ what about $P_c$ and $V_c?
yes
@Tanuj hmm ok lemme think for 15mins
lol sure
06:11
@GaurangTandon Not really. You forgot the space. $\mathrm{5~mol}$ would be okay.
@mhchem okay thanks!
06:28
see, T_c is the temp above which the gas cannot be liquefied; higher T_c => higher energy being supplied by the surrounding to break the molecules's intermolecular forces (IMFs).
Now, since H2O has better IMF than NH3, so T_c of water is higher
getting it? @Tanuj
@GaurangTandon intermolecular forces as in ?
@GaurangTandon Hydrogen bonding ?
@Tanuj yeah that surely counts
okay . What intermolecular forces were you talking about ?
@Tanuj i mean whichever are there; in noble gases and non-polar molecules you have those london dispersion forces, in polar molecules you have dipole dipole interactions; in water and ammonia you have H-bonding; all these are IMFs
got it
@GaurangTandon $T_c$ seems to be clear .
06:36
critical pressure is the pressure that needs to be applied at critical temperature to liquefy 1 mole of gas; again, since H2O has higher IMF than NH3, its P_c is also higher
get it?
@GaurangTandon don't really get this, If H2O has higher H bonding , would it not liquify easily ?
@Tanuj duh I wrote the wrong thing; rewriting...
i'm kinda stumped
do you have any clues about comparing P_c @Tanuj?
what does the solution manual say?
06:54
@GaurangTandon There is no solution manual , the only correct option in the question though was -critical volume of H2O is less than NH3
alright I am posting a question on main site
wait
we are correct about $T_c$ though
so , any luck ?
i am posting question on main...
06:58
alright man , but I'll edit it ;)
Are you done ?
it's long, you'll see
ah okay ! Lol all i see is people trolling SE
Someone asked , Do all ideal gases have same molarity ?
haha really? where?
07:07
In the queue of newest questions , somewhere 9-10 from the top
dude ! you already have a comment on it :|
ah yeah i forgot
upvote it first ;)
and then if you need clarification or have to suggest changes, tell here first
dude what was that suggested edit?! You inserted needless spaces :( @Tanuj
i approved them for once though
i hope the content is okay?
07:23
@GaurangTandon Yea , they were there because I upvoted your question , or should i say my qyestion ;)
the question looks really good though , should be hard to ignore
@Tanuj hehe ;)
@Tanuj yeah I really hope someone comes up and writes a detailed answer to it
anyone with morison boyd has any idea about this? chemistry.stackexchange.com/q/91309/5026
I am pretty stumped :/
@GaurangTandon Yea , seems easy but no clue .
@Tanuj yep, looks really strange
08:21
@GaurangTandon @Tanuj took a shot at the question
@AvatarShiny thanks man :)
@AvatarShiny you took V_c to be inversely proprtional to b , its directly proprtional
yes Tanuj is right, is that a typo?
must be
Avatar you needn't hurry, take your time and edit your answer as much as you want to; I am not in any hurry at all :)
@GaurangTandon That was actually a math error
@Tanuj Thanks for the edit tho
08:36
sure thing :)
guys have a look at this problem
@AvatarShiny "become extremely shifty " what do you mean by "shifty" ? :-O
@Tanuj go to the h-bar ;)
@GaurangTandon no luck
@GaurangTandon even JR got it wrong
@Tanuj oh, lemme try then
08:41
yea sure
@Tanuj he got it wrong :-O
that invincible man :-O
or so i thought
yea lol i was shocked too
multiple-correct hai?
yup @GaurangTandon
08:46
I think it's CD; am I right or wrong Tanuj? (don't give the correct answer if I'm wrong)
Well, he did say he doesn't understand the question.
it's a great question though
After getting it wrong
(I haven't still opened the h-bar just in case to spoil the correct answer for myself)
@GaurangTandon yea ,let me know what options you got as correct
08:47
1 min ago, by Gaurang Tandon
I think it's CD; am I right or wrong Tanuj? (don't give the correct answer if I'm wrong)
@Tanuj ---^
wrong
arrgghh, ok trying again
well I think CD should be right
:(
its A,B,C
:-O
Now, that's tricky!!!
whoa just checked the PSS room JR agrees with me I'm so happpyyyy!!!
08:53
Definitely a "trap" question.
@Tanuj Why don't you ask it on main?
I don't get replies on the main for such questions
and i' mtoo tired to type all of that again !
You will if you ask it in polite manner.
now that two people agree that the answer is CD, you must accept that your answer key is wrong; and if you wanna challenge then you gotta post the question on main ;)
@GaurangTandon how did you do it ?
08:57
@Tanuj i know their hw-policy can be off-putting sometimes but if you phrase your question neatly enough you'll definitely get an answer if you include all your working
@Tanuj if you have to bring the point A at rest (which has velocity = 2v rightwards) you have to subtract that 2v from the velocity of com (which is v rightwards)
if you do that you'll get v_com = v leftwards
and this situation (with the pivot point A above center) is now identical to the one when the ring was rolling rightwards (with the pivot point B below center)
since both are clockwise
by pivot point I mean instantaneous axis of rotation
@GaurangTandon I don't get instantaneous axis of rotation , how do know the disc will rotate about these ?
@Tanuj well if you don't understand the IAOR I don't see any other way of explaining this to you... :(
i suggest do some practice on IAOR and then revisit this problem
okay
I'll be back
09:03
sure, i'll have to leave now, bye!
later
09:43
@Gaurang I give you two sets of numbers
And tell you
That in each set which one is
Small ,larger, largest
Then tell you to divide these numbers from across the set and
Arrange the divided result
In descending order?
Would you be able to?
 
3 hours later…
12:33
sure, why not? bring it in @AvatarShiny
13:09
@GaurangTandon Happy arranging
0
A: Formatting Sandbox II: please test stuff here

Avatar Shiny$$\ce{Ca^2+}$$ Gshdbdbjsisjsbdhhjsbsbshdvdvsjdjdjj$\ce{Ca^2+}$t T $$\ce{color}{red}{Ca^2+}$$ Can't figure out the color thing as of now did this work Google Some good links For me and if some new users happen to pass by https://stackoverflow.com/editing-help https://mhchem.github.io/M...

The data is in my sandbox
lol this is crazy
where's the numbers?
@GaurangTandon Dude tanuj's problem doesn't have numbers That's why I was saying it's not possible to arrange for Tc and Pc
:P
ha well your answer for that V_c was fine and I agree with that part; but rest, I'll wait for someone to come up with an explanation for P_c
i really want a reason for this wonderful trend
;)
@GaurangTandon You can't find the trend I t depends upon two factors
Mathematically
i know but I don't want to give the green checkmark so quickly ;) at least wait a week ;D
13:19
Ok man
Ok
12 hours ago, by Gaurang Tandon
user image
don't forget this @AvatarShiny
i'm waiting
@GaurangTandon Which one did I miss?
I thought I covered all of them
I didn't get a ping for any reply on those comments :/
I think I didn't ping you
duh
alright i'll check them out tomo
 
1 hour later…
14:33
@GaurangTandon thanks
@Abcd are you free right now?
@Tanuj depends on the problem. Got my reshuffling test, revising whole 11th so really busy
@Abcd it is from 11th. Check it. It's in this room.
@Tanuj will solve it later, doing chemistry right now.
Okay
14:42
@GaurangTandon How was CS exam?
2
Q: Acidity order of 4-halophenols

AbcdHow do I theoretically predict the acidity order of the following para-halophenols? (experimental $\mathrm{p}K\mathrm{a}$ values beside each) parafluorophenol (9.92) parachlorophenol (9.41) parabromophenol (9.17) paraiodophenol (9.30) At first, I thought of simply using the -I effect to deter...

5
Q: Explanation of bond angles in the aluminium chloride dimer

AbcdIn order to attain stability $\ce{AlCl3}$ dimerises to $\ce{Al2Cl6}$ whose structure is depicted as: I want to understand why one of the bond angles is $79^\circ$ and the other $118^\circ$. Is it possible to justify this using Bent's rule?

@Abcd a question from chemistry , give it a try if you have time .
which one @Tanuj?
Common ion effect...
14:51
yea
@Abcd what's your answer?
@Tanuj not solved ... will try later.
okay
15:15
@Abcd dude it was the easiest from entire past five years; i was amazed how straightforward it could really get; they didn't try to twist any problem even by a small degree
entire class was really happy
i myself finished half hour before, with extra questions attempted and doubled revision
hoping a century :D
@GaurangTandon what are you talking about ?
@Tanuj I was speaking to Abcd
I know what was it about ?
The boards paper ?
@Tanuj yep, the computer science paper day before
sweet :)
15:19
@Tanuj yeah :)
@GaurangTandon give it a try
30 mins ago, by Tanuj
user image
@Tanuj yep, I know ammonia plus silver will form the [Ag(NH3)2]+ cation
so that increases the stability
i am in doubt about that cyanide thingy, lemme check once
[Ag(CN)]^2- would be formed too right ?
@Tanuj [Ag(CN)2]- though; but is it soluble?
idk
How do you remember these products and solubilities ?
15:23
@Tanuj by practice; silver ammonia complex is a very common product anyway;
not sure about that cyanide though
ans is either (1) or (4)
most probably (1)
am I correct?
Your logic would be this right --> since Ag forms Complex with NH3 its solubility increases
its 3rd
@Tanuj actually diamminesilver complex is very well known to be soluble
@Tanuj duh :( apparently, silver's cyanide complex has higher solubility; but I don't know much about it :/
okay
@GaurangTandon When is next and which one?
@GaurangTandon Even if it is , why is iv>iii ?
15:26
@Abcd tomo maths!
@Tanuj both should be equal, right? (since CN- conc is 2M in both)
yea
Oh, such a small gap! Anyway, Good luck!
@GaurangTandon Good luck Tandon !
@Abcd haha, i've been studying englisss literature for past two days; boards maths doesn't matter anyway :P
thanks bros :)
@GaurangTandon I heard 2016/ 17 Maths ISC paper was disastrous
15:28
@Abcd well it never really got tougher for me; i always scored 100 in preboards and practice papers...
@Abcd Don't mention these things now
cool
@Tanuj it's too late anyway :P
lol right
kbye guys gotta finish another english story :D
15:29
Bye!
@GaurangTandon Kill it man !
@Abcd Apart from JR , who else do you ask doubts from ?
@Abcd I saw that you put a bounty on the para halogen question
Imma gonna right an answer now
Not now
By next week
More research
@AvatarShiny what are your views about this
13 mins ago, by Tanuj
30 mins ago, by Tanuj
user image
@Abcd how much of HOMO LUMO do you know
@Tanuj It'll prolly make a complex with NH3 not sure about CN
@AvatarShiny Assuming we know CN- forms a more badass complex , why is iii<iv ?I mean aren't the concentrations of CN- same in both cases ?
15:40
@AvatarShiny Yeah ;). Its a good question!
@AvatarShiny Studied it only from Clayden....
@Abcd That's good that's good I've done it from clayden only
@Abcd yeah man
@Tanuj Error?
Not sure .Can't be
@Tanuj Ask on main far better than asking random highschool kids
PhD people roam around on main
lol okay
 
3 hours later…
18:23
Will my reputation be lost even if I don't get the answers I am looking for?
I have "bountied" two questions.
18:45
@Abcd yes
331
A: How does the bounty system work?

A. Rex Sources: the official FAQ and blog posts. See also the official privileges page for bounties. What is a bounty? A bounty is a special reputation award given to answers. This feature was designed to motivate answerers, and help questions get the answers they deserve. Bounty awards are ...

@Loong Oh
@Loong even if question is not answered?
Yes. You pay for the advertising. That does not guarantee an answer.
that is sad. :/
My aluminium chloride question hasn't been answered since months..
Are there very few Inorganic Chemists on Chemistry.SE?

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