I need some advice from people who might be familiar with graduate school applications in the states, I got back my gre chem test scores and have 830 (86th percentile)..do you think I should retake this fall (after finishing my third year)..

I was told that ZnO won't react with CuCl2, on Socratic

Is that true?

@MelanieShebel I read that as "re-titting". I need to get out more..

@getafix Hullo! It's been a while o/

Maybe @hBy2Py Brian can help you out there?

@CowperKettle XD

@paracetamol indeed it has

How goes?

@getafix Goin' pretty well, actually ^_^

Hey @geta, got wind of this?

thehindu.com/news/national/other-states/…

^ It's amusing :D

@hBy2Py can't we all upvote her question and invite her to chat? It just takes 20 rep to participate in chat

@paracetamol ^

@BerryHolmes Well after what Brian said...it seems like a bad idea ._.

Oh i get it, true indeed

:)

Should this be flagged?

@BerryHolmes Just one more vote and It'll be closed...don't you worry ;)

@paracetamol thank u :)

@getafix pentavalentcarbon is probably a good one to ask, though he's not pingable in chat currently, unfortunately

I'd think it'd be a fine score for many schools, but it might not be high enough for some of the top-tier universities.

@CowperKettle imo it would undergo a double displacement reaction forming CuO and ZnCl2. Now let's apply the good ole "strong acid --> weak acid". CuCl2 must've been formed from HCl and Cu(OH)2 and ZnCl2 must've been formed from HCl and Zn(OH)2. HCl is no more our suspect (it's common in both). Pulling up data of Ksp (solubility product) i can say that Zn(OH)2 is a better base than Cu(OH)2, which implies that ZnCl2 is a weaker acid. If my deductions are correct, the reaction should be feasible.

@PrittBalagopal what's chemdoodle?

@BerryHolmes thank you!

@BerryHolmes this is chemdoodle : web.chemdoodle.com/demos/sketcher

Works on PC, good drawing tool

Morning peoples

@PrittBalagopal Thanks, a browser based sketcher is amazing.

@M.A.R. morning!

\o

@Loong Can you answer a short questio

-n ?

Qn no 5

@satyatech (2E)-3,7-dimethylocta-2,6-dienal

But you could just call it geranial or citral A. ;-)

That is where I am confused,how did you name it?Should not it be 2,6-Dimethyl octa-2,6-dienal

@Loong

@satyatech Where do you start numbering?

Loong from where should we start numbering according to iupac, left or right

Somebody said me that aldehyde has more priority over alkene in a molecule ,so accordingly I now think that a) should be correct ,am I right? @Loong

You number the chain so that the principal characteristic group gets the lowest number. The principal characteristic group is the group that is cited as a suffix (here "-al").

Thanks;

@Loong o/

@Mithoron hi

:D