An unknown amine is treated with an excess of methyl iodide. Two equivalents of methyl iodide react with the amine. The anime is treated with silver oxide and water, and then heated to $120^\circ \mathrm{C}$. The resulting products are trimethylamine and ethylene. The unknown amine is
...
On another randomly unrelated note: It’s always nice if you guess correctly that an answer by Martin will come in. And it’s good to have a well-calculated MO scheme of CH2N2 at hand, now =D
Oh yeah, Loong. In a Fischer projection, is it the carbon with the highest oxidation state placed closest to the top, is it the carbon with the lowest IUPAC-nomenclature number or do the two definitions coincide (or should I make that a question on the main site)?
> The atom numbered 1 according to normal nomenclature rules is conventionally placed at the top of the main chain, which is drawn vertically and other groups are drawn on either side of that main chain.
Hey, I'm in Analytical Chemistry and I'm working on potentiometry and I'm having a really hard time. Any really good resources anyone can suggest? I'm not a fan of the text (Skoog.)
According to molecular orbital theory, two atomic orbitals form two molecular orbitals analogous to waves combining constructively or destructively but how can a wave combine destructively and constructively at the same time to produce two molecular orbitals? why don't two atomic orbitals combine...
@hBy2Py Yeah, I've seen the answer, that must've took quite a bit of time to type out. Thanks! ^_^
upvotes
As for the "switch of the checkmark" ... I'm still mulling over it, actually 3;)
Oh, and @hBy2Py Brian, just curious (since you mentioned you've graduated from the MIT)... How much undergrad physics do you still remember? (More specifically, Lagrangian mechanics)
ethyl bromide to propanoic acid: 1. $\ce{CH3CH2Br + CN- ->[\text{cold, aq}] CH3CH2CN + Br-}$ 2. $\ce{CH3CH2CN + 2H2O + HCl ->[\text{heat under reflux}] CH3CH2COOH + NH4Cl$ The isolation is left to the reader as an exercise.
ethyl bromide to propanoic acid: 1. $\ce{CH3CH2Br + CN- ->[\text{cold, aq}] CH3CH2CN + Br-}$ 2. $\ce{CH3CH2CN + 2H2O + HCl ->[\text{heat under reflux}] CH3CH2COOH + NH4Cl$ The isolation is left to the reader as an exercise.
@DHMO ''what subjunctive is'' -- If we're trying to show off grammatical skills, we should know that subordinate clauses do not have subj-aux inversion ;)
ethyl bromide to propanoic acid: 1. $\ce{CH3CH2Br + CN- ->[\text{cold, aq}] CH3CH2CN + Br-}$ 2. $\ce{CH3CH2CN + 2H2O + HCl ->[\text{heat under reflux}] CH3CH2COOH + NH4Cl$ The isolation is left to the reader as an exercise.
@DHMO You can synthesize alcohols, (from aldehydes and ketones)...you can use it to synthesize dialkyl cadmium which can be used to prep ketones from acyl halides...among other things...
classification has 14 questions right now, most of which would either fit neatly under terminology or could just have classification stripped off.
Of the 14, two actually do deal with classification systems of one kind or another:
What do these mineral classification symbols mean?
Is there an ...
When I'm reading a post with quoted material, the quote doesn't seem to stand out to me, maybe it's something about it being yellow, but I cannot see it.
Quoth the raven
Nevermore
The blue here on meta stands out, but on Chem.SE it's a pale yellow which doesn't seem to stand out to me.
...
Here is my proposed synthetic pathway to make propanoic acid from bromoethane:
$\ce{CH3-CH2Br ->[\ce{KCN(aq)}][\text{heat}] CH3-CH2-C#N}$
$\ce{CH3-CH2-C#N ->[\ce{KOH(aq)}][\text{heat under reflux}] CH3-CH2-COOH + NH3\uparrow}$
I have some questions about my proposed pathway:
Is it...
As in, did you find any information about percentage yields for these two specific reactions?
The thing is, we can't pull out numbers from thin air about yields. We might have a general idea of roughly how good one step is, and what problems might potentially occur in the synthesis (Klaus already mentioned that bromoethane is difficult to handle), but until you actually do it in the lab, you don't really know.
If you're looking for experimental yields then that's all good, however I just wanted to make sure to clear that up. You can't pull predicted percentage yields out of thin air
I've seen really on paper simple steps go with 40% yield.
Alkyl halides react with $\ce{KCN}$ to form alkyl cyanides as the main product, whereas the use of $\ce{AgCN}$ leads to isocyanides as the chief product. Why does this happen?
In this Meta question I went ahead and applied the new Meta site-cleanup. Is this a good Meta tag to have?
It seems like it would be a useful category to be able to search over. In particular, I'm aware of TRE 1 and TRE 2 (et seq.) that it would fit onto; perhaps there are others?
Or, will it b...
https://youtu.be/thSeYzcPrqs
^^
This is the video. On the video it shows a water bottle getting crushed by the surrounding air.
My understanding:
When the person put cold water over the bottle which has Hot water inside it, the hot water produces water vapor which increases the pressure inside i...
I like whiteboard, but they dry out quickly and some of them don't erase well. Chalkboards can be annoying too, though. I hear there are better and worse ones.
@gannex The worst thing about a whiteboard is a light blue board and a dirty eraser, yeah. And the worst thing about a blackboard is the noise the chalk might make.
(This is also applies to ideal gas law related topics, like Boyle's law, Charles's law, Gay-Lussac's law, etc.)
On a recent question about how a bottle of air behaves when the temperature changes, a commenter said:
This isn't a chemistry question ... This is just physics.
While the comment...
By bubbling Cl2 in a solution containing 176.6 g of MgBr2...
Hi guys, I need help with this question please.
my thought was like this..
176.6g/184.13=0.9591 moles of MgBr2
and also of Br2 cuz its the same ratio so
0.9591X159.82=153.28 gr of br2
now the yield: 135/153.28=0.88 percent.
in my lo...
This was a question that was asked to me in my recent test.
I said that entropy will decrease as a hard boiled egg has molecules in more organised way than a un-boiled egg, but I was marked wrong with a remark that entropy will increase because the protein and other molecules are decomposed due...
I've been going through with a grammar checker on posts, especially newer ones, to clean up grammar sitewide... one post at a time, though.
I did this a few weeks ago with articles I'd written and Google traffic shot up as a result. Even with articles that never really saw traffic in the first place.
I was surprised (and appalled) at the amount of grammatical errors I had in my stuff. :S
I had the following question on a bio test covering cell respiration and glycolysis, but I'm not sure if I agree with the answer.
When a molecule loses hydrogen atoms (as opposed to hydrogen ions), it becomes
B) oxidised
According to my textbook (Principles of Life, 2nd Edition), oxidati...
Non metallic character increases along a period and decreases down a group. Therefore the most non metallic elements should be the right-most. But the right-most elements are noble gases. Do they count?
We should introduce the new typographic convention of writing M as the unit symbol for a metre so it can no longer be confused with milli. The reasoning is more sound than that applied to litre.
> The latter form may also be written without a space, i.e. “$\mathrm{Nm}$”, provided that special care is taken when the symbol for one of the units is the same as the symbol for a prefix. This is the case for $\mathrm m$ (metre and milli), and for $\mathrm T$, (tesla and tera).
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