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Jan
Jan
00:04
@ToddMinehardt For a second I was thinking Mart the mod’s guys xD
@ringo - Nah, Steve Martin, orgo :)
Jan
Jan
If that was re me; I’m not Ringo ;)
oops @Jan sorry :)
Jan
Jan
I fear that soap may be made of seals D=
00:17
Zhe
Zhe
00:37
@ringo That's pretty cool
It's just like using phenol
And that would'be been antiseptic
00:57
@ringo @Jan apparently, I am safe; these soaps don't contain me.
Jan
Jan
We were lucky =D
Jan
Jan
01:28
@ortho, you seem to still be around. Can you tell me if my answer to the ionisation energy question is physically sound or mislead?
0
A: Do cations have high or low ionization energies?

JanConsider a simple thought experiment. Your ionisation process is essentially removing a (negatively charged) electron from a remainderatom. $$\ce{Atom^n+ -> Remainderatom^{(n+1)+} + e-}$$ Throughout this process, you are separating charges, thus there is an electrostatic force driving the elect...

It's simplistic, but works (which is what you said anyway), and I read that argument elsewhere before too.
I really dislike the phrasing "nucleus pulls on the electrons more", that's all.
Maybe I shouldn't have bothered.
It's not wrong, but has massive potential to be interpreted wrongly. For example I've seen people write that "the nuclear attraction is distributed over fewer electrons => each individual electron feels a stronger nuclear attraction".
Jan
Jan
@orthocresol I was thinking that that’s the difference between my way of writing and Lone wolf’s.
Well, he edited it. It seems fine to me now.
Funny thing is I didn't even downvote the answer. Oh well.
Jan
Jan
:D
Yeah, but you can never tell downvoters …
Yeah you can't.
I guess you circumvented it entirely by treating the atom as a point particle ;)
Jan
Jan
01:38
Reads a little like ‘but I can with my supermodpowers *muahahahahaaa~*’ xD
You can't, but I can.
MUAHAHAHAHA
(Actually, I can't. Lol)
Jan
Jan
It’s a good thing I didn’t run in the election; I would totally abuse my mod powers due to curiosity every second day.
Oh wait you can’t? Damnit, revert that statement =C
(Another reason never to run for mod, then xD)
I've probably done so already.
For example, I've found your home address already. Be prepared
Jan
Jan
At least you’re honest and self-critical xD
That would be strange; I didn’t know mods had access to SE emails xD
We have access to everything including your date of birth and passport number.
Jan
Jan
01:41
Cool. Now I wanna be mod again =3
You can run when I resign ^^
If my workload increases too much I will quit... but that's not happening for a while at least.
My real life workload that is.
Jan
Jan
But on a more serious note: You can see the email I’m signed up with so you could send me emails in private if you wanted?
Yes. We have access to emails but there are nearly no cases in which we need to actually email people: meta.stackexchange.com/q/17173/312770
@Jan Yes, however, access to personally identifiable information is logged.
So, actually using it to send private emails would constitute abuse.
Jan
Jan
01:47
Ah, SE preventing abuse with a logging system. I approve ^^
But it leads to deforestation. :(
Jan
Jan
Sustainable logging is fine, imho …
Oh well, I'm off to sleep.
Nights to both of you :)
@orthocresol Good night!
Jan
Jan
Good night o/
I should go, too. It’s an hour later here than at ortho’s place …
But seeing that @Loong is still around, I don’t feel so bad …
user228700
02:41
Hello everyone :-)
user228700
I've a question about steam distillation.
user228700
> "Steam is blown through the mixture and the water and phenylamine turn to vapour. This vapour can be condensed and collected. As the hot steam passes through the mixture it condenses, releasing heat. The condensed vapour will consist of both water and phenylamine. If these were truly immiscible, they would form two layers which could be separated using a separating funnel."
user228700
I don't understand exactly what is happening, in order...
Jan
Jan
*still waiting for your suggestion of the order*
 
6 hours later…
09:12
@Jan That's exactly what I was thinking when I went to sleep :P
 
2 hours later…
11:32
That's weird we cannot send pictures from mobile phone
 
1 hour later…
12:51
and the whole thing reminds me of most posts of Marko... i.e. why should I include my failed research...
13:07
@Martin o/
Any organic chemists here? [Jan's gone for the night :( ]
It's a little issue with carbohydrates.
13:38
@DHMO hi
Do we every time get CO_2 in a combustion reaction?
@AaronAbraham you could try me, although no guarantees
-2
Q: Delete This Question Already

Widow MavenDelete this question already. I have flagged this for deletion because I can't delete it as it already has answers. Someone delete this please. Why are you mods so persistent on keeping this question up? I agree this question has not been productive and only confusing, so it is not contributing...

does anybody have a quick link to the content ownership policy
@Loong Thanks. That's the one
@orthocresol Gimme a sec
Well, here's the problematic bit:
> Reactions with carbohydrates should be carried out it acidic or neutral medium, because in a basic medium they undergo rearrangement.
To what degree is that^ correct?
I'm not entirely sure, actually.
Is this referring to the open-chain form of carbohydrates?
Those can undergo rearrangement via keto-enol tautomerism.
13:50
@orthocresol The text doesn't specify ._.
@orthocresol ಠ_ಠ
I googled 'carbohydrate rearrangement' and I got : The Ferrier rearrangement and the Lobry de Bruyn–van Ekenstein transformation ._.
well, glucose can isomerise to, for example, fructose
6
Q: Why does fructose reduce Tollen's reagent and Fehling's solution?

Nilay GhoshEven though fructose is a ketohexose (ketone-containing hexose, a six-carbon monosaccharide), it reduces Tollen's reagent and Fehling's solution. Generally, a ketone does not reduces Tollen's reagent and Fehling's solution. So, why is this possible in the case of fructose?

Does that help perhaps? haha
@orthocresol Ah yes; but would you happen to know if that statement is correct?
I'd be inclined to agree with it.
13:55
@orthocresol So what rearrangement d'ya think they're talking about? [ @Loong mentioned the van Ekenstein transformation, but all the same...]
Precisely the one that Loong described, just a series of keto-enol tautomerisms.
@orthocresol danke ;)
@getafix o/
@AaronAbraham hullo
@getafix You seem...kinda down ._. What's up?
what makes you say that? lol
It's the usual problem sets and mid terms
14:00
@orthocresol hm, what is that wikiwand link doing in that answer?
@getafix Lack of punctuation X'D
@getafix OH WAIT! I forgot to ask! Did you make it to Hoffmann's lecture? :O
Oh yeah I did.
It was great
There was no place to sit, so my friend ( a postdoc) and i literally sat on the floor in the back..
@getafix Got someone to tape the other class? 3;)
It was like listening to jesus on the mountain or something..
14:01
nah, don't really give a fuck about civil engineering
@Loong I didn't notice actually lol
@getafix "Transformational" ;)
I did send in my report, and had someone else sign the attendance shit
@getafix And that wouldn't be an issue? O.o
Well I still haven't gotten around to reading the papers he referenced..sigh
well, i tried to be nice and sent the prof an email a week in advance but he never replied..so he can go suck a bag of dicks for all I care..
14:03
@getafix Whoa, first off...what was the lecture even about?
also about your carbohydrate question..
@getafix Ouch
epimerisation is quite likely in a basic media..
@getafix Do I get to ask why?
hoffman spoke about carbon clathrates and 1 dimensional benzene polymers (nanothreads)..
the title of the talk was new games to play with carbon.
14:05
@getafix 1 dimensional benzene ? O.o
i dimensional benzene polymer..
basically CH
oh and graphanes..
GraphEnes?
no
I am not stupid
phane
lol
@getafix No No...I implied a typo ;P
basically half of it was dedicated to (CH)n
and half of it to clathrates.
14:07
> Graphane is a two -dimensional polymer of carbon and hydrogen with
Wikipedia
!!wiki/Graphane
Graphane is a two-dimensional polymer of carbon and hydrogen with the formula unit (CH)n where n is large. Graphane should not be confused with graphene, a two-dimensional form of carbon alone. Graphane is a form of hydrogenated graphene. Graphane's carbon bonds are in sp3 configuration, as opposed to graphene's sp2 bond configuration, thus graphane is a two-dimensional analog of cubic diamond. == Structure == The structure was found, using a cluster expansion method, as the most stable of all the possible hydrogenations ratios of graphene in 2003. In 2007, researchers found that the compound is...
yup that
At @getafix I really don't get the one dimensional thingy ._.
stack benzene rings on top of each other
remove double bonds and connect..
@getafix Oh? But wouldn't the polymer have a width?
So 2D?
14:09
yeah of course..
1 D not in the mathematical sense..
@getafix In that case, Alright! ^_^
plus anyway, there was interesting discussion about topology too..it was a great lecture all in all.
@getafix I haven't studied topology (yet)... so I can't judge that ;p
me neither
I am not a mathematician
I have seen some topology in my analysis classes..
Just curious, weren't you caught up in the whole 'entrance exam' thing? After all, you did do your HS back here ._.
14:12
yeah I took the medical entrances for the lols.
The "lols" huh?
I actually had an offer + scholarship from my current uni before I took my boards.
@getafix Oooh! How'd that materialize?
I applied early.
and then I got lazy and did not apply anywhere else..
@getafix ಠ_ಠ
14:13
sigh bad move on my part
@getafix Where else would you've applied?
I wasn't so serious back then
IISER?
@getafix I hear that a lot XD
no, i did not want to stay in India
Japan seemed like a fun place to go to..
@getafix You know Japanese?
14:15
other than that, I had explored unis in the states.
@getafix I'm currently under the impression that's true ;)
Japan was kinda wild card.
but it has been a valuable learning experience lol, although I am kinda fed up of my uni in particular.
I don't speak a lot
I can understand some
can't really read..
@getafix It'll nuked by N.Korea someday in the not-to-distant future...of course it's a wild card :D
I obviously spend more time doing science than learning japanese.
@getafix Obvi
14:17
yeah but once I have some time, i want to learn it well..
we had classes everyday in first year, but they weren't very helpful
doing exercises, exams everyday is not how you learn a language in my opinion..
@getafix I wanna learn German :3 =*_*=
@getafix Isn't that what CBSE does? X'D
the little that I have learned is by talking to people..or mostly just listening to people talk
@orthocresol "improved formatting"
@getafix Are you a manga guy or an anime guy? O.o
@Loong LOL
14:18
Neither.
@orthocresol ಠ_ಠ
I don't really read manga.
I watch some anime, but I am not crazy about it
@getafix Ah well, I don't blame ye :P
I like studio ghibli,
Btw, what entrance exams did you sit?
14:20
great art+music
AIPMT?
@getafix Don't know it ._.
yeah I think it was
I don't know the indian govt is stupid. they went from AIPMT to NEET to AIPMT?
I'm kinda new to the whole anime-manga thing myself
More of a manga guy though ;)
i took it the year they went back to AIPMT
i did not really study for it
@getafix They went back to NEET again XD XD XD
14:21
my national rank was like 14,000
oh wow!
I don't get them lol
@getafix They're the government... of course they don't function in a way that's to be understood XD
yeah
I think the exams are pretty easy
if you study for them..
Scientists have discovered the heaviest element known to science which can only be found in India.

The new element is Governmentonium (Gov). It has one neutron, one pseudo-neutron , 31 assistant neutrons, 30 deputy assistant neutrons, 252 higher neutrons and 545 lower neutrons giving it an atomic mass of 851u.

These 851 particles are held together by forces called morons, which are
surrounded by vast quantities of particles called peons.

Since Governmentonium has no electrons or protons, it is inert. However, it
This one's old, but still amusing :)
14:25
lol
> since it has half as many
peons but twice as many morons
That was priceless XD
I giggle every time I see it :D
yeah. anyhoo, I think I should sleep..I have a lot of work to do tomorrow. ciao
@getafix Adieu o/
@ortho I think I've become @Loong 's sock now ._.
@AaronAbraham That's a disaster. We'll just have to suspend Loong.
:-(
14:30
As for socks, they just get outright deleted
So, goodbye.
@orthocresol NO WAIT!
I..um....I...uh...like seals? Um heh heh?
I wonder what that button does.
Ortho, No...
I wonder what that does? @orthocresol
@getafix Oh wait, I forgot to tell you: be careful when ye say stuff like that ._. A month back, they slapped someone with "sedition" because he typed something along similar lines :P
@ortho A question?
'bout Fehling's test ._.
14:44
Hmm?
According to my book, the Fehling's test is used to identify aldehydes and reducing sugars. However ketones do not give a positive result for it.
Right?
._.
@Loong Kannst du auch helfen?
Fehling does only work with aldehydes. reducing sugars can be aldehydes or ketones, but those ketones have first to be tautomerized to aldehydes
Does the tautomerisation bit apply to cyclic sugars too? O.o
Well, no. The cyclic form doesn't react. Only the open chain form can react with fehling, since only in this case you actually got an aldehyde, and for ketoses only the open form can tautomerize since you only got the ketone in the open form.
@DSVA Ah well, that make sense :D
15:00
But, in any solution of glucose, for example, there will always be some amount of open chain form present.
Once that amount of it reacts, then more of the cyclic form will open up to give the open-chain form (Le Chatelier's principle).
And so on, and so on. Eventually all of it will react.
If you dump in enough of the other reactant, that is.
For a qualitative analysis, you probably don't need to react all of it ;)
The cyclic form doesn't have a carbonyl group; it's "protected" as a hemiacetal. So, there's no keto-enol tautomerism to speak of in the cyclic form.
user228700
15:58
Ello everyone!
user228700
Is anybody familiar w/ gamma radiation? I've a quick question about it.
user228700
Ah, never mind.
16:22
it's dangerous and you should stay away from it
16:33
oh no, gamma spectroscopy is always fun
Gamma-ray spectroscopy is the quantitative study of the energy spectra of gamma-ray sources, in such as the nuclear industry, geochemical investigation, and astrophysics. Most radioactive sources produce gamma rays, which are of various energies and intensities. When these emissions are detected and analyzed with a spectroscopy system, a gamma-ray energy spectrum can be produced. A detailed analysis of this spectrum is typically used to determine the identity and quantity of gamma emitters present in a gamma source, and is a vital tool in radiometric assay. The gamma spectrum is characteristic...
Although there is not much practical chemistry involved. If you want to do real radiochemistry, you have to do alpha or beta spectroscopy.
I can't say I've ever heard of any of these but it makes perfect sense for radiochemistry
So there isn't gamma absorption spectroscopy, right?
@pentavalentcarbon That would be something like Mössbauer spectroscopy.
17:38
@ortho Another question?
Does something have to be an Acyloin type of ketone, if it's gotta be converted to the aldose form in the presence of a base?
> Thus, although the ketose fructose is not strictly a reducing sugar, it is an alpha-hydroxy-ketone, and gives a positive test because it is converted to the aldoses glucose and mannose by the base in the reagent.
!!wiki/Benedict's reagent
Benedict's reagent (often sold as Benedict's Qualitative Solution or Benedict's Solution) is a chemical reagent named after an American chemist, Stanley Rossiter Benedict. Benedict's reagent is a chemical reagent commonly used to detect the presence of reducing sugars, however other reducing substances also give a positive reaction. This includes all monosaccharides and many disaccharides, including lactose and maltose. Such tests that use this reagent are called the Benedict's tests. Generally, Benedict's test detects the presence of aldehydes, alpha-hydroxy-ketones, also by hemiacetal, including...
Yes.
Do you know the mechanism?
 
2 hours later…
19:48
2
Q: Elimination in dibromocinnamic acid

RobChem The above is a picture of dibromocinnamic acid. In the lab today I carried out an elimination reaction on this molecule using potassium carbonate giving the carbonate anion as a base. I thought about the mechanism and I initially thought that the base would attack the hydrogen on the leftmost c...

Hm, the picture doesn’t show dibromocinnamic acid. What is correct here, the name or the picture?
I'm guessing the picture.
Yeah, the picture goes better with the description of the proposed mechanism.
!!img/2,3-dibromo-3-phenylpropanoic acid
20:05
should I be proud of this?
._.
Mod abuse!
I am not going down without a fight
 
3 hours later…
22:52
0
Q: Group theory tables

orthocresolJust a pet project of mine that will likely serve minimal use. And something for me to do when I'm bored because I like looking at LaTeX. The tables are taken from the OUP website; there are some typos which were distributed internally in my university. I have corrected the tables as necessary. ...


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