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2:13 AM
@DHMO There is no electronic SE for the dihydrogen dication -- it has no electrons. Did you mean something else?
 
user228700
2:39 AM
Hi everyone :-) Does anybody know about the "levelling" and "differentiating" effect of solvents..?
 
user228700
3:20 AM
@JohnRennie: Are u familiar with this concept?
 
4:58 AM
@KaumudiHarikumar I hadn't come across the idea before, but it seems straightforward enough. What in particular did you want to know?
 
user228700
@JohnRennie As usual, I came across several different definitions and they are confusing me.
 
user228700
The first, oversimplified version given by my textbook goes like:
 
I think the point is that if all acids are 100% ionised then they produce the same $[H+]$.
 
user228700
 
That seems pretty clear ...
 
user228700
5:07 AM
@JohnRennie Yes, but I wanted to have an idea about why this effect is observed and when I googled it, I found some other definitions that confused me a bit...
 
OK, what other definitions are causing you grief?
 
user228700
 
user228700
"No acid stronger than $H_3O^+$ can exist in water"
 
user228700
How come?
 
user228700
It is my understanding that acid-base reactions tend to proceed in that direction of the stronger acid(/base) to the weaker acid(/base)
 
user116211
5:13 AM
@KaumudiHarikumar stronger acid turns to weaker base...
 
user228700
@MAFIA36790 I'm sorry, I've edited that. I didn't mean acid converts to acid. I meant that it goes to the side which has the weaker acid among the two.
 
user228700
So, in case a stronger acid than $H_3O^+$ is mixed with water, then the reaction will proceed in the direction leading to the formation of the weaker acid, $H_3O^+$, correct? I dunno, I'm not entirely confident about that statement. Is this correct?
 
user116211
Hey Hey @shadow ;)
 
user116211
@KaumudiHarikumar Letting off, for a moment, the truthfulness/falsity of the statement, tell me what makes you dubious of the fact.
 
user228700
@MAFIA36790 Which fact?
 
user116211
5:21 AM
@KaumudiHarikumar You mentioned above.
 
user228700
@MAFIA36790 Well, I kind of feel like I haven't fully understood how these reactions work so I dunno if saying "leading to the formation of the weaker acid $H_3O^+$" and all makes any sense...
 
> No acid stronger than $\ce{H3O^+}$ can exist in water
That's another way of saying the acid is completely dissociated in water, though it's a rather less obvious way of saying it.
 
user228700
@JohnRennie How are those two statements equivalent..?
 
user116211
@KaumudiHarikumar Tell me first why acid-base reactions favour weaker acid-base products.
 
Suppose you have an acid HA. If it is a stronger acid than water it completely dissociates to give H+ and A-. OK so far?
 
user228700
5:28 AM
@MAFIA36790 Oh, I just read that in my textbook. I don't really understand why...
 
user228700
@JohnRennie Yep.
 
user116211
@KaumudiHarikumar Hint: Acid-base reactions are under equilibrium-control.
 
user116211
Now, think of the position of the equilibrium...
 
And when we write H+ we really mean $\ce{H3O^+}$ since we don't have individual proton floating around.
 
user116211
Think of the concerned thermodynamic potential...
 
user228700
5:30 AM
@JohnRennie Yes...
 
So when we put our strong acid in water we get a mixture of water, $\ce{A-}$ and $\ce{H3O^+}$. Yes?
 
user228700
@JohnRennie Yeah...
 
So what is the strongest acid present?
 
user228700
Uh, $H_3O^+$?
 
Correct! So regardless of what A is the strongest acid is going to be hydronium. That's why the statement is equivalent to saying the acid completely dissociates.
 
user228700
5:39 AM
@JohnRennie Ah...
 
user228700
Okay, I see.
 
user228700
Lastly, can you help me to understand this:
 
user228700
"Because of the leveling effect, you don't really have hydrochloric acid or sodium hydroxide floating around in water, as would be predicted by Arrhenius Theory. Instead, you have lots and lots of the threshold acid or base and extra ions capable of forming hydrochloric acid or sodium hydroxide once the water (or any solvent) is removed, as predicted by Brønsted-Lowry Theory."
 
user228700
?
 
user228700
Oh, BTW sir! My friend who is doing his undergraduate degree in IIT right now has just bought "Atkins" and he's offered to lend it to me for a whole week so do u think that will help me/will be enough time to understand the concepts of chemical+ionic equilibrium, as well as Thermodynamics? (Given that I've already done thermo. in physics...)
 
user228700
5:46 AM
With regard to the paragraph that I've quoted, what do they mean by "...according to the Arrhenius theory"?
 
user116211
@KaumudiHarikumar There is free pdf available online; try not to get the edition of Atkins-Paula; they dropped out many important discussions.
 
user228700
With regard to the paragraph that I've quoted above, what do they mean by "...according to the Arrhenius theory"?
 
user116211
@KaumudiHarikumar A very good book; it really would give you a very good insight on the concerned topics.
 
user228700
@MAFIA36790 Online?! Okay, I will check it out. Which edition are u talking about? (That has cut out some parts, I mean)
 
user116211
@KaumudiHarikumar Prior to the 2005/2006 edition, if I remember that was the year when Paula became the co-author.
 
user228700
5:49 AM
@MAFIA36790 So the editions published before 2005/2006 are good, you mean?
 
user116211
@KaumudiHarikumar Both are good; but the earlier versions had more relevant discussions in them.
 
user228700
@MAFIA36790 Oh, OK. Do u think I'll be able to finish all those chapters in a week?
 
user116211
@KaumudiHarikumar That depends; it took me a month or more to complete the concerned chapters as then it was my first serious study of physical chemistry; also I had other books to follow....
 
user228700
I mean, I realize that that's very subjective, but still, now that you know about my pace a little bit...
 
user228700
@MAFIA36790 Well, I can tell you that this is probably the 5th/6th time I'm learning these chapters as I have been constantly revising these chapters over the past two years but still, I don't have the adequate in-depth knowledge required for JEE. I've already spent a lot of time and I hope I'll be able to finish within the next week :/
 
user228700
5:55 AM
Anyway, @JohnRennie: What about that paragraph..?
 
user116211
@KaumudiHarikumar The chapters are small; you can skip some part and a chapter not relevant to JEE (can't remember the name; but contained phase rules and Clapeyron equation derivation etcetera). There must be six chapters that cover the concerned topics. Since, you more or less know what you are reading; you should take not more than two weeks or so. But read slowly without considering the time - this is my advice for sure.
 
Busy at work, back soon ...
 
user228700
@MAFIA36790 Actually, Clapeyron equation is given in my coaching textbook so it must be relevant. I'll skip those topics that haven't been given in my textbook; my intention is to get a broader picture. I certainly cannot spend two more weeks. I'll try my very best. Thank you :-)
 
user228700
@JohnRennie OK sir.
 
I'm back!
I assume the threshold acid or base means the acid/base formed from water i.e. hydronium or hydroxide. If so the paragraphs just says (again!) that the acid or base is completely dissociated.
 
user116211
6:08 AM
@KaumudiHarikumar Seen that many coaching materials do try to cover many more things that aren't even important; however the chapters are quite intuitive and lucid; so don't think you should face any problem.
 
user228700
@MAFIA36790 Well, yeah, but I'm trying to know as much as possible...
 
user228700
@JohnRennie Yeah, I too don't understand what they mean by "threshold acids/bases" :/
 
user228700
One second. Brb.
 
user228700
6:25 AM
I'm back. Sorry about that; something important came up...
 
user228700
Let me look up "threshold acid/base"...
 
user228700
Oh, it's all about something called the "lactic acid threshold" :/
 
user228700
OK, never mind that. @JohnRennie: What do they mean by "...according to Arrhenius concept"?
 
@KaumudiHarikumar no idea. The only thing associated with Arrhenius I know of is the Arrhenius equation and this doesn't seem relevant.
 
user228700
@JohnRennie Well, there is the Arrhenius concept of acids and bases. U are not familiar with that..?
 
6:32 AM
@KaumudiHarikumar Oh, OK, I guess I just consider that part of the furniture rather than a theory.
I still don't understand what the paragraph means.
This could mean it's too deep and meaningful for me to understand, or it could mean that it's badly written :-)
 
user228700
@JohnRennie OK :P But how does the Arrhenius concept predict that the acid(/base) introduced to water floats around as such..?
 
user228700
The Arrhenius concept simply states that an acid dissociates to give $H^+$ and than a base gives $OH^-$, correct?
 
user228700
What's that to do with this "independent floating around"..?
 
I've no idea. I can't see why the (almost) complete dissociation of a strong acid in water is in contradiction to Arrhenius' theory.
Back to work for the next few minutes ...
 
user228700
Hm, OK...
 
user228700
6:37 AM
OK sir, never mind that paragraph then. BTW, MIT also teaches Le Chatelier's principle like the way my textbook does: "The system moves in that direction in which the applied stress is relieved".
 
user228700
Anyway, back to physics then :-) Thanks for ur help. And @MAFIA36790: Thanks to you too. BTW, do u listen to Hindi music?
 
user116211
@KaumudiHarikumar Sometimes...
 
6:59 AM
@MAFIA36790 hey ho!
 
user228700
@MAFIA36790 OK. Have u listened to "Channa mereya" from "Ae dil hai mushkil" yet? I think it's absolutely brilliant.
 
user116211
@KaumudiHarikumar Listened the title song; liked it.
 
user228700
@MAFIA36790 Which one's the second one?
 
@Rubisco too late!
 
user228700
@MAFIA36790 Oh, OK. I feel that "Channa mereya" is better. Arjit Singh's voice :o <3 Anyway, I've got another question. I'll be back after lunch.
 
7:16 AM
@ringo probably not very long, actually
But nobody would do it, for the simple reason that IPA is so easily accessible! :D
Reflux for about 1 hour should be enough, from a quick Reaxys search.
 
I didn't have my lab's Reaxys password so I figured I'd ask chem.se
Thanks, though
Just saw your post about HBr addition to 1,3-butadiene
Really funny, we just talked about that today in my phys org class
@orthocresol but I suspect you've been working on it for longer than a day...
care to divulge just how long? lol
It's a hefty piece post
 
7:35 AM
@ringo maybe a couple of hours yesterday
 
Really??
 
I didn't do the research yesterday - actually it was in one of my lab reports
 
Now you're just making me feel bad
Oh thank goodness lol
 
And i thought i'd just share because most people have the simple explanation.
 
user228700
Hi :-)
 
7:37 AM
It's going to be a useful post no doubt. Good work
 
user228700
I've got a small question related to partial pressure.
 
Thanks, it's hols now and I'm doing zero work so this is my way of making myself feel slightly less guilty haha
 
Do tell
 
user228700
We have a gaseous system at equilibrium. If we introduce an inert gas to this system without changing the pressure and the temperature of it, then his does this change affect the system?
 
It depends
As is usually the answer
 
7:39 AM
@ringo very good answer
 
user228700
OK, hang on.
 
user228700
Clearly, if both the temperature and the pressure remains constant, then the volume increases.
 
Most containers don't expand when you add more gas into them
 
user228700
But so does the partial pressure, correct? If the total pressure is kept constant, then clearly, the partial pressure will change on increasing the number of moles. In fact, it will decrease.
 
@KaumudiHarikumar Precisely, it will.
 
user228700
7:42 AM
@ringo No, but the pressure does increase, correct? In this case, it is given that the pressure as well as the temperature is kept constant so clearly, the volume has to increase.
 
You just have to assume that you have an expandable container. With frictionless walls, etc. etc. other ideality assumptions. But in chemistry, we're always ideal, so it's fine.
 
Well yes, in that case you'd be right
 
user228700
@orthocresol OK, so given this, since the reaction quotient($Q$) is determined using the partial pressure of the gases, plugging in the new, decreased numbers, we will arrive at $Q<K_{eq}$, no?
 
@KaumudiHarikumar Why should that be so?
That depends on the form of the reaction quotient.
So, as ringo said, it depends :)
 
^^
 
user228700
7:45 AM
@orthocresol OK. It depends. So does that mean that we cannot make any generalization for this case?
 
I wouldn't say that either
 
Consider a gaseous reaction like: $$\ce{H2O(g) + CO(g) <=> CO2(g) + H2(g)}$$.
Let's say that, at equilibrium, K = 1.
 
user228700
@orthocresol No, no, please spare yourself the effort of explaining to me why it depends. I understand it, thanks :-)
 
And initially, total pressure is 400 atm. And all gases are present in equal amount. So the partial pressure of each gas is 100 atm.
So if you add an inert gas, all partial pressures are decreased to say, 80 atm. But Q would still be equal to 1.
 
user228700
But this example shows that we can't make any general statement regarding this situation, correct?
 
7:47 AM
Ah, ok.
Well, I wouldn't say that either ;)
 
user228700
@orthocresol Why not?! :o
 
It depends on the relative no. of moles on LHS and RHS.
 
boom
 
user228700
@orthocresol Well, yeah. So no general statement regarding the direction in which the reaction will move can be made, correct?
 
I think perhaps we have a different idea of what a general statement is.
 
user228700
7:49 AM
@orthocresol Haha, maybe :P
 
Our "general" statement is: If the LHS has more moles of gaseous reagents, then addition of an inert gas will push the equilibrium position towards formation of products.
 
user228700
OK, but if someone gave u only that much detail and asked u to predict the direction in which the reaction will shift, would u be able to do so? You must say either "forward", or " backward", or "no change". No general statement (:-))
 
Only how much detail?
Without the chemical equation, you mean?
Yeah, you wouldn't be able to say anything.
 
user228700
@orthocresol The amount that I've given while describing the situation I did.
 
Nothing isn't really much to go on
 
7:52 AM
13 mins ago, by Kaumudi Harikumar
We have a gaseous system at equilibrium. If we introduce an inert gas to this system without changing the pressure and the temperature of it, then his does this change affect the system?
This one?
 
user228700
@orthocresol Yes, exactly.
 
Yeah... that's nothing, so you can't say anything.
 
Say ortho, you're a 3rd year right?
 
That's the most nihilistic thing I've ever said in my life.
 
lol
 
7:53 AM
@ringo Yeah, soon to be, at least..
 
Then a 2nd year?
 
user228700
@orthocresol Lol, OK. Watch this at 16:37
 
@KaumudiHarikumar Ok, it is 15:53 now, so I will watch it in 44 minutes' time.
@ringo Term starts on 9th Oct, so I'll be a third year then :)
 
user228700
@orthocresol Haha, no! I meant to ask you to watch from the 16th minute of that video!
 
7:54 AM
Ahhhh
Are you thinking of going to graduate school?
 
@KaumudiHarikumar Let me think about it.
@ringo Probably in UK.
 
user228700
@orthocresol At 17:42, the professor says "The volume increases and so does the partial pressure; all of a sudden, the gas has a lot more room..."
 
And you want to study organic chemistry?
or something else?
 
@ringo Yeah probably organic. I must say I like QM a lot actually, and it will make me sad if I have to give it up entirely, so I don't know - I might want to meddle with some computational chem here and there, but exactly how is a question I will leave for a couple years later :)
 
user228700
I mean, even if the inert gas hadn't been introduced, and the pressure and temperature had been kept constant, the partial pressure wouldn't have changed...right?
 
8:00 AM
I feel the same, only I'm sure my understand of qm is dwarfed by yours
 
@KaumudiHarikumar She said the partial pressure will decrease, which is correct.
 
I've still yet to take most different types of chemistries, so this next year and a half will be eye-opening for me
 
user228700
OK, no, you can't even do that if the number of moles of the gas don't increase because you can't just keep temperature and pressure constant and expect the volume to increase w/o increasing the number of moles in the gas.
 
@ringo well, a lot of people here are comp chem experts, so we can actually see how little we know!
@ringo Yeah, America, right?
 
I am, yes
Australia, right?
 
8:02 AM
You guys are weird, I must say. Here we do every chemistry simultaneously from the get go. Nah, UK.
Just currently living at GMT+8 home for now ;)
@KaumudiHarikumar Yup, precisely.
 
It is weird I'll admit
 
user228700
@orthocresol Oh, crap! She did say that! Damn. Okay. Thanks guys! I really appreciate your help! :-)
 
@KaumudiHarikumar No problem - you have a good understanding of chemistry.
 
It makes everything seem very disconnected
Maybe
Everyday I'm blown away by what you and others put out
I'm a competitive guy so in a way you guys push me to learn more
 
@ringo Hmm, I'm not going to say that it's better or worse. I'd just find it weird myself
Personal preference :)
Obviously it works for lots of people, and I must say, the real cutting-edge research is probably to be found in the US.
 
8:06 AM
Haha, yes when you import the best you get the best
 
A lot of the time, I just post stuff that I happen to be revising. If you ask me now what I revised six months ago, I've probably forgotten all of it :D
 
Yeah, most everything I post is pure research
That's one thing chem.se has made me proficient at
 
It's a good skill.
 
Truly
The esteemed @Wildcat joins us
Welcome
and also goodbye, I've much too much work to do to continue chatting
always a pleasure, though
 
@ringo See you around :)
 
8:10 AM
Goodbye for now
 
user116211
8:50 AM
 
:D
Hullo, humans! =^.^=
 
user116211
Welcome @wildcat.
 
!!flip/@Rubi
 
(β•―°ΰ¨Š°)β•―οΈ΅@ᴚnqᴉ
 
user116211
9:06 AM
@ShadowWizard Rubisco will kill Shadow...
 
9:23 AM
Home page spamming in progress. No apologies offered.
19
A: Why don't gases escape Earth's atmosphere?

LoongThe atmosphere actually loses gases to outer space. The average velocity $\bar v$ of gas molecules is determined by temperature $T$. However, not all the molecules travel with the same velocity. The probability of finding a molecule with a velocity near $v$ is described by the Maxwell distributi...

That's one large equation...
I actually checked to make sure it wasn't an image...
 
@orthocresol That's @Rubisco's fault.
 
I like it!
Although, in my notes I usually used \exp{}
I presume the complaint was that the exponent was too small.
 
@orthocresol Hm, yes, AMS recommends: The "e" notation should be changed to exp notation whenever an expression becomes cumbersome.
But we are not using AMS typography. I have to check some other standards.
 
9:50 AM
@Loong Κ• βŠƒο½₯ β—‘ ο½₯ Κ”βŠƒοΈ΅β”»β”β”»
 
Ugh, okay, I'm tired of retagging questions.
 
Hullo tired of retagging questions. I'm Rubi.
 
Well played, well played..
 
:D
 
@orthocresol No, I said Rubi
 
10:07 AM
Atkins, P.; Paula, J. *Elements of Physical Chemistry* 6$^{th}$ Edition. W.H. Freeman and Company. New York, NY. **2013**
That's one way of doing it, I guess...
 
@orthocresol ugh
 
@Loong Loong why don't you push the button and bomb all the inconsistent ones with a nuclear warhead?
So much unIUPACness isn't good for health.
 
I've taken over the front page, it seems.
 
@orthocresol ruined the front page. Please use chemistry.stackexchange.com/questions?sort=newest instead.
3
 
> phenyl + HCL is this a possible reaction?
 
10:15 AM
 
I see I am not the only person triggered by $<v^2>$
 
user116211
@orthocresol Why do people write this like that O.o
 
This book and its sequel is full of <> instead of \langle \rangle. I'm quite surprised nobody has pointed it out yet.
 
@orthocresol Misery loves company.
@orthocresol 'cause it's the only book of its kind without rangle langles.
 
user116211
@orthocresol I suggested an edit earlier at Maths turning < > to \langle \rangle; they rejected it :(
 
10:22 AM
@MAFIA36790 They can have fun with their less than v squared greater than, in that case.
 
user116211
@orthocresol I guess so ;D
 
@MAFIA36790 Generally, the math community are suckers in typography.
 
user116211
@Rubisco nods
 
No offence or defence or any other fence.
 
@Rubisco yes, they use italic dx and e^x :-(
 
10:29 AM
@MAFIA36790 \langle \rangle sucks badly due to inadequate autosizing.
I hate the way TeX autosize any brackets.
Always hardcode the size I like.
 
user116211
@Wildcat You can use \left\langle \right\rangle, can't you?
 
@MAFIA36790 oh wait!
These two will be sized automatically.
 
@Loong I've seen worse
 
\langle \rangle should be always of the same size.
 
2
A: Formatting Sandboxβ€”please test stuff here $test$

orthocresol\newcommand{\md}[0]{\mathrm{d}} \frac{\md\hbar}{\md\pi} $$\newcommand{\md}[0]{\mathrm{d}} \frac{\md\hbar}{\md\pi} = 0$$ \md U = \md q + \md w $$\md U = \md q + \md w$$ Please don't murder me for not using the inexact differential sign. \langle \psi_1 | \psi_2 \rangle Doesn't look good on my ...

 
10:32 AM
But I have to say, I use XeTeX with unicode-math, which is different from LaTeX.
 
I use XeTeX too. Because of the flexibility in language options.
 
The problem is MathJaX still feels like it is from 90's.
 
I guess any nonnative does that.
@Wildcat Worse. It's from the 10's.
 
21
Q: Difference between \langle and <

ManishearthIs there any difference between \langle S \rangle and \left< S \right>? Or is \langle just an alias for < that by default works on one line without having to use \left?

I use \langle ...\rangle for Dirac brackets.
W/o autisizing.
 
user228700
10:42 AM
@orthocresol: I was trying to figure out why it is true that reactions proceed in a direction that goes from a stronger acid(/base) to a weaker acid(/base) and now, I'm more confused as to how we're able to talk about reactions at equilibrium proceeding in one way or another. Are we not talking about equilibrium? Are we considering the case in which we bring together all the reagants involved in both the products-side and reactants-side of the equation and then looking at what happens?
 
user228700
@MAFIA36790: Thoughts?
 
user116211
@KaumudiHarikumar I've given you the hint; ponder over that.
 
user116211
5 hours ago, by MAFIA36790
@KaumudiHarikumar Hint: Acid-base reactions are under equilibrium-control.
 
user116211
5 hours ago, by MAFIA36790
Now, think of the position of the equilibrium...
 
user116211
5 hours ago, by MAFIA36790
Think of the concerned thermodynamic potential...
 
user228700
10:49 AM
@MAFIA36790 Well, yeah, I was thinking along those lines but I realized that if we're talking about any system at equilibrium, the reaction doesn't tend to go anywhere...
 
user228700
@MAFIA36790 I'm afraid I'm not familiar with the concept of "thermodynamic potential"
 
user116211
@KaumudiHarikumar reaction doesn't tend to go anywhere... - seems to me quite vague and unclear.
 
user116211
Anyway, I'm busy a bit in writing a post.....
 
user228700
@MAFIA36790 Never mind, I figured it out. Thanks anyway!
 
user116211
@KaumudiHarikumar good!
 
11:15 AM
@KaumudiHarikumar $\ce{HCl + H2O -> H3O+ + Cl-}$ is certainly an equilibrium.
The only issue is that the "equilibrium" lies far, far, far, far, far, far, far, FAR, FAR, FAR, FAR, $\Huge \mathbf{FAR}$ to the right.
 
user116211
@orthocresol oho ;P
 
user228700
11:50 AM
@orthocresol Hm, OK :-)
 
1:07 PM
!!tea/coffee
 
@ShadowWizard It's been a bit bugged for a while, I think.
:(
 
Please don't break the coffee.
 
1:21 PM
!!coffee
 
Is the following reaction elementary?
2N2 + O2 -> 2N2O
 
1:40 PM
@DHMO Three molecules react together at the same time in a single step? Probably not.
 
@Loong what do you reckon?
 
2:09 PM
@DHMO That three molecules don't react at the same time in a single step very often.
 
@Rubisco I mean, what do you reckon about the mechanism.
 
@DHMO probably several radical reactions
 
@Loong more specifically?
 
@DHMO Well, why has it sparked your interest?
 
perhaps starting with O2 <=> 2O
 
2:12 PM
@Rubisco Nothing, just curious
@Loong I thought about that but I doubt it
 
What good would knowing the mechanism, and most prolly memorizing it, do . . . Oh, okay
 
then O + N2 <=> NO + N
 
O2 <=> 2O requires so much energy
 
@Loong Alert: Unbalanced equation
 
user116211
noticed something dangerously formatted....
 
2:14 PM
@orthocresol hm, typo :-(
 
@orthocresol You forget the bzzzzz bzzzzz
 
@Rubisco Bzzzz bzzzzz
 
user116211
$\color{red}{\textrm{Alert: Unbalanced equation}}$
 
user116211
;)
 
$\Huge\color{red}{\textrm{Alert: Unbalanced equation}}$
:p
 
user116211
2:17 PM
O.o
 
@orthocresol Imagine you had to alert seals of an incoming shark. Your forgetfulness would've cost a lot of lives. Pay attention
 
@DHMO breaking N2 requires even more
 
@Loong so let's break neither
 
@DHMO You should at least break one of them.
 
N#N + O=O <=> N#N-O-O
N#N-O-O <=> N#N-O + *O
etc
 
2:21 PM
No, not etc. It doesn't look like a chain reaction.
I mean your proposed mechanism isn't
 
what's a chain reaction? (sorry)
 
@DHMO A reaction that repeats itself.
 
ohhh
but O=O <=> 2O requires so much energy
~800 kJ/mol
so i figured maybe i would just break one of them
 
Not that it never happens.
 
sure
 
2:24 PM
@DHMO well, yes, you don't see much nitrogen oxides in natural equilibrium with our N2 + O2 atmosphere
 
@Loong that equilibrium doesn't happen?
2N2 + O2 <=> 2N2O
by "doesn't happen" I mean "favour the left intensely"
 
@DHMO yes, just check the enthalpy balance
 
Nice idea...
O=O ~800
O-N 631
N#N O=O N#N
N#N-O O-N#N
it's still exothermic?
Am I the only one who often reads this as "We are having electrons"?
2 days ago, by Martin - γƒžγƒΌγƒγƒ³
We are having elections! Do you have a question for the candidates? More information on meta.chem.se.
 
@DHMO Yes. Feel alone.
 
 
2 hours later…
5:00 PM
Do we have an uncharged NO3 species?
I felt stupid for a moment
 
@orthocresol Just a typo then
I mean in what I'm studying.
 
Happens in the best of books
 
Pats the stupid PDF in the back
 
Mmmm... typos. :D
 
5:07 PM
BTW, something weird happened today.
I posted something on a main site. OMG
 
BTW, how could we tell that a particular molecule does not exist?
 
Not here, mind you.
@Wildcat By using our mouth.
Or figurative mouth.
I know it's hard for a cat.
 
Say, @ortho is sure neutral NO3 is a typo. But how does he know that?
@Rubisco Cats can talk!
 
@Wildcat No they can't
 
@Wildcat It could probably exist.
 
5:10 PM
@Rubisco you're one small step away from loosing a vote in the upcoming elections. :|
@orthocresol AHA! :D
 
@Wildcat I swear I'm not racist. Or cattist. Or felinist
@orthocresol That's one unhappy oxygen
 
@orthocresol oh boy, it "exists"!
 
@Ortho I just got time to read the original revision of what you wrote. I'll try to address your concerns in the questionnaire.
 
Sep 25 '15 at 17:34, by Loong
actually, I once talked to a cat on the phone
 
5:25 PM
@Loong We're talking about normal people, not Loongs.
It's debatable whether Loongs can talk either.
 
:-(
 
Rubi, excluding Loong from things since 1888
 
5:41 PM
@orthocresol yeah, need to find a different host for the tea
 
Nothing much happening today...
Quick! Somebody submit a question asking "how can I stereoselectively reduce a beta-hydroxyketone"!
Either that, or I continue flooding the home page with kinetic-theory-of-gases...
 
02:00 - 18:0018:00 - 00:00

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