From an online textbook, the first step in the preparation of an amino acid:
Can we be sure that the clorine will connect exactly at that spot, in the alpha-position? Won't we get an acyl chloride instead? Or a molecule where Cl is connected in the beta-position, or further down the line?
@CowperKettle There's always logic if you read some reaction mechanism. If you want to make logic out of things, you should first study acids and bases, and then I'll tell you something.
Then you can study and understand mechanisms easily.
So, what is the difference between nucleophilicity and basicity, or electrophilicity and acidity?
I hope you don't mind my numerous questions @Cowp. It's how my awesome Chem teacher makes me understand things and it's the most effective teaching method: Interactive teaching
Good questions on the site aren't necessarily touching advanced topics unlike language; they're often thought-out questions from people fluent enough in what they studied to ask them.
By what mechanism would you expect to get the acid chloride? The $\sigma _{C-H}$ bond $\alpha$ to the carbonyl is going to be the weakest bond in terms of homolytic cleavage. — SendersReagent12 mins ago
> Irradiation will cleave the Cl−ClCl−Cl bond and yield chlorine radicals (Cl⋅)Cl⋅). These will abstract hydrogen atoms (not protons) from the carboxylic acid to form a carbon centered radical (and HClHCl).
Yes, we can :-D
Note the $h\nu$ in the reaction. It is a radical reaction. Irradiation will cleave the $\ce{Cl-Cl}$ bond and yield chlorine radicals ($\ce{Cl*})$. These will abstract hydrogen atoms (not protons) from the carboxylic acid to form a carbon centered radical (and $\ce{HCl}$). The fa...
I feel that it must be a good answer, but I'm too dense.
Everything again goes back to how oxygen drags the cloud from carbon @Cowp. That's always the case in carbonyl when we don't want to dig further into more advanced MO schemes and calculations.
I am going to say, no, this does not work in practice.
In theory you would say that that the α C-H bond is the weakest because the resulting radical is stabilised by conjugation into the C=O. That's all fine and dandy until you actually run the experiment.
The problem is twofold. Firstly, the c...
Pretty nice answer. BTW @Ortho between Clayden and Carey, which one'd you choose if you could only choose one? Should I go read Carey when I finished Clayden?
@Cowp translating Ortho's answer, he's saying that you might think that conjugation stabilizes and the CH bond your question wanted to break is weakest, but it's not true because 1. chlorine doesn't choose its victim and 2. since it's an electrophilic radical and likes electrons, it wants a hydrogen that has some more cloud to it.
@PhMgBr I'm trying to understand WHY it is an electrophilic radical.
Oh, he just expanded the answer
> On top of that, it is what we would consider as an "electrophilic radical"; it has a very low-energy SOMO, and therefore has a tendency to abstract a more electron-rich hydrogen atom. Essentially, it means that the radical behaves more like an electrophile than a nucleophile. In the transition state for hydrogen abstraction
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@PhMgBr Clayden definitely, IMO Carey/Sundberg is not a good intro. It's good if you have your basics down and want to go further then Carey/Sundberg is great but for starters you'd go for Clayden.
My impression is that Carey/Sundberg is a bit inconsistent in how much prerequisite knowledge it expects, so if you're confident enough then it's great (there's a lot of info in it)
@CowperKettle The radical is neutral, but it leans more towards an electrophile than a nucleophile. These are called "polar effects in radical reactions" - as with everything in chemistry, it is not black and white
Honestly though, at a simple level of theory, you just need to say that yes it is chlorinated at the alpha position.
@CowperKettle Chemistry's pretty diverse. Even more diverse than language. We have to stick to simplifications because the more we try to explain things the more we have to know and apply different concepts, in multitudes.
@PhMgBr I felt like Clayden's introductory chapters were meant to bring any reader up to the level required but I can't remember so I'm not sure. Of course the same textbook will work differently for different people too. In all honesty I haven't read Clayden for quite a while already (the main reason why I open Clayden is actually to cite stuff for answers here because I figure people will likely have access to it). Most of the suggested reading lists here only have specialised books
It's a style I picked up, I think it works quite well. Judging by the popularity of Clayden at least. I can write in the formal textbook style quite well too
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