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4 hours later…
15:56
@Martin-マーチン <3
Hullo @NotN!
Welcome to the Table!
Hey guys I just got my second "Steward"! \o/
16:40
@Ϻ.Λ.Ʀ. Hey! xD
@NotNicolaou How're you doin'?
Jan
Jan
16:51
@Ϻ.Λ.Ʀ. Imposters!
Merry Christmas to everyone who celebrates on the 24th, btway =D
Oh yeah, I should pin something.
Jan
Jan
@Ϻ.Λ.Ʀ. *applauds*
@Jan ᕙ(⇀‸↼‶)ᕗ (づ。◕‿‿◕。)づ
Holmium holmium holmium, merry Christmas everyone!
6
17:22
@Jan you there?
Jan
Jan
Yeah?
Is this statement true?
> The isotopes with even numbers of N and Z are generally more stable.
Jan
Jan
Dunno, it’s nuclear physics.
IMO it's gibberish, since half of the elements in the periodic table have odd zs.
Jan
Jan
I wouldn't necessarily say so.
I mean, stability of a nucleus can still be reduced even though the overall nucleus is still damn stable … and I think that there are some kinds of non-trends within radioactivity half-lives, so that even-Z isotopes have longer half-lives or whatever. But then I repeat: I am not a nuclear physicist ;)
And going to have dinner now o/
17:43
\o
18:00
@Ϻ.Λ.Ʀ. noradsanta.org
Hullo @pentavalentcarbon! Welcome to the Table!
18:12
6
A: Why is Tin-112 stable, but indium-112 radioactive?

LoongFor isobars (i.e. nuclides with a constant mass number $A$), the binding energy $E$ as a function of the atomic number $Z$ describes a parabola, the so-called valley of β-stability (see also Weizsäcker’s formula or semi-empirical mass formula). $$E = a \cdot Z^2 + b \cdot Z + c \pm d/A^{3/4}$$ ...

@Loong K yeah thanks, I'll take a look.
@Ϻ.Λ.Ʀ. In short: yes, it's correct.
That's also a reason why you can do fission of U-235 with thermal neutrons, but not of U-238.
 
5 hours later…
Jan
Jan
23:07
@Mart coming from someone inside the system, which Japanese unis would you suggest for good organic chemistry in general? Just so I know which to treat preferentially when looking for postdoc positions xD
Jan
Jan
23:51
@ortho congrats on mortarboard =3

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