I'm trying to see if there is a better way to split vector into list in such a way that all consecutive unique values are put in one group.
Note that the method has to work when x is character too.
#DATA
x = c(0, 0, 0, 7, 7, 7, 7, 0, 0, 0, 0, 0, 0, 0, 7, 7, 7, 7)
x
#[1] 0 0 0 7 7 7 7 0 0 0 0 0 ...
I ham fairly new to R and I might have a rather "stupid question" here.
I have a data frame that consists multiple measurements of 10 sensors (named X1,X2,...X10). Each row number indicates the the trial number. So for example if we assume we have 7 trials then the data frame looks something lik...
I have a Python scipy csr_matrix as follows.
A = csr_matrix(np.random.choice(a=[0, 1, 2, 3, 4],
p=[0.35, 0.2, 0.15, 0.15, 0.15],
size=[10, 12]))
A dense representation would be:
[[0 2 1 2 1 0 2 0 4 2 1 2]
[0 0 1 0 2 1 0 0 0 1 ...
Usando tu metodo reemplazar le paso la expresion regular:
"(?i)[a-z]"
Que signfica:
- (?i) -> sin importar mayusculas o minusculas
- [a-z] -> letras de la "a" a la "z"
String cadena = "11222ytygygy.jkjkjj,ooiin899";
String sinLetras = reemplazar(cadena,"(?i)[a-z]","");
Output
"112...
