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02:43
Well helloooo :D
Why the hell are you guys up so late?? :O
By the way, I agree there is logic in chemistry, in most places atleast.
I have a really wonderful teacher.
Well I have a test today, in resonance..
Hope it goes well, it'll give me some confidence :D
I'll be here around 4:30
See ya guys :D
03:37
Have you guys done derangements?
Suppose a 6 men go to a hotel and deposit their umbrellas there at the reception. They enjoy their dinner there and on coming back, no one gets his own umbrella. In how many ways can this happen?
And also- Calculate $$(1.5)!$$
Lets see who can tackle this!
Hint: Use the gamma function.
Find $Re(e^{(3+4i)x})$
find $\lim_{x \to 0} \frac{e^x^3-1}{(\cos(x)-1)\sin(x)}$
You want someone to solve these for you?
No.
They wanted questions.
Jusst a discussiono chat.
discussion*
Find $$\lim_{x\to 0} \frac{e^{x^3}-1}{(\cos (x)-1)\sin (x)}$$
Mb didn't read back very far.
03:52
Kk.
Do you have any question?
Find the Taylor Series of $e^x$ at $0$.
@Tuntuni It is called a wente torus In more easier language it is a twisted torus. Torus is a donut . So you cut a torus in such a way that it is connected and the surface area is more than if you cut it another way that is cutting it from half then you will get two torii But according to this way you will get two knotted torii That is two torii joined with each other(This field of maths is called algebraic topology and knot theory)
@AdityaAgarwal Why do you ask questions when you know the answers of them this is question answer site not a quiz site
 
2 hours later…
06:23
@Arpan HOW DID YOU WAKE UP ON 8:00 THIS IS BLACK MAGIC
@AdityaAgarwal ,the limit is easy
$$\huge{\frac{\frac{e^{x^3}-1}{x^3}}{-\frac{2 \sin^2 \left(\frac{x}{2}\right)}{4\times \left(\frac{x}{2}\right)^2} \times \frac{\sin x}{x}}}$$
$\tau (1+\frac{1}{2})$ and $\tau \frac{1}{2}$ is $\pi$ or something idk
@Rememberme This is a discussion chat.
I don't remember the values of gamma function atm
But it's essentially a modification of factorial notation into function That i remember hah
cos 3x is real part
or wait
Limit answer is wrong.
:O?
I am eating and looking questions though not really going through details xD
And real part is also wrong.
It is based on the oiler's formula.
Oh Sorry, *Euler!
06:33
e^3 cos 4x
i know
Limit is wrong why?
e^3x*
(y)
Arpan's answer was wrong.
Sorry i am eating lol
I think he gave the answer in "Tau".
06:34
for?
tau for gamma function
I don't remember tau 1/2 was is $\sqrt{\pi}$
it*
Ok!
Limit's answer is?
Try series expansions for the limit.
Maybe -1/2
Not required ^^
or -2
Yes, you are right. Answer is -2.
ah yes -2
Derangements?
06:36
I remember then
them
$6! - (1\frac{1}{6!}+-$ some series
Not sure though xD
1.5! might be $\sqrt{\pi}$
In derangements, cramming till 6 is pays off in Advanced,
:OOO , I don't even remember how it works lol
Hehe.
And your answer is right!
06:39
I remember when i did it it was based on some inculsion and exclusion
But idk .-.
oh yay
Yes.
When is the exam?
24 .-. I am wreked
wrecked*
Hehe.
Sorry its $\frac{3\sqrt(\pi)}{4}$
Ah well, last exam can't wait for it to end
see i don't remember .-.
Doesn't it have gamma functions and series expansions and derangements?
06:42
I remember a trick to derive t(1/2) it was something related to polar coordinates
series expansion?
Well gamma function is not in syllabus of iit
Ohk.
Taylor Series, Power Series, Harmonic Series, Mclaurin Series.
I think the value is $\frac {\sqrt{\pi}}{2}$
I think they do come in advanced.
06:46
Harmonic nope
Answer is now confirmed, it is $$\frac{3\sqrt{\pi}}{4}$$
but you said (1.5)! .-.
In mathematics, the gamma function (represented by the capital Greek letter Γ) is an extension of the factorial function, with its argument shifted down by 1, to real and complex numbers. That is, if n is a positive integer: The gamma function is defined for all complex numbers except the non-positive integers. For complex numbers with a positive real part, it is defined via a convergent improper integral: This integral function is extended by analytic continuation to all complex numbers except the non-positive integers (where the function has simple poles), yielding the meromorphic function...
06:48
Look for $\tau (1/2 + n) $
With its arguement shifted down by one
Yes
Shifted by 1
1/2 is left outside
$$\gamma(n)=(n-1)!$$
And inside too
So we will calculate gamma function of half.
06:49
$\tau (1/2+1)=\frac{1}{2} \tau \frac{1}{2}$
Hehe
3/4 sqrt pi is for (2.5)!
I am talking about the integral.
which :O
We will calculate gamma(2.5)
06:52
uh yes sure
OK I understood the whole problem.
Or it's on wikipedia already xD
gamma(n)=(n-1)!
So gamma(2.5)=(1.5)!
gamma(n+1)=n (n-1) (n-2) ... 1
Ohk, Yes
06:53
put n=1/2 and 3/2
OK.
We'll put 3/2
Uh wait it wont work like that sorry D:
See the integral!!
Ok! (y)
or it will
06:55
Replace the first negative value by t(1/2)
in series
Yes
See the image.
I am :O
06:57
t=1/2
ok
:O?
MathJax is working!!
Yes , you can go to the link
on right
Hmm, I have saved the bookmark!
06:59
Then you just have to click it :O
Where is @Arpan
Not sure, maybe doing black magic xD
HE WOKE UP LIKE 8:00
Hehe!
I woke up at 5.
This is the kind of thing black magic do
You are alien
I know!
You?
Woke Up at?
07:00
I used to sleep at that time year ago xD
11
My brother does.
All passouts do.
:D
I know it's just like that
:P
Hmm.
Questions?
Let me try t(1/2)
Nvm found link
The Gaussian integral, also known as the Euler–Poisson integral is the integral of the Gaussian function e−x2 over the entire real line. It is named after the German mathematician and physicist Carl Friedrich Gauss. The integral is: This integral has a wide range of applications. For example, with a slight change of variables it is used to compute the normalizing constant of the normal distribution. The same integral with finite limits is closely related both to the error function and the cumulative distribution function of the normal distribution. In physics this type of integral appears frequently...
Gauss was a beast.
When he was of 10 years, he deduced the formula $\frac{n(n+1)}{2}$
07:02
I know D: like in elementry school
Yup.
And that technique too!
I used to know jack had 5 apple he gave away 1 he is now left with 4 in elementry school
Always wondered where all the apples came from
.-.
Everyone except those Newtons and Leibnizes!
Hehe!
07:03
YES!
Have ya heard about Divergence Theorem?
And the Green's Theorem?
Yes
Partial differentiation.
VEctor calculus
?
Multivariable Calculus sucks!
07:05
onononono D:
Vector calculus (or vector analysis) is a branch of mathematics concerned with differentiation and integration of vector fields, primarily in 3-dimensional Euclidean space The term "vector calculus" is sometimes used as a synonym for the broader subject of multivariable calculus, which includes vector calculus as well as partial differentiation and multiple integration. Vector calculus plays an important role in differential geometry and in the study of partial differential equations. It is used extensively in physics and engineering, especially in the description of electromagnetic fields...
All green theorem or divergence are part of this
It's quite fun
I had learnt a few tricks on khan academy about year ago
Once you are into it!
I know. I saw these on Khan Accademy only.
AHAHAHA me 2
Had nothing else to do. so went over it
lol
Like I see people craving that Trig is too hard in tenth, but once they are into it, they relish it!
Trig is well very good but our system does it wrong .-.
Always saying remember this and that, when you really don't have to remember anything
They make us cram!
07:07
YES
I know.
Gotta Go!
Our brain is already designed to keep useful information
oh ok
Bye
Hmm.
Well Said!
Bye!
 
2 hours later…
08:39
'Morning from Italy everyone! ;)
Mornin' from Latvia
08:55
Oh hi :D
If roots of equation $x^2-10cx-11d=0$ are $a,b$ and those of $x^2-10ax-11b=0$ are $c,d$ then the value of $a+b+c+d$ , ($a,b,c,d$ are distinct numbers)
09:18
Interesting! While I'm working on it I noticed that $a^2+b^2+c^2+d^2 = 2(11+5a)(b+d)+20ac$
cool :D
Lemme try aswell
@Mann That's the most overasked question.
But, it's good. no .-.
I've solved it so many times that I can now recall the final answer from the top of my head: 1210.
Yeah, it's a nice problem.
In india, you see for @AndreaL. , it's still nice ^^
09:24
@Mann Yeah ;) I recall seeing it sometimes, but now it's the first time I'm actually trying to solve it
Oh :D, it's actually a tricky one @AndreaL. .
To the credit of the professors who come up with these problems, they're really well-designed.
Actually @ParthKohli ,it even possible to find each number a,b,c,d rather than usual way. ^^
@AndreaL. here's what you should need,

$a^2-10ac-11d=0$ , $c^2-10ac-11b=0 $^^
$\log_2(a+b)+\log_2(c+d)\geq 4$ Then minimum value of $(a+b+c+d)$?
In the last two equation set $b = d$
:O
09:32
It's given that they're distinct.
But if $a^2-10ac=11d$ and $a^2-10ac=11b$, how can be that $b\neq d$?
c^2*
$c^2-10ac-11b=0$
oh!
I see that, sry I was careless :(
I know the feels :D
Happens a lot with me too
@Mann 8?
09:35
There's always room for improving, if we understand our mistakes
Hmm, it's not provided to us if they're positive.
Let me recheck.
Yep, 8 . That was one easier. Yes @AndreaL. , that indeed is true ^^
But the problem is when I keep doing that careless things again and again in exams and get wrecked .-. D:
I completed my worksheet in math. 50 questions. Holy crap.
one day only? :O
Do you guys want questions from that?
09:37
Sure why not
Nah, I completed that last week. I'm a celebrity in the class now. lol
$a^2+c^2-20ac-11(b+d)=0$ @AndreaL.
And $(b+d)=9(a+c)$
Alright, let's see.
Let's start simple.
Complete the square and find $(a+c)$
Evaluate:$$\sum_{r=1}^{n}\dfrac{r^2 - r - 1}{(r+1)!}$$
09:39
True, I noticed that $b+d=(a^2-c^2)/11$
oh cool :D
ok @ParthKohli , seems not that easy ^^
What do you think when you see a sum?
Especially one that involves fractions?
And ESPECIALLY one that involves factorials?
Well firstly i though oh something like series with $e$ secondly i tried telescopic series
thought* of
Yup, keep going.
How would you get something in terms of $r+1$ in the numerator?
That is what i was wondering ,what would be the best way :D
I think starting to get it
Does $n \to \infty?$
09:47
Nope, just evaluate till $n$ terms.
UH D:
I guess then
OK, how are you planning out the numerator?
Dont worry i got it D:
ok
$\frac {1}{(n+1)!} -\frac {1}{n!}$
09:52
Is that your answer?
Oh! $a^2−c^2=−11(10c−a)+11(10a−c)=121(a−c)$, and if $(b+d)=9(a+c)$ it should be $a+c=121$ and $a+b+c+d =a+c+b+d=(a+c)+9(a+c)=10*121=1210$
Yay :D @AndreaL. :D
At last :)
Yep\
Try the one by @ParthKohli @AndreaL. :D
It's a nice series with factorial
Just cancel them a lot ^^
@ParthKohli hopefully it is lol
I was rushing on my page, it was all messed
The sum can be easily written as $$\sum \frac{1}{(r-1)!}-\frac{2}{r!}+\frac{1}{(r+1)!}$$
Oh, the sum. I thought that $r^2-r-1=r^2-(r+1)$, so $$S=\sum_{r=1}^n\frac{r^2}{(r+1)!}+\sum_{r=1}^n\frac{1}{r!}$$
09:55
ohhh :D
Try mine
$r^r-r-1=r^2+r-2r-2+1$
It's quite easier after
That's a very inconvenient way to do it. Just write $r^2 - r - 1 = (r^2 - 1) - r = (r+1)(r-1) - r$
Telescopic, all right
Ah well, either way it just work ^^
Great.
Singing in ugly voices and mathing favorite work xD
09:58
Can't see any other good question.
:O
Maybe this one.
I think, because $$\frac{r^2}{(r+1)!}=\frac{r}{(r+1)(r-1)!}$$then from here "la vedo grigia" (I see it can be an ugly way to do it)
Hahah :D Well it may just work who knoes ;)
$r= r+1-1$
09:59
But idk sure if it will work well

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