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10:00
Yes.
No bro, scared shitless xD
I saw 2014 Advanced paper.
Could solve only 12 math questions.
2014 was easy
except maths
Yes
:D
10:00
Yes.
Check IIT 1998
too much definite integrals
They were too easy.
xD
10:00
or maybe IIt 2004
Those ones are hard.
JEE 2010.
Aditya, you're confusing me .-.
Math was too tough in 2010.
easy or hard
oh ok
those exams also existed in 1970 or 1980's those paper are rofl
10:01
Definite Integrals are hard. Rest in easy.
yes I know!
conics i absolutely hate
I like conics kinda .-.
You're in 11th?
My second favourite!
aditya?
10:02
Yes they are too good!
I like singing :d
No tenth.
Already studied 12th portion? .-.
See, we arr 17 and nothing.
10:02
Yup!
People these days .-.
xD
Coaching class?
nope^
No coaching.
Nothing extraordinary.
10:03
.-.
._.
I am too dumb. You dont know me!
You dont sound too dumb .-.
Sound!??
10:03
This is what i felt in that statement
where do you live?
Rajasthan side.
Hehe!
You both?
Mumbai
( ͡° ͜ʖ ͡°)
10:04
Pakka kota ka hai xD
OK, dont tell me mains' marks. But you can tell me your Math marks.
Punjabi
No.
Not kota.
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My last week :(
10:05
Hehe!
Bas last week hi hai. Uske baad to khatam.
Yep
Then we can finally learn new things
Studied a lot for this
Math marks?
Hmm.
Gonna feel weird after a week
This is what i feel
ヽ༼ຈل͜ຈ༽ノ
10:06
Did you take coaching?
I know.
When you ask math marks
Yep
Resonance
How much then?
Kota?
( ‾ʖ̫‾)
Mumbai bro -_-
10:07
Ok, you live in mumbai.
Sorry sorry!
(ง ͠° ͟ل͜ ͡°)ง
No worries :p
"You can perform this action again in 13 seconds."
My net is too slow! :(
When @Mann doesn't have memes, he makes them
[ ͡° ͜ʖ ͡°]
I feel to lonely without them .-.
10:08
Hehe! :P
get a girlfriend
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seriously
No useful applications in it .-.
Complex numbers? They are great.!
10:08
PC > gf
PC win
"chat.stackexchange"
Yes . Complex geometry
lonileness go away
complex is good
True :D
gf.stackexchange is is required .-.
Complex numbers
Hehe!
Make it.
10:09
stack.gfexchance lol xD
Lmfao
*exchange
I wish xD
For when you've had enough of one :p
10:10
Actually, I am not such a loner, I had chances just didn't took one :D
stack.exexchange
BRO'S BEFORE ....
YES
I so get you :D
:o
@AdityaAgarwal , you are comfortable right?
10:11
whispers they're gonna get you :o
Yes, that is what remove for .-.
Haha lol
Jee advanced is getting prepared. xD
We're sorry @AdityaAgarwal we'll change the topic :p
10:12
Yes
You'll know me gradually.
$\sin x + \cos x=\sqrt{y+\frac{1}{y}}$
the word you're looking for is eventually?
$x \in [0,\pi]$
10:13
@Mann No of solutions?
No the solution
Oh i see
You got me.
It's easy one :D
Tricky huh
10:14
@AdityaAgarwal , are you troll or sober type?
Troll :P
$x=\frac{\pi}{4}$
Oh great
$\woo$
like a boss
If you are angels then I am a devil!
10:15
You don't know my angel level it's over 9000 :D
$2 \sin x \cos 2x = \sin x$
Troll level $$\lim_{x\to 0^{+}}\frac{1}{x}$$
Wait i got a facebook post lemme show
@Mann The question?
Find... ?
10:17
$x=\pi/4$??
sin2x=1
or $\sin x=0$
2x=\pi/2
Find everything :d
in $[0,\pi]$
x=0,
$x=\frac{\pi}{6}$
10:19
Or use $n\pi$
$x=\frac{5\pi}{6}%
Yes
$x=\frac{5\pi}{6}$
$x=\pi$
Yep
Oh well you can generalize :p
10:19
Did you look the post?
Haha that fb post! xD
Baby are you rytght angel , cause i am feeling a $\tan (\pi /2)$ in my ".fill here ". xD
.fill?
Ohhhh
xD
:D
@AdityaAgarwal , got it? :D
10:20
That page is crazy over samosas lol
I know, that guy adtiya sr
Is actually on quora
I have seen him, he's from iit khg lol
haha
Let me show his post, it's good one xd
Ok, yes :D
10:22
people do all kinds of stuff after iit
!!
Hehe, no one knows it better than me and my brother!
Yep :d
First have to get there .-.
True that's the only problem .-.
Do you guys follow EPL?
10:23
Then troll level to $\lim_{x \to 0^+} \frac{1}{x}$ finally
not really the time atm xD
yep xD
can't find the post atm
Whut?
Nope
10:27
Nope
not really the time bro
Hmm.
Cricket?
not the tiiiiiime
All the time!
10:29
Have you done number theory?
India is cricket-crazy
Not even little :d
Hehe @Mann!
Did some of it
Last year in INMOTC
10:29
Don't remember anything .-.
I have given it.
Yep
Qualified?
6 questions?
No.
You must have given RMO?
Only till INMO.
10:30
Oh ok
Me too xD
$$\huge{\int_0^1 \frac{x^{\alpha}-1}{\ln x}.dx} $$
Use two dollars, its too small
D:
Only till INMO.
Yup.
Number theory is very difficult in it.
Holy **** thats big
True @AdityaAgarwal
10:31
I made it $\huge
"ADD lenny face here"
intriguing
I am trying differentiation under the integral sign
It's not easy D:
Yes D:
10:34
\alpha?
How to do :o
$I(\alpha)$ yes
a constant?
Yes
$I(0)=0$
10:34
or another variable?
constant
Anyone here giving FIITJEE AITS? :p
Never heard of it! :P
The answer maybe 0
10:37
$\log(\alpha+1)$ :(
$Fk, lost the question. $
xD
damn it xD
Haha xD
Wolfram alpha wins again
oFc :d
I actually tried this
what :o
I(0) =0
I'(0)0=
=0*
10:38
Whaat?
$I^{\alpha}(0)=0$
Derivative wrt $\alpha$
So...?
Well now you have to integrate it alpha times :D
using initial condition $I^{r}(0)=0$
Wait let me write something down im not getting anything :p
OK
Wait fk
I took such an wrong derivative
Kill me
10:40
omg so easy :o
I actually derived $x^{\alpha } $ as $\alpha x ^{\alpha-1}$
Haha xD
wrt $\alpha$!
Killme :D
Easy, but tricky, IIT confirmed xD
Hehe Indeed
10:41
@AdityaAgarwal You here?
Wait one more
sure bring it on :D
Yup*
Was doing something.
solve these questions they're good
10:42
Hello guys!
Well heloooo
Apna asli naam bata bhai @user223679 :D
hahahaaa
Aj nahi chhodunga :D
10:42
@MayankJain @AdityaAgarwal @Waffle'sCrazyPeanut Welcome to the Indian Room!
keep it english!
@Mann still waiting for your question!
$\huge{\int \frac{(x^2-1)}{x^3\sqrt{2x^4-2x^2+1}} . dx}$
@user223679 , name bata :D
@AdityaAgarwal Please don't post all of your questions here asking for upvotes. Its sort of looked down upon by the community.
easy :p
10:44
Not for upvote but for solving .-.
I had a question ban.. so!
Straight out of the IIT @Arpan :D
$$\frac{1}{2}\frac{\sqrt{2x^4-2x^2+1}}{x^2} +c$$
And guys, try to use "reply" feature of chat. Click on the message and there will be an arrow head which is the reply symbol.
$I_n=\int^{\pi}_{-\pi}\frac{\sin nx}{(1+\pi^x)\sin x} dx$ $n \in \mathfrak{W}$
10:46
@AdityaAgarwal Question ban for?
Find reduction formula
I don't know. Asking too much questions! :P
@Mann Right now, I am replying to Mann's last message.
$\sum_{m=1}^{10}I_{2m+1}=?$
LO
:O
Try out the reply fearure.please.
10:48
$\sum_{m=1}^{10}I_{2m}=?$
Where
@user223679 ok
Did
Sorry for that :p
Lmfao @Arpan
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@Arpan It will reduce the crap of wondering who replied to whom.
10:50
No problem it's random mess @user223679 :D
@user223679 Seriously tho, it was just a joke, im all for the reply thing
:D
@Arpan And that meme was good ;)
@user223679 tell us your name :D
@Mann Raj. But dont ask me to change my username.
3
@user223679 , change your username :D
10:53
@Mann Lol :D
$$\huge{\frac{1}{\sin^2 \theta +3 \sin \theta \cos \theta + 5\cos^2 \theta }}$$
Maximum
@AdityaAgarwal Asking bad questions leads to a ban. And by asking upvotes for downvoted questions, you are going against the system.
Sorry bhai.
Galti ho gayi.
Moderator sahib.! :P
@Mann Are you sure you don't mean minimum?
No .-.
Minimize denom ,maximize nume :D
10:56
@Mann sorry messed up a bit
@Mann 2?
Ruk kar raha hun mein LD
:D
Haan
Cool :D
@AdityaAgarwal I am saying so that you dont repeat it. So that you can get out of it. Just helping you out.
More questions! :D
Ok
10:57
I know. Thank you for your kindness. :P
Raj : Troll level $\lim_{x\to 0^{-}}\frac{1}{x}$ :D
@Arpan Find the range of xln(x)
$$\huge{s_n=\sum_{k=0}^{n}\frac{n}{n^2+kn+k^2}} $$ $$\huge{T_n=\sum_{k=0}^{n-1}\frac{n}{n^2+kn+k^2}} $$
Let F(x)=f(x)+f(1/x) where f(x)=int_{1}^x \frac{log(t)}{(1+t)}dt. Then F(e) equals-?
@Mann Just did this one few days ago :p
10:59
Ahahahah :D
Gotta find a integral compare reimann sum?
Roger

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