We love math, physics, chemistry and random talk.

Mann

13:00

$g(x)=\frac{4x^3+2x}{x+1}$ .'. this just got weirder

uh waot

no

ADG

g(x)+g'(x)=12x^2+2

$$g(x) = c_1 e^{(-x)}+12 x^2-24 x+26$$

and now:

user223679

ADG

$$\int_0^1\frac{12}{g(x)+g'(x)+10}{\rm d}x=\int_0^1\frac{12}{12(x^2+1)}{\rm d}x=\frac{\pi}4$$

Mann

welcome become user :d

ADG

@user223679 we don't support homework without any efoorts. Vote to close

:D

Mann

13:03

Lol

But this question seems fun

pp

oo

user223679

lol

ADG

GMP numerical

Mann

Can the rod move?

That attrached to pulley right next to cylinder

user223679

No idea. This is the complete question. But it shouldn't move.

ADG

obviously it is just there to maintain another pulley at that heigt otherwise it would fall.

Mann

13:05

Hmm cool then it's easier ._.

user223679

GMP fullform?

ADG

I love SHM

Mann

Well this really has lot of tension to real with

2

ADG

nvm

Mann

Lol D:

ADG

13:07

natural length makes it's easy, it is oral

user223679

@Mann Whats the fullform?

Mann

neither i know .-.

ADG

nevermind the full form of nvm

user223679

I can guess G and M ;)

Mann

I am glad you didn't guessed P

:D

guess*

ADG

13:08

grandmaster'spackage

oh you're thinking GMC?

user223679

Yes. This is some FIITJEE paper.

Mann

I have no clue for this question .-.

user223679

@ADG 5 mins are up, you missed 2 questions, your rank fell by 2000. You are screwed , so RELAX!

ADG

sorry

Mann

I am in rank 900000 atm

I feel nice

ADG

13:15

@SMF are you just walking in the park

what brought you here?

Mann

WHY IS THERE AN ARROW with circlular curve on that massless rod!

SMF

just wondering what sort of things are discussed in a chat called "We love math"

Mann

Apparently , it's little different from math .-.

ADG

@SMF we're random indeed "the real desi chokras"

sorry Mann if I wrote soething not according to the motives.

Mann

hindi mein bat kar raha hai shana .-.

ADG

13:17

@Mann Maybe he came to ban me, no!

no

Mann

NO!

ADG

@SMF please don't ban me

We're just having mutual fun

We're not fighting

SMF

...I'll think about it

user223679

He doesn't look like a mod. Don't freak out.

ADG

@SMF I beg you my lord.

user223679

13:18

He can just look around right?

Mann

I am scared

Check this guys **

http://math.stackexchange.com/questions/1272579/evaluating-a-double-integral-that-arises-in-computing-the-solid-angle-subtended/1281837#1281837

2

A: Evaluating a double integral that arises in computing the solid angle subtended by an equilateral triangle

Let $\Omega$ be the solid angle we seek. It is actually not that hard to compute $\Omega$ by evaluating your integral in polar coordinates (see method 1 below). Method 1 - direct integration in polar coordinate. Rotate the figure $180^\circ$ with respect to the center. By symmetry, $\Omega$...

ADG

@SMF ok can[are you able to] you write a code to print 00:30;01:00;01:30;02:00;... with python?

SMF

Sure, it goes like this
print("00:30;01:00;01:30;02:00;...")

lol

Mann

SMF IS FROM STACKOVERFLOW

**

ADG

@Mann you should've maybe asked me with when I can provide simple solution

@SMF false attempt server breakdown

Mann

13:21

BUT THAT GUY ANSWER WAS AMAZING

**

ADG

@Mann K

back to reality

Mann

SEE

ADG

[Oh this reminds me of Eminem]

Mann

I am still seeing the answer

PERIPHERY

ADG

@SMF are you interested in talking?

Mann

13:22

Talk to him in codes ** English is hard

SMF

Talk about what?

ADG

@SMF this.World.getUsers().getUserbyName("SMF").ask("Is he interested in talking").getReply().print();

aything?

speak whatever comes to your mind

@Mann probably user just came back to shadow me with his most powerful question, maybe he was hurt with ellipse, but now he's gone back?

SMF

"whatever comes to my mind".speak();

Mann

Lol but i liked the SHM :D

SMF

Hmm you want a quick math puzzle?

ADG

13:26

@SMF semanatically incorrect, : speak(getWhateverComestoMyMind());

user223679

room topic changed to We love math: Random Talk. If you don't understand the talk, hardluck! (no tags)

Mann

BETTER^

ADG

not the room you are looking for?

Mann

we are too bad at math @SMF .-.

ADG

There are other rooms, with 104 users currently talking in 59 rooms

user223679

13:27

@ADG I was not hurt with that ellipse question. Lol, I didn't remember the eqn of tangent. And my powerful question is the one I can't solve ;)

ADG

@user223679 maybe you can solve this then

Mann

NO

ADG

plz yar name change kar na ajjeb sa lag araha hai user bol bol ke

Mann

I WONT

DO ANYTHING

:(

My rank fell by 100000 already D:

ADG

this=user's cylinder question

english ko maaf karo

Me:

Mann

13:29

I wanna solve that cylinder

Solve it for me @ADG

user223679

I couldnt @ADG

ADG

eating kurkure while having two chrome browsers splistscreen open one with chat and best online games and other cylinder question while having a penn and paper on desk trying random thoughts

user223679

Which Kurkure?

ADG

chilli chatka

Mann

Interesting interest in type of kurkure

2

D:

ADG

13:30

LOL

user223679

Color?

ADG

paglon ki tarah hansh raha hoon

Mann

Lmao this topic @user223679 @ad

Same

ADG

dark green

Mann

@user223679 , uska solution hai?

ADG

13:31

gale main fansh gaya

Mann

Nice

Ab mera rank aur niche nahi girega

ADG

$\sqrt 6$ to kahin se aata nahi dikh raha

Mann

Bahar mat nikliya kurkure!

user223679

I guess SMF will run away, thinking that 3 mad people are talking crap in this room. lol

SMF

Hello

Mann

13:32

Hi @SMF :)

Glad he doesn't know hindi

ADG

@Mann remove your message instantly

suspension warning

user223679

Btw, I asked about Kurkure because all the other things which he mentioned was not interesting.

Mann

ADG

something simlar happened to me

Ok here' the solution

Let cylinder move x distance to right [The COM]

then compression in right spring is x

Mann

Yep

4k has 2x right?

ADG

13:34

now let springs 4k and k on left are extended by $x_2$ and $x_3$ respectively

Mann

don't know just guess

ow

ADG

then $x=2x_2+x_3$

and let tension in right string be T that is $T=kx$

user223679

Who got a suspension warning and why?

SMF

Keep up the good work

ADG

and in left be T' which is $T'+kx_3=4kx_2$

@SMF vague statement lacking context [yours]

Now $T-T'-f=ma$

and $fR=\frac12mR^2\frac aR$

so $f=\frac12 ma$

and thus:

$$T-T'=\frac32 ma$$

now find T and T' in terms of x and put it here,

Mann

13:36

Wow I can't keep track of things in all these tension.

xD

ADG

then relate to $a=\omega^2x$

then Time period is $2\pi/\omega$

user223679

Who got the warning and why?

Mann

Anyway continue oo

Interesting

ADG

but I am bad in solving equations so I solve most such questions in exam 2-3 times and therefore get less marks

and I have trid it many times but can't get the answer.

maybe you people can solve now?

Mann

Nope , I am hopeless.

user223679

13:38

@ADG Please reply to my initial question.

ADG

@user223679 which?

user223679

1 min ago, by user223679

Who got the warning and why?

ADG

because I said "chal na jhandu paka mat" jokingly on chemSE to someone who knew english only but the IITB third year student who is also the moderator of Phy and Chem Se was there and suspended me

Mann

$T'+kx_3=4kx_2$ how

ADG

the pulley is massles

force on it must be zero

in left see again

I think $\sqrt 6$ can come if we consider the masslese rod's rotation too.

Mann

13:41

Yes there's a freking circular arrow

freaking

D:

ADG

that's just pointing to its name

Mann

FML

ADG

I can't solve linear equation

*s

I am struggling

user223679

I think that the massless rod is fixed.

Mann

I can't do anything

ADG

13:44

let's try it first

here are the equations:

$$T=kx\\T'+kx_3=4kx_2\\2x_2+x_3=x\\T-T'=\frac32 ma$$

Mann

ROGER

ADG

missing one more equations regarding x's

Mann

WE NEED $x_2$

:|

ADG

yup

Mann

What if the pulleys move o.o

ADG

13:48

I've already considered that and it is in accord to that.

Mann

Then let's suppose they don't xd

Damn this shit is impossibru

ADG

thinking

room topic changed to We love math, physics, chemistry and random talk.: Random Talk. If you don't understand the talk, hardluck! (no tags)

Mann

Not chemistry tho

Not that much

.-.

ADG

placeholder.

Mann

Did you get the solution? xD

ADG

13:56

well it might taqke up an hr.

Mann

I'd solve it in 2 days here goes my rank to 90000000

user223679

@Mann Only 1.5 lakh students appear.

@ADG Wtf happened there?

Mann

I think we need some $\pi ^2$$ T = \frac{1}{2\pi} \sqrt{\frac{k'}{m}}$

HIHi user

Effective spring constant is

$3\pi^4 (\eta + \sqrt{6})^2 $!

@user223679 I made it to 11 lakh 50 thousand now. :)

ADG

14:28

@Mann I seriously need a break from SE

Mann

Lol, well same. Should solve some easier previous year question

user223679

@ADG I understand. Better to come back after ADV.

Mann

^

ADG

@Mann got another half hour ban there

Mann

After 24, i gotta start caring back for looks .-. , i seriously degraded them a lot.

Where?

Chem?

ADG

14:30

aur shayad user unke saath mil gaya hai

The Periodic Table

Haikus are awesome / Chemistry's even better / So pull up a chair

Mann

:O

Chemistry ain't for me xD

ADG

@Mann just read the messages and come back

Mann

Ok

user223679

@ADG No. It would be better for you because people will look at your past records and not at the present you.

ADG

It doesn't feel bad having a bad rank but when a firend that was below you has a better rank.... you know

@user223679 matlab?

Mann

14:34

Da hell,

ADG

@Mann ??

Mann

doing .-.

dat lordstryker is so full .-.

of himself well

but user why are you praising him .-.

ADG

His messgae: "Do you always come here with the intent to be irritating or is it just by accident?" was actually "Do you always come here with the intent to be a dick or is it just by accident?"

He edited it

user223679

Matlab, log teri past dekhenge aur present ko nahi dekhenge. Isiliye interact mat kar. Simple.

Mann

.---.

woh banda .--.

user223679

14:36

@Mann Make this chat room protected. Dont keep it public.

Mann

How

ADG can 11000 k

12000

I am just poor 1127

ADG

room mode changed to Gallery: anyone may enter, but only approved users can talk

user223679

Go to [access]

Mann

Have seen

"anyone may enter"

Got the solution to that physics one tho? o.o

ADG

I was angry so I said "gth" and I got suspension for 30 mins

w8

Mann

14:38

I think the cylinder rotating ain't so simple

As i said effective spring constant is $3\pi^4 ( \eta +\sqrt{6})^2$ Already seems nasty or $\eta = 0$

But idk

user223679

Btw, no need for gallery. It lets people view the transcript. Keep it open for all :)

Mann

Yep, I know seen it.

Back to the physics .-.

ADG

@Mann hmm

what did he said to you?

Mann

Nothing, "don't worry about it"

I said it's rather rude.

Before the reply

ADG

and he said

Mann

14:51

Hi SMF

Welcome

user223679

SMF is back :)

ADG

@SMF maybe he need to ask us

Mann

How to add **

And that physics problem got any new idea?

ADG

nope

Mann

Man the effective spring constant is already weird enough, i think 0 will be the most probable case

@SMF , why are you here though :D

user223679

14:55

Just let him in.

ADG

added SMF

@user223679 would you tell your real name

and the real reason you called me this afternoon

and @Mann how do you know him?

Mann

I know who?

ADG

user22

Mann

I just met him, in this room. :O

@user223679 , indeed what's your real name though.

user223679

It is:

223679 ;)

ADG

14:58

bah! not good.

Mann

facebook.com/Limitsofawesomeness

2

Here's is me :D

Real name

Though mann is already real enough lol

Mann

15:17

Can you find the answer?

http://math.stackexchange.com/users/59379/achille-hui

user223679

?

lol

Mann

Not sure. No idea^

user223679

15:39

-5

A: Why is geometric progression called so?

In geometric sequences, each number is the geometric mean of the numbers adjacent to it, assuming that all the numbers are positive. EDIT gregory grant you're not correct.

@Mann

Mann

The downvotes were strong lol

user223679

Look at the revisions.

Mann

Grobnocker lol

I am bored of jee advanced now .-.

user223679

-46

Q: Unique Representation and The Fundamental Theorem of Arithmetic

While reading this thread Is 1 a prime number?, I recalled that The Fundamental Theorem of Arithmetic (FTA) which says that every positive integer greater than 1 can get written uniquely as a product of only primes except for order of the factors. What does "uniqueness" here mean? I ask, beca...

number-theory

Most downvoted!

Mann

Wow -46 though. Lol You are sure good at searching lol

user223679

15:47

@Mann Just sort the questions by votes and go to the last page.

Mann

250 bounty too .0.

Gonna take a bath sec

user223679

@Mann See you later

Mann

17:05

Admit card tomorrow :D

Mann

18:56

room mode changed to Public: anyone may enter and talk

The Periodic Table

Transcript for

$Mathematics$ We love math, physics, chemistry and …