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16:14
1
Q: Asked to review my own question

rcollyerOver on Mathematica.se, I was recently asked to review my own answer: which seems like a bug in the review process.

16:40
Hey people, quick one. All my messages are being output in the Messages window, and not even recorded in $Messages, even after kernel restart. Do you konw what global option I touched*
16:58
@Rojo are you here?
17:40
@rojo Perhaps Preferences > Evaluation > Message and Warning actions ?
 
2 hours later…
19:34
I'm here @MrWizard
Yeah, thanks @SjoerdCdeVries
(I also had mixed up $Messages with $MessageList)
@rojo So everything back up and running?
Everything good ;)
OK, back to this weird question then
0
Q: how to solve a numerical function equation? (DSolve?)

LászlóI reduced a (special case) of my problem to the following code. Even though in this special case all related functions are analytical, I am not sure DSolve is the tool for this, esp. as no derivatives are directly involved yet I am indeed looking for a continuous function as a solution. H = Pare...

Btw, @MrWizard, I think I read a few days ago that you complained that you barely had a chance to answer questions lately.... Then I saw you were leading the rep table this month. You aim too high, hehe
acl
acl
20:08
@SjoerdCdeVries I think it's a mathematical misunderstanding (or it was); see my answer
@acl I did that too, but substituting back the solution gives problems. The integral doesn'tconverge
acl
acl
@SjoerdCdeVries could be, I didn't check and won't. it's not a mathematica question, but a mathematical one
@acl True. BTW did you forget a Exp[zz - z] term?
acl
acl
@SjoerdCdeVries no it's Exp[zz-z]=Exp[zz]Exp[-z] so I pulled Exp[-z] out of the integral and subsumed it into h (or whatever I called the thing)
OK. Did that too.
acl
acl
20:12
this is one of an increasing number of half-thought-through questions which are impossible to parse because the poster throws a complete problem at us.
@acl close this one?
acl
acl
@SjoerdCdeVries I think if he agrees that this is indeed what he's asking then it's a mathematical problem now, so I'd close it
or migrate but I doubt anybody would like to take it
R.M
R.M
I haven't been able to follow any of his 5 open questions so far
@R.m. He's fumbling around
no clear thinking here.
acl
acl
yes, and too much detail.
20:15
Tries a few command names that sound good, and ask questions here if nothing comes out of it.
R.M
R.M
Ok, I've voted to close and left him a comment too. Perhaps others will too...
acl
acl
@RM so you're saying that he'd have worked it out had he thought about it? damn, and I thought it was my exquisite mathematical ability that led me to the answer...
ok @sjoerd nuked it already
R.M
R.M
@acl no, that he'd have asked clearly had he thought about it a bit more...
acl
acl
@RM right, I was joking. You're not meant to answer seriously :) Of course he should have thought for 5 min before asking
20 minutes of my life spent badly
R.M
R.M
20:24
@acl :)
acl
acl
@SjoerdCdeVries guess it was more of his time wasted on this though :)
20:38
@Rojo It's a far cry from the days on StackOverflow where at times I answered about 50% of the questions. :-) I just posted a solution to the Except[x ..] question using your guard trick; thought you'd like that.
R.M
R.M
You've answered about 18ish % of all questions on this site... the next highest is Szabolcs at 12ish%, followed by Heike, Leonid and myself at around 10-11ish%
~20% is crazy
R.M
R.M
21:16
@Verbeia answered as predicted!
1
A: Combinator Reduction Wolfram Mathematica

WReachLet's define a function called eval that will perform one step of combinator evaluation. First, we need to consider what exactly constitutes a single step. Arbitrarily, we will evaluate the left-outermost expression first and work inwards from there. ClearAll[eval] eval[e_] := Module[{r = eval1[...


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