Wolfram Mathematica

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C. E.

00:02

0.056331 seconds

halirutan

@C.E. Exactly. Forgot about vectorized assignment.

(the offsets are wrong, but that can be fixed)

4 hours later…

zhk

04:26

Hello!

How to avoid this overflow problem?
Z1 = (7580104959982914123117804044806461820154572036369549529405552162\
6488569562312450304058967833376318713210170859333343064305013439093653\
79890910193903441 - \
(760161143827796896393043533996637553776272378892913824150509233503221\
6337024111944145650540579951639515460945444623092013993572866002842083\
492323809287290^17592186175489));
Z2 = (7580104959982914123117804044806461820154572036369549301773204651\
0446541563286119940196786027909330520499970747379421470095046003374583\

5 hours later…

Szabolcs

09:32

Questions are just more boring than they used to be a couple of years ago.

J. M.

09:45

@Szabolcs I do kind of miss the days of beta...

...on the other hand, we have users like Michael and Kuba who joined way after the beta period, but have contributed so much.

Szabolcs

10:02

GeoGraphics accept entities in many places, and interpret them based on context. Is there a way to replace these entities with their interpretation even before applying GeoGraphics?

E.g. Polygon[Entity["Country", "Austria"]] should be replaced with the result of Entity["Country", "Austria"]["Polygon"]

Point[Entity["Country", "Austria"]] should be replaced by Point[Entity["Country", "Austria"]["Position"]]. And so on.

I could try to write code for all these specific cases (Point, GeoMarker, Polygon, etc.), but this is a lot of work, and not robust (I will probably miss some cases, and new versions will introduce new cases).

Is there a builtin way to do this automatically?

Szabolcs

10:28

Q: Python to Mathematica

I am required to use Mathematica for a course I am taking, but prefer to use python for everything we are doing. I am interested in writing a program to turn my python scripts into Mathematica code that I can run and submit for the class. After doing some research, it seems like I'm trying to mak...

"I don't know Mathematica and I don't want to learn Mathematica. Therefore I will write a program that auto-translated Python to Mathematica!"

Kuba

@b3m2a1 are you aware of any formatting function from GeneralUtilities that works with boxes as opposed to expressions? The problem is that I'd like to preserve operators forms I started with, that is sometimes keep [[]] and sometimes Part etc, not let MakeFormatedBoxes decide.

rhermans

@zhk So you want to be able to deal with Integer number of the order of 10^10^15 in Mathematica?

J. M.

@Szabolcs Poor, unknowing, little kid...

rhermans

10:48

@zhk Surprisingly Log10@Log10@$MaxNumber is 15.13 in my system, but your numbers are larger than 10^10^15.43. As the error you are finding explains, "This message is generated when the scale of a result exceeds the scale of numbers that can be represented in the version of the Wolfram Language that is in use."

zhk

@rhermans i had a little idea about this. I wanted if there is some work around to avoid overflow

rhermans

11:17

@zhk You need to explain better what you need. Integers? Floats? Which operations? Exact or approximate? What is the final goal?

zhk

12:13

@rhermans here is a working example

Z1:= (7580104959982914109394378405621081680045277328933902877018950173722431866047182165909685701898461476201769271496346873969218041590426190558248064238412-(5542744080416549313204339685348101804092633280776996094712323671936025724303663565120968650288374354487920966943136994524637343823470109069100536001825061^65537));
Z2:= (7580104959982914109394378405621081680045277328933902557064898247755957479231576299665165903124564064889635003580310606233252493957322555511313835652894-(221005295986323366635263174360554494848966934958858976293573138235370627268786…

2 hours later…

Seriouslynothing

14:00

Hi everybody, I know I can find this in the documentation, but I can not figure out how to do it, I have tried for several hours.

I have a list of lists lists, list={{1,2},{3,4}} (much bigger) and I want to add a fixed value to every second item of that list, so that biglist={{1,1002},{3,1004}}

could anybody please help me?

Jason B.

@Seriouslynothing Something like

list2 = {#1, 1000 + #2} & @@@ list;

list2 = ConstantArray[ {0, 1000}, Length@list] + list;

Seriouslynothing

yes, both work, thank you very much, i'll look into why exactly they do what I want

oh man I was trying to get this for so long now

J. M.

14:43

Version 11.2 is now available in the cloud.

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