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11 hours later…
12:13
0
Q: Collatz-like recursion issue

EusaI created a variation of Collatz's sequence that includes division by three. As far as I understand it is stable and works just like the original recursion. Additional tests are of course desirable. $$f(n) = \begin{cases} (3n+1)/2 &;\text{if } n \equiv 1 \pmod{2}\\ n/2 &; \text{after previous if ...

12:27
One more vote to delete incorrect answer
 
2 hours later…
14:53
Thank you , Jose

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