^^^ The rudeness has been handled by a diamond mod (thanks!). The dupe answer still needs 2 D's (alas I mistakenly retracted my D due to the poor UI - amazing they have not fixed this yet).
Please, is it correct to argue the following?
Let us set the Riemann functional equation equal to zero
$$
\pi^{-\frac{s}{2}} \Gamma\left(\frac{s}{2}\right) \zeta(s) = \pi^{-\frac{x+iy}{2}} \Gamma\left(\frac{x+iy}{2}\right) \zeta(x+iy) = 0,\ x\in (0,1), y\in \mathbb{R}.
$$
Factors $\pi^{-\frac{x+i...
@XanderHenderson closed. Perhaps the comments, if they continue below the question, could be moved to a chatroom? The thread is not outrageously long. But if it gets longer....
I am requesting to reopen "Bounding with exponential Markov inequality".
The asker posted a question and showed the work that they had done so far. They explained where they got stuck (can't show $at-\phi(t)$ is positive), and their unsuccessful attempts (Taylor expansion). I explained why they w...