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[ SmokeDetector | MS ] Potentially bad keyword in answer, blacklisted user (70): Probability Disribution Tables by srsly on math.SE
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@user21820 All gone.
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Q: Vector field over $\Bbb Q^2$

UltradarkConsider the vector field restricted to the rationals, $\vec F_\Bbb {Q^2}=(x,y).$ This is a vector field $\vec F:\Bbb Q^2\to \Bbb Q^2.$ Is this vector field weak with respect to the same vector field over the reals: $\vec F_\Bbb {R^2}=(x,y),$ $\vec F: \Bbb R^2\to \Bbb R^2?$ Edit: A weak vector f...

The above question was closed for being unclear. How can I make it more clear?
 
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RRL
RRL
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For deletion: DA, DB, DC, DD, DE, DF, DG, DH

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