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RRL
RRL
00:56
For deletion: D1, D2, D3, D4, D5, D6, D7, D8,
RRL
RRL
01:20
For deletion: D9, D10, D11, D12, D13, D14, D15, D16
 
4 hours later…
SmokeDetector
SmokeDetector
05:41
[ SmokeDetector | MS ] Few unique characters in body, no whitespace in body (190): Find all functions $f: \mathbb{R}\rightarrow \mathbb{R}$ satisfying a functional equation ✏️ by AngelBaVy on math.SE
Devashish Kaushik
Devashish Kaushik
@JyrkiLahtonen It probably needs to be closed again, as the OPhas edited it back into a PSQ.
Also, the OP's other question happens to fall in the same category.
Devashish Kaushik
Devashish Kaushik
06:22
PSQ
PSQ2
PSQ
 
2 hours later…
Jyrki Lahtonen
Jyrki Lahtonen
07:58
@DevashishKaushik At least now the question makes sense. It may even be true, fianally :-) Yeah, it is still a PSQ, but now there is some hope to turn this into a real question. I don't know what's best.
 
2 hours later…
SmokeDetector
SmokeDetector
10:26
[ SmokeDetector | MS ] No whitespace in answer (95): If $\cos\theta=\frac{\cos\alpha+\cos \beta}{1+\cos\alpha\cos\beta}$, then prove that one value of $\tan(\theta/2)$ is $\tan(\alpha/2)\tan(\beta/2)$ by Tsr on math.SE
[ SmokeDetector | MS ] Blacklisted user (69): If $m^2\cos{\frac{2\pi}{15}}\cos{\frac{4\pi}{15}}\cos{\frac{8\pi}{15}}\cos{\frac{14‌​\pi}{15}} = n^2$, then find the value of $\frac{m^2 - n^2}{n^2}$ by Tsr on math.SE
SmokeDetector
SmokeDetector
10:45
[ SmokeDetector | MS ] Blacklisted user (69): Finding the value of $x$ when $2^{\frac{1}{\cos^2(x)}}\sqrt{y^2 - y +\frac{1}{2}} \leq 1$ by Tsr on math.SE
[ SmokeDetector | MS ] Blacklisted user (69): If $\tan{\frac{x}{2}}=\csc x - \sin x$, then find the value of $\tan^2{\frac{x}{2}}$. by Tsr on math.SE
 
6 hours later…
RRL
RRL
17:02
@user21820 @MikeMiller @Lord_Farin @Did : Items D2 - D19 need one additional deletion vote each. Thanks.
SmokeDetector
SmokeDetector
17:54
[ SmokeDetector | MS ] Mostly non-latin answer (50): What is Var(X - Y)? by user645681 on math.SE
 
2 hours later…
Xander Henderson
Xander Henderson
19:24
Ugh... PSQ as audit.

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