MY SOLUTION
Let the given sum be S. Then
S=lim a→−∞ S=1
lim a→0 S=∞
In the range of (−∞,0), it has one minimum at a=−2,b=4, the minimum value being 0.75.
Also, S=lim a→0 S=lim a→2 S = ∞
Since b>0, a<2
In the range [0,∞),s has one minimum at a=2/3, b= 4/3
the minimum value being 1.25 > 0.75....
@Arjun I should also say that I am not criticizing you. This room gets a lot of flak on the main site, and I think it is important to not give ammunition to dishonest brokers who will take quotes out of context.
The quote "this guy hasn't been using mathjax, with repeated warnings", taken out of context, can look bad.
Or maybe a little more accurately, I think the right rule is not to talk about specific users in a context where it could be misconstrued that action should be taken on many of their posts.
Discussion of patterns of problematic user behavior are better tackled through moderator flags, and then maybe meta as a last resort.
Indeed, @rschwieb. It is helpful when users notice patterns of problematic posts, to alert mods via flags, rather than chatrooms. So I do think it is valid for a user to note patterns of misbehavior by specific users, but to use flags for moderator attention when such a pattern exists.
"Is there a criterion, a clue that makes me think that certain integrals can also be solved through complex analysis and how to solve them?"
When I can't solve an integral, I use the numerical methods.
Thank you all very much.
@Sebastiano I have no idea why you received downvotes on two of your questions. But this room is not really the place to complain about downvotes on one's own posts. You can flag the posts, if you think the downvotes were made in bad faith. But this room is dedicated to requests for Closure, undeletion, reopening, deletion, or editing.
@Sebastiano if you're looking for how to edits to improve, try adding more explicit context. For example, what, exactly, does it mean to "use complex analysis"? include your definition of this
MY SOLUTION
Let the given sum be S. Then
S=lim a→−∞ S=1
lim a→0 S=∞
In the range of (−∞,0), it has one minimum at a=−2,b=4, the minimum value being 0.75.
Also, S=lim a→0 S=lim a→2 S = ∞
Since b>0, a<2
In the range [0,∞),s has one minimum at a=2/3, b= 4/3
the minimum value being 1.25 > 0.75....
"Is there a criterion, a clue that makes me think that certain integrals can also be solved through complex analysis and how to solve them?"
When I can't solve an integral, I use the numerical methods.
Thank you all very much.
