2:25 AM

3:07 AM
@XanderHenderson Indeed. It's easier to teach face-to-face because the real-time continuous student responses push certain buttons in our head harder than the intermittent sometimes non-existent responses on the internet. =)

@user21820 Regarding the comment above, thank you for the kind words here.
And yes, the lack of face-to-face makes things different.
I mean... I've taught this class multiple times. :\
I any event, it is 8, and I would like to get to sleep before people start setting off fireworks.
G'night.

3:26 AM
@XanderHenderson Heheh. Good night!

9 hours later…
12:28 PM
For closure:
For deletion:

12:40 PM
3

Well the answer you gave here is completely correct.

12:57 PM
Duplicate; most of the answers really miss the point. :\ Why is it not true that $f^{-1} = 1/f$?‭ - Fabian‭ 2020-07-05 09:21:50Z

1:17 PM
RH-related stuff to be deleted: 3740504

3 hours later…
4:01 PM
This was reposted after the first post was closed: math.stackexchange.com/q/3745730/321264

5 hours later…
8:44 PM
Good evening...for all users.
I have this question:
0

Supposing to have these integrals, for example, $$\int\limits_{-\infty}^{+\infty}\frac{dx}{(x^2+1)^2}=\frac12\left(\arctan x+\frac{x}{1+x^2}\right)\tag 1$$ $$\int\limits_{0}^{+\infty}\frac{x^2}{x^4+1}dx=\sqrt{2}\pi/4 \tag 2$$ $$\int\limits_{0}^{2\pi}\frac{1}{2\cos x+5}dx=\cdots \tag 3$$ They can ...

What more can I do to reopen my question? I hope it's clearer.

@Sebastiano Do you want us to do something about that question?

@XanderHenderson I am interested in whether there is a bottom-up order of solution, i.e. whether an integral cannot be solved by classical methods when resorting to complex analysis and what needs to be done?

@Sebastiano This room is is meant to help users coordinate action on questions which may need to be closed or reopened, deleted or undelete, or edited. If you are asking us to take one of those actions, please explain.

@In other words, when I can't solve an integral I solve it with numerical methods? With complex analysis, can integrals always be solved in real variables?
@XanderHenderson My question is actually CLOSED.

If you are simply looking for feedback on your question, you might have better luck in the room "Constructive Feedbadk":

### Constructive Feedback

@Sebastiano No.

8:51 PM
@XanderHenderson I see this now:

@Sebastiano Yes, I see that. Personally, I think that it should have been closed. It is too broad (maybe try to narrow down on a specific class of functions...?), and lacking in details (what do you mean by "the usual mode"?).
2

@XanderHenderson With integrations for substituting or parts, or rational functions.

@Sebastiano What action are you asking people in this room to take? If you are not asking us to take some action, please seek advice in the room "Constructive Feedback", to which I linked above.

@XanderHenderson I thought you could ask for advice in this room and I didn't think it was the wrong one. Anyway, I'll take your advice and thank you very much.