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1 hour later…
5:46 AM
 
 
2 hours later…
9:09 AM
[ SmokeDetector | MS ] Few unique characters in body, no whitespace in body, no whitespace in title, potentially bad keyword in body (259): dsadasdsaddsadasdsaddsadasdsad ✏️ by Iustin Ouatu on math.SE
[ SmokeDetector | MS ] Few unique characters in body, no whitespace in body, no whitespace in title, potentially bad keyword in body (259): dsadasdsaddsadasdsaddsadasdsaddsadasdsaddsadasdsad ✏️ by Iustin Ouatu on math.SE
 
 
4 hours later…
1:27 PM
1 message moved to Sandbox
Apr 29 at 18:55, by user21820
Just wrong answer because "All provable statements are true" is false...
^^ needs one more delete-vote, if anyone has a spare. =)
 
@user21820 I still have a lot of them left.
 
@JoséCarlosSantos Ooh that's great thanks!
 
1:48 PM
This post looks like a big mess, and note that it has had 76 revisions.
 
@user21820 That particular question has been the topic of at least one meta post, also.
The asker is clearly quite confused.
 
Note also that the author keeps linking to his chat-room called "new discovery riemann-like sum".
Which, as we all know, is a common symptom...
 
0
Q: Riemann Zeta improper integral

Shekhar SumanCan i apply residue theorem or numerical integration to prove that $\int_{-\infty}^{\infty}$log |$\zeta (1/2+it)$|/(1+$4t^2$) dt =0. where $\zeta$ is the Riemann Zeta function

A PSQ with an up vote probably from the answerer
 
 
2 hours later…
4:56 PM
@user12986714: Thanks for posting your requests!
 
5:15 PM
@user21820 No I don't know, but it just looks like do my homework question and shows zero research...
 
Sorry I was referring to a different post, not any of your three.
Don't know why I thought it was one of yours, so I'm going to delete my totally useless comment.
1 message moved to ­Trash
 
5:32 PM
@rschwieb welcome to Covid bash 2020 pal
 
5:48 PM
D1, D2, D3.
D4, D5, D6.
D7, D8, D9.
C1, C2, C3.
C4, C5, C6.
 
 
1 hour later…
8:03 PM
@All Sorry about missing a number of days. Currently the site is in dire need of quality control. And... Stay healthy.
2
@amWhy Thanks for the vote of confidence (in the form of the invitation for me to become a co-owner of this room). I will continue to assist the effort here, but I think I'll pass. I am rather inexperience in managing chatrooms, and might unwittingly do some damage. I am practicing/tiptoeing in the Pearl Dive. May be later :-)
 
8:46 PM
[ SmokeDetector | MS ] Repeating characters in answer (81): Area of a trapezoid without the height by user786149 on math.SE
 
9:38 PM
Welcome @MattSamuel
 
Hi @skullpatrol, thanks.
 
how's life?
 
Suffused with work and children, you?
 
Still alive and kicking, thanks :-)
 
 
1 hour later…
11:19 PM
Guys just out of curiosity, why is amWhy suspended?
 
@Archer I don't see any suspension notice on the profile
 

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