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barlop
barlop
00:49
any idea why my sin graph looks funny?
user image
that is plotted in scilab
one one thing when x=90 i'd expect y=1 but it isn't quite there
 
11 hours later…
Glen_b
Glen_b
11:30
Because it's working in radians, not degrees, naturally. sin of 90 radians is just below 0.9
user image
You've gone through 57.3 cycles in your plot. Click my plot to see the details. I have stretched the horizontal axis
To convert degrees to radians multiply by pi/180
so 90 degrees is pi/2 radians, for example
ankii
ankii
11:50
Hey @Glen!
Thanks for all the help and intriguing questions which made me lookup some good questions on the site and wikipedia etc.
It was for a assignment in a course of ML and I am not looking for deeper concepts in statistics.
 
5 hours later…
barlop
barlop
16:24
@Glen_b thanks.. any idea how to get the x and y axis to intersect at x=y=0?
whuber
whuber
16:42
@barlop The axes always intersect at the origin ;-). If you would like to depict them, consider issuing the post-plotting commands abline(h=0) and abline(v=0).
 
1 hour later…
Tim
Tim
17:47
"ML bootcamps" ;) medium.com/@gantlaborde/siraj-rival-no-thanks-fe23092ecd20?
barlop
barlop
18:38
@whuber is that matlab? or octave? I have scilab and get "Undefined variable: abline"
whuber
whuber
19:14
@barlop It's R (which is what @glen_b was using--I didn't notice you used something else). abline draws lines across the plot region. This is a basic operation in any graphics environment, so I'm sure you'll know how to do it.
 
2 hours later…
TreFox
TreFox
21:05
Can anyone do a sanity-check for me rq? If a distribution gives a certain probability p(x) for each pixel x in an image, the probability of generating the whole image is the product of p(x) over every pixel in the image?

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