Welcome Bob. Please take our tour and refer to the How to Ask section of the help center. Um, there's a huge variety of tanks - none of which have been tested for sustained high-G functioning. Not certain what sort of answer you're expecting - pretty much all we could give you is guesses - and a very wide range of guesses at that. Could you please give us much more detail, and if the suspension/equipment has been upgraded.

Hello @BobPerson, welcome to Worldbuilding. That comment by the automated Community BOT tells us that your question (Q) doesn't pass Stack Exchange's basic requirements for a good Q. I suspect the problems were (a) you're allowed ot ask only one Q and (b) the use of "gs," which isn't a computer-friendly abbreviation. I've edited your Q to solve the problems. However, please note that there's no science behind what you're asking because nobody has had to worry about the issue, so the closest we might come is if we can find an example of someone dropping a tank out of an airplane.

It may help to define what sort of damage you want. "Crushed like a tin can" is a very specific level of damage, but I expect the tank will become unusable far before that as most systems are not designed to gees (e.x. if a connector becomes unplugged because of the weight of the wire connected to it, the tank may become unusable). Is the extreme of "crushed like a tin can" the actual goal you seek, or are you looking for something more like a mobility kill?

Come to that, the people crewing the tanks aren't much going to enjoy anything above normal, nor tolerate it for long.

@CortAmmon One of my edits was to remove a second question that asked at what point it would be unable to move. I picked the more objective question, but you're right, it might not be what the OP needs.

Thanks for the updates. I'm just looking for an estimate for any sort of tank (un-upgraded), since like the comments mentioned there isn't really any research on this. I was more curious how much it would take to reach the extreme case (crushing the entire tank), even a higher-end estimate would work.

A typical car crusher generates 2,000 psi. The problem is that there's no direct conversion between psi and the "force of gravity" because they're two different types of force (there's an argument that gravity isn't even a force). However, if F=PSIArea and F=MAcc then Acc = PSIArea/M and if an average car is 1800kg and the area is the sidewalls of said car (abt 4.6 m^2 twice or 9.2 m^2) then Acc=10.2 m/s (1.04G) *and there's the problem because they are different forces and the equivalence doesn't make sense. Interesting question!

BTW, I didn't check the units of those two measurements of Force. I might be off by miles because of that.

I think this question would have a better chance of being asked on the WarThunder forums..

@JBH wrong calculation. If you want an estimate by way of car crushers, guess the weight of the part of the car above some arbitrary point e.g. halfway from the bottom to the bottom of the windows, and the cross-sectional area of the halfway point (including air space) in square inches. Multiply by A x 2000 PSI. Divide by weight of top part. Result is in g factor (upper bound) at which the top part will crush the bottom part.

I get order of 1000 to 10000, which is obviously too much for a regular car, but upper bounds are what they are.

@gs Thanks for the insight! I suspected (ok, I knew...) something was wrong when the crushing force of the car looked an awful lot like standard gravity.

can you narrow down tank a bit, ww1, modern, ect.

‘pick any one you want’. This actually probably matters a whole lot more than you might think, and it’s a much much wider range of vehicles than you probably realize, with a lot of strange edge cases (see for example the M56 Scorpion, Stridsvagn 103, Obiekt 279, or Versuchsträger).

As a useful rule of thumb, this question is approximately equal to "how many tanks could you carefully stack on top of each other before the bottom one gets squished?", assuming the loads are distributed very very evenly. I don't know the answer to that at all, but it's an interesting image.

@N.Virgo Actually, that is not going to give you an accurate model since stacking tanks creates specific points of higher strain than others whereas gravity will be much more uniform; so, a stack of tanks should crush with less weight than a single tank under higher gravity.