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To factorize N = p * q with p < q e (p-2) mod 9 = 0
It does so: N=209 solve:
[(h+1)^2]*[(2*h+2)^2/2-1] = X*(209-4-2*n+2*(p-2)),(h+1)/3=(k+1)/6 ,p^2+n*p=209,
h+1+k+1=(209-4-2*n+2*(p-2)),h,X,n,k
->
h = (2 (-209 + 99 p + 2 p^2))/(3 p)
solve:
[(h+1)^2]*[(2*h+2)^2/2...