Please show a schematic diagram (not a breadboard wiring diagram). Otherwise we all have to guess what you have done. Thanks.

I fixed the capitalisation and punctuation.

Check GND is connected with each and every IC. Same for Vcc. With bigger breadboards, chances are you need to explicitly wire "the power rails" - between "stripes", quite possibly between halves with what looks one long stripe. Same colour does not connect. An uninterrupted line immediately besides a row of holes should indicate interconnection.

@Transistor i added the schematic

@greybeard should i just remove the power rails in between? And just have a power rail in the outer portion? But i guess it would be difficult to connect gnd and vcc to the ic. But it's the ic im having trouble with since when i connect the vcc of the ic in the positive power rail and connect it yo the upper power rail where the 5v battery is connected it just turn the led i connected to the dip switches in the first breadboard

Why a crooked photo instead of a screen grab? (Hit Prt-Scrn.)

@Noobielectrix Please see copy of your photo that I have added - links shown in green MAY be needed in SOME cases. Where a continuous red or blue line runs the whole width of the breadboard the power bus is usually continuous. In some cases it MAY not be. This is worth checking explicitly. || The question is answerable with only a little more input from you. I suggest that you look at the problem presentation as others see it and "fill in the gaps" . Is the psu sagging or ...? Do meter readings make sense of what you are seeing? Is there ohmic continuity across your whole power supply bus? .

You'll need to turn on the component designators (the names of the components, U1, U2, etc.) on the schematic otherwise we won't be able to discuss the circuit.

What logic family are you using? Regardless - some on board decoupling capacitors would be a really really really good idea.

Photo was good. Straightening it (which I did) takes minimal effort and helps perception of quality.

How much power supply current does your circuit draw, with or without the red link? What current is your power supply rated for?

@GrahamNye im using a breadboard module as power supply and is set in 5v, with a 2.8uA

Is yellow wire at bottom of power supply connected or a possible short?

@StainlessSteelRat its not connected

Your power supply module will certainly supply more than 2.8 uA. With a 9 V battery, it should be able to produce at least 200 mA. What logic family are you using? Original TTL (74xx) could easily require more current than the 9 V battery or power supply can supply. 74LSxx will require much less current, and 74HCxx, even less. Your photo doesn't show how you connect the battery to the supply module.

@PeterBennett im using 74lsxx, tho is precisely Sn74lsxx

If you are using 74LSxx parts, your switches should be connected between the input pins and Ground, or need a pull-down resistor of less than 1 K, as the inputs on 74LS parts can source 0.4 mA, and must be taken below 0.4 volts to be recognized as a Low. I don't see and power or Ground connections on several of the ICs.

I really don't know whats up now, i restarted making the breadboard and the xor gate is okay while my 7483 is not outputting the required output and basically when connected dims the LED i put

My guess is that the voltage across isn't enough to go through the adder ic... Idk im really at a stumped

(You will learn to keep extra conductive material/components out of the area of your experiments. One way or the other.) Seeing the upper stripe supplied from the left and the switches&LEDs on the right, its rails probably run the whole length.

You seem to be going without explicit measurement equipment. One indicator (say, blue LED+1 kΩ combo) at the left end of the middle stripe would be reassuring.

(Are you aware that the '83 is "centre pinned" (Vsupply₊ does not go to "the last pin", GND not to the opposite one)?)

@greybeard yes i am aware the vcc is in the 5th pin and the gnd is in the 12th pin

Question: will the adder 74ls83 run when inputs are floating like im just using the A0 and B0 adder to test if theres an output (which there is not) the gnd and vcc are connected properly.

Question: the adder B3 B2 B1 B0 are all on gnd if the switch is of the calculator is in add mode, and is 1010 in subtract mode, question is the 0 value i input in the adder ic for the 9s complement are in ground and the 1 is in the switch which is an spdt and is connected to gnd or vcc

A3 A2 A1 A0 are the switch input and when i test 0001 in add mode the output of the S0 in the adder should be 1 but in this it is (0)

Floating LS inputs are true / logical 1: you'd be adding 15+15+1 (carry in). I expect 15 + carry out. What does there is no output mean, how do you establish that? A blue LED from an LS output to ground may stay pretty dim; with TTL outputs, use LEDs to Vcc.

(I can't read the labels beside the ICs in the schematic. I may be able to guess -I'm unwilling to.)

I tested what you recommended, i put gnd to the inputs unused and left the outputs alone and used the A0 B0 adder and it worked the S0 output is 1 as i am adding 0+1, but the led dimmed as i tried the output into led with vcc into it it did not light up. It only worked with the led to gnd. I want to use the ouput S0 to connect to the other adder to complete the circuit but i think the signal is lost or unable to be read by the adder ic as the is dim when tested.

It only worked with the LED to gnd an LED+R to Vcc will light when connected to a low signal. Interpreting with true = high, lit <-> false, true <-> dark. If you want easy interpretation of LEDs as a logic signal monitor, use an appropriate driver or, with TTL, inverter. This should reduce the load to the signal monitored, too.

Just multitested the 9v Battery and it's in 6v, weird I bought this yesterday. The current is 2uA

This would not be applicable for this right? As it is when connected to the power module 5v mode it output 3.9V and much less current

I think the power supply was the problem..... I switched to an outlet power brick and it worked all ouputs were high,,,... I feel dumb....

I meant there was no dimmed light

(It is nice to have a current limited supply when experimenting - don't know how "defensive" that "breadboard logic PS module" is. I'd plug it directly into the stripe with greatest power hunger/most logic ICs, btw.)

The current consumption cannot be 2uA (micro = 1/1000000). A single 74ls83 takes some mA (milli = 1/1000) already. A 9V block has 200 mAh (cheap ones) to 1000 mAh (lithium) and will last therefore only a few hours.

I can't fathom how much thankful i am for all y'all response. Im gonna make this project now and hopefully it will go well. There might be problems i might encounter in the making of it i might asked here again about it