Doubt on double integral; do you want check it, please?
http://math.stackexchange.com/questions/1579690/the-value-of-double-integral
http://math.stackexchange.com/questions/1579690/the-value-of-double-integral
Given double integral is :
$$\int _0^1\int _0^{\frac{1}{x}}\frac{x}{1+y^2}\:dxdy$$
My attempt :
We can't solve since variable $x$ can't remove by limits, but if we change order of integration, then
$$\int _0^1\int _0^{\frac{1}{x}}\frac{x}{1+y^2}\:dydx$$
$$\implies\int _0^1\int _0^{\frac{...
