@V2Blast to be fair.... it is not like the other girls don't have their own fair share of issues. Blossom has extreme OCD tendencies, Buttercup is basically Dash 2.0 and has her share of issues (it is pretty clear in some episodes that she acts over the top because she needs that to keep believing she is good, otherwise she would get depressed). Bubbles is just weird in her own way...
it is just that Bliss ones are far more extreme and pretty stereotypical.
As many user have already noticed, the network is apparently undergoing some "Ads testing" aimed at evaluating the various available alternatives for publishing advertisement to the network.
It is my understanding that the test has been silently extended to many sites in the network (The Workpla...
Anyone got a moment for a Java question? (it's for my RPG "Random Dungeon" App)? How do I convert an Integer to 2 significant figures? e.g. 1234 -> 1200
Bear in mind that on a non-RISC CPU (which x86 processors generally are) the log function, no matter the base, is going to be very slow, even if there's an opcode for it (which there is, IIRC). Dividing an Integer a bunch of times is almost always going to be faster.
> Bug#69420: Rounding the number 1000 to 2 significant digits takes 15 µs fewer than Rounding the number 2000, and because we are working with a real-time embedded system, this is causing us to have to manually adjust timings to keep the pacemaker operating at a consistent frequency. Please fix this discrepancy.
what is the type of area increase granted by incrementing each side of a square by one unit, one side at a time? Feels logarithmic.
ex. Square of sides of unit length 1. step 1. increase one side so that we have a 2,1 rectangle. step 2. increase the short side so that we have a 2 square. step 3. increase one side so that we have a 3,2 rectangle. etc.
It's a normal Quadratic Growth curve, just slower than usual. The formula to express the area at iteration X (X0 = 1,1; X1 = 1,2; X2 = 2,2; X3 = 2,3; X4 = 3,3, ...) is
if x MOD 2 == 0 y = (x/2)^2 else y = ((x+1)/2)^2 + ((x+1)/2)
@goodguy5 Well, that's not quite the definition of the derivative. The derivative is definitely linear, because the rate of acceleration is approximately 1/2, because the rate of growth is 1,2,2,3,3,4,4,5,5,6,6,7,7,8,8,9,9,...
I say approximately because it's 0 on even steps and 1 on odd steps.
Calculating rate of growth as a function of the previous step is technically valid, but it's not used very often.
Like, under that definition, a line of 0,1,2,3,4,5,6,7,8,9,10,... Has a rate of Growth of ∞%, 100%, 50%, 33%, 25%, 16%, 14%, 12%, 11%, 10%, ...
For a straight line. Mathematically valid, but weird to think about.
@goodguy5 Fair enough. In that case, it's 100%, 100%, 50%, 50%, 33%, 33%, 25%, 25%, 20%, 20%, ..., which is the same regression (A*1/x) just larger than before. I'm pretty sure all curves of the form x^y, where y is a constant, will exhibit that behavior in some form or another.