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HNQ
6:44 AM
2
Q: How is time measured in particle experiments?

Sohail KhanI was reading about the half life measurements and was curious to understand the experimental setups that allows so minute measurements to be captured. Specifically looking into half life of Higgs boson. I am looking to understand one example method of measuring Higgs boson half life. Please feel...

 
 
5 hours later…
HNQ
11:26 AM
4
Q: Incoming and Outgoing Waves in Quantum Field Theory

Daniel WatersI apologize if this seems like a simple question, but I have been agonizing over it recently. In nonrelativistic quantum mechanics, a plane wave of the form $e^{\pm i\vec p\cdot \vec x}$ is called outgoing (incoming for the minus sign). However, in QFT (particularly in the context of the mode exp...

 
 
4 hours later…
HNQ
3:42 PM
1
Q: Why are virtual photons never observed, if QFT predicts them as a possible outcome of experiments?

Ryder RudeConsider the Dyson series of the S matrix of Quantum Electrodynamics. The second term in this series predicts non-zero probability amplitudes of observing photons that are off-shell. For an incoming state of a positron and an electron, the second term of the series gives a non-zero amplitude that...

 
 
3 hours later…
HNQ
6:43 PM
2
Q: Different interpretations of (bundle-theoretic) gauge transformations

szantagThe physical minimal coupling procedure is usually expressed mathematically in the language of fibre bundles where instead of local presentations we deal with global objects - gauge fields are connections on a principal bundle with structure group of symmetries, matter fields are sections of a bu...

 
 
3 hours later…
HNQ
9:43 PM
2
Q: Infinitesimally small time intervals

Fadeel KhanWhen saying that in a small time interval $dt$, the velocity has changed by $d\vec v$, and so the acceleration $\vec a$ is $d\vec v/dt$, are we not assuming that $\vec a$ is constant in that small interval $dt$, otherwise considering a change in acceleration $d\vec a$, the expression should have ...

4
Q: Why do we say the universe is isotropic when we are clearly moving w.r.t the CMB?

AllureModern cosmology is built on the Friedmann equations, which in turn relies on isotropy - the idea that the universe looks the same in every direction - as a fundamental assumption. However, there's a very noticeable dipole in the CMB, the standard interpretation of which is that we are moving w.r...

 

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