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Aastha Choudhary
Aastha Choudhary
05:18
Now for u′(x)≤0 to be true for some x, u"(x)<0 for some x∈[0,∞) as u′(0)>0. How you concluded this line?
@DevanshBhardwaj
For u''(x)<=0 implies u'(x) is strictly decreasing and in an alter way u'(x) not strictly decreasing implies u''(x) is not <=0.
Devansh Bhardwaj
Devansh Bhardwaj
05:37
@AasthaChoudhary $\int_0^xu"(x)\,dx=u'(x)-u(0)$. So u" must have been negative somewhere for $u'(x)-u(0)<0$ or $u'(x)<u(0)$.
sorry u'(x)-u'(0)
Aastha Choudhary
Aastha Choudhary
06:02
Give me some time.I am not getting things clearly.

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