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Devansh Bhardwaj
14:11
@Aasthachoudhary you can come here
Aastha Choudhary
Hi!
Please elaborate that portion.
Devansh Bhardwaj
Yeah
So I am not really fast at mathjax and as I too am preparing for entrances, I do not have too much time to type it, yet I will try; please follow with pen-paper or something:)
Aastha Choudhary
That's completely fine.
Devansh Bhardwaj
First of all it is helpful to notice that 1/2+1/3=5/6. 5/6+1/7=41/42. In entrance environment that will lead you to answer already
Aastha Choudhary
yes, that way I also observed.
Devansh Bhardwaj
14:23
Secondly, for my formula, it was clear till 1+1/a_n right?
that one term
Aastha Choudhary
yes upto that only!
Devansh Bhardwaj
now $a_{n}-1$ would give plainly the fraction $\frac{1}{a_{n-1}+\frac{1}{a_{n-1}-1}}$
and this is the denominator
Aastha Choudhary
yes
Devansh Bhardwaj
there would be a fraction upon a fraction. which can be moved up
Aastha Choudhary
sorry?
This is kinda continued fraction but not actually continued. Isn't?
Devansh Bhardwaj
14:28
to give something like $a_{n}+a_{n-1} $ in denominator
yeah
it is
continued
Aastha Choudhary
okay!
simple typing is fine
mathjax is time consuming.
Devansh Bhardwaj
see in the fraction I have shown a_(n-1) in denominator. Applying the same formula as that to a_n - 1 gives a fraction upon a fraction
Aastha Choudhary
yes basically like continued fraction.
Devansh Bhardwaj
yeah so it leads to $a_{n+1}=1+\frac{1}{a_n+a_{n-1}...a_1+\frac{1}{a_1-1}}$
Aastha Choudhary
yes..
Devansh Bhardwaj
14:33
so adding this to sigma a_n gives the required formula after some manipulations
I did not try anything further, though that formula seems helpful
Aastha Choudhary
okay! So this was the usage of the given condition again and again!
yeah! Thanks for your efforts btw what exams are you preparing for?
Devansh Bhardwaj
yeah. I do not know whether you were taught number theory in college, but I don't think students are taught except in iisc or isi
I am preparing for IISc undergrad entrance KVPY
or maybe CMI or ISI
Aastha Choudhary
Sadly, I am not shortlisted for ISI :(
Devansh Bhardwaj
And JEE Advanced
@AasthaChoudhary woops
CMI is better
Aastha Choudhary
No! they are not taught!
Devansh Bhardwaj
14:37
yeah, So this was the formula only
Aastha Choudhary
@DevanshBhardwaj undoubtedly its better.
Devansh Bhardwaj
@AasthaChoudhary Well try cmi then
Aastha Choudhary
Sure! Good luck!
Devansh Bhardwaj
CMI undergrads have went to PhD in Princeton (9 students) and princeton is best for math PhD
We get to attend IAS lectures
Aastha Choudhary
Wow IAS lectures!
Devansh Bhardwaj
14:38
@AasthaChoudhary Thanks. I am in last year so I have 1 year to prepare
Aastha Choudhary
That's great!
Devansh Bhardwaj
I am referring to Institute of Advanced Study, that would be clear:)
Aastha Choudhary
yeah!
I am not aware of advanced study
Devansh Bhardwaj
Thanks for giving your time; I wanted to talk about that for so along
@AasthaChoudhary what?
Aastha Choudhary
Institute of Advanced Study!
Devansh Bhardwaj
14:40
ias.edu
Aastha Choudhary
Thanks again :)
Devansh Bhardwaj
Welcome. I hope CMI does shortlist you:)
and again IISc is just as good for mathematics
Aastha Choudhary
Hopefully!
undoubtedly IISc is,let's see!
Devansh Bhardwaj
Im leaving this room undeleted, so if I happen to answer or comment again and you want to discuss, just ping me here
And are there not sources for MCQ solutions on internet? I think they are not really promoted on stackexchange.
@AasthaChoudhary You are welcome. Bye :)
1 hour later…
Aastha Choudhary
15:56
Bye!
:)
Asking for sources on internet for mcqs?
yeah! not promoted on stack.
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