04:10
@LinearChristmas I think the weak points is still in 4 (e.g. why does $P(\omega)^M$ mean the same thing in $M$ as is does in $V$)
Like you're saying "ZFC proves this countable transitive model of ZFC has a countable powerset and countable omega_1." Sure. Relativizing that to a countable transitive model M, M thinks "this countable transitive model of ZFC has a countable powerset and omega_1"... but why should "this countable transitive model" be M?
7 hours later…
11:49
I will try to evaluate point 4 in isolation; pretending not to know that contradictions eventually arise. It seems to me... that point 4 should hold in the stated form. This is due to the definition of relativisation, and due to the absoluteness of the concepts involved for (large enough) transitive $\in$-models. I will just say “absolute” from now on for brevity.
The formula $\varphi$ is of the form $\exists f\, \psi(f)$, so its $(M,\in)$-relativisation $\varphi^M$ is, by definition, $\exists f \in M\, \psi^M(f)$. Relativisation distributes nicely over conjunctions $\wedge$, so we must ge…
The formula $\varphi$ is of the form $\exists f\, \psi(f)$, so its $(M,\in)$-relativisation $\varphi^M$ is, by definition, $\exists f \in M\, \psi^M(f)$. Relativisation distributes nicely over conjunctions $\wedge$, so we must ge…
5 hours later…
16:30
@LinearChristmas No, same issue. P(omega)^M is not just some set... it's a definition in terms of the definition of M, whatever that is. dom(f)=P(omega)^M is a complicated abbreviation, not the statement that dom(f) = X where X is some set in M.
17:34
@spaceisdarkgreen I agree with you. I do admit I am still confused about "objects" and formulae for which we can prove a unique object exists for. But if what you say is true, I am struggling to see the usefulness of absoluteness results as a whole...
@spaceisdarkgreen That being said, why would relativising something twice in a row would be any different to relativising just once. In the end, $(M, \epsilon)$ will get down to atomic subformulae, and along the way, the quantifiers get bounded to $M$. If I have bounded them once, bounding them again must surely be equivalent? Even predicate logic equivalent (if there is an $\in$, anways). After all, $\forall x \in M\, \Psi$ is amounts to saying the same thing as $\forall x\, (x \in M \Rightarrow \Psi)$
Doubling that, we simply get $\forall x\, (x \in M \Rightarrow (x \in M \Rightarrow \Psi))$ which is equivalent to $\forall x\, (x \in M \Rightarrow \Psi)$. Right?
Of course, we would go deep inside $\Psi$ as well, but all we are really changing is the quantifier business when relativising to $(M, \in)$.
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I would understand, of course, from a meta-theoretic model theory perspective... Say we have a set object, let's say it's $S$. If we interpret it in a model, we would get $S^M$. Say that is again a set object (part of the original universe). So it too would have an interpretation in the model, $(S^M)^M$, which is not necessarily identical to $S^M$. But here we can say we are actually doing formal syntactical things...
I would understand, of course, from a meta-theoretic model theory perspective... Say we have a set object, let's say it's $S$. If we interpret it in a model, we would get $S^M$. Say that is again a set object (part of the original universe). So it too would have an interpretation in the model, $(S^M)^M$, which is not necessarily identical to $S^M$. But here we can say we are actually doing formal syntactical things...
18:19
@LinearChristmas Well, like for instance if you let M be the minimal transitive model of ZFC, you can't relativize that concept to M since there is no minimal transitive model of ZFC in M. Far as I can tell, same kind of thing happens when you try to use fragments and reflection (i.e. the minimal V_alpha satisfying some fragment), or formal introduction of a constant (as in ZFC+)
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