I don't mean to be harsh or mean, but I think your question is unclear in many ways. It's not clear to me what exactly is that you are asking and what you are even referring to. If you have multiple questions you should do multiple posts.

@KarimChahine Did you downvote my question? If so, thank you for also providing an explanation and being nice to me! I really appreciate the kindness shown by you in providing a reason you downvoted my question. I am curious: is a left polarized photon the opposite color of a right polarized photon of the same color? If so, which direction do you mean by LEFT POLARIZED?

I am still trying to figure what the 3 other base colors are in your scheme.

@KarimChahine Do you use exponential functions to describe polarized light? I used $e^{it}$ for LEFT polarized. Did I do it BACKWARDS to you?

I didn't downvote your post. Color of light has to do with its wavelength, not its polarization. Note that left polarization refers to circular polarization and that it's just a matter of definition. You can find more information here: en.wikipedia.org/wiki/Circular_polarization

@KarimChahine Thank you so much! I upvoted your comment =) Cheers!

@KarimChahine You said "Color of light has to do with its wavelength, not its polarization" What wavelength is GREEN light, and what color is the opposite of GREEN?

It's easy to find online pictures of colors and their corresponding wavelengths. Note that colors are on a continuous spectrum, there's no such thing as a well defined green, but only a well define wavelength. There's no physical definition of opposite colors, I don't know what you are referring to. I believe it's just a human thing.

"I claim that there are 6 base colors". What are the 3 other ones?

@MattCalhoun There are no three base colours. That's just how a computer displays colours. Colours are different wavelengths on the continuous electromagnetic spectrum. Green for example could be 515nm. (more wavelengths than one are different shades of green). Polarisation has nothing to do with the colour, only the wavelength.