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01:17
@bobble apparently not
apparently. and I have to leave soon, so it would be too late.
hmm
i'd offer but i'm not in physics yet
 
2 hours later…
03:11
@bobble sorry for the delay - available now but it's likely too late
I'm here, maybe you can point me in the right direction
I'll pull up the problem
Okay, so there's a stupidly complicated set-up
On table, cart is attached to spring and is in Simple Harmonic Motion
cart is also attached to a sting which extends off table and is attached to a bucket
the bucket has a pencil attached to it
There is 0.5kg in the bucket and 9.5kg in the cart
And now the problem starts
A paper is placed such that when everything is at rest, and there are no weights in bucket or cart, the pencil is at its top
When the weights are in, and the cart is in SHM, and the paper is moved horizontally at a constant rate, the pencil draws a sine curve with amplitude of 2cm, with top 3cm from top of paper
so now: at what speed did the paper move horizontally?
(period of 8cm)
wow you weren't kidding about "stupidly complicated setup"
I am.. um.. very stuck
oops, cart is attached to "string" off the table, typo
can you provide any pointers at all?
okay so
first: draw a picture. make sure you can see what's going on.
there will be slight lag as I draw picture
03:18
pictures always help in my experience
i've got a picture that i've drawn
it's not good but it works
please enjoy the artistic masterpiece
ooh pretty
should I draw arrows on it for forces?
that's the usual second step!
@Deusovi considerably better than this "absolutely garbage picture"
(no offense ofc)
(image editor is being annoying)
03:21
to be fair, for that other one i was literally just drawing "a point on two curves"
Assuming that the cart is past the halfway point
arrows not to scale
ooh yay fancy shadows on the words
I don't see anywhere where they explicitly say "no friction between cart and table", but I'm assuming it
yeah it's probably a cart because it rolls
So, one thing: for the cart, F_norm = F_grav, since the cart isn't moving vertically
03:26
plus friction would mean that it's not SHM because the oscillations would get smaller and smaller
true!
so. what relates the horizontal speed of the paper to anything else?
horizontal speed of cart = vertical speed of pencil, since they're attached through string
so amplitude of pencil (2cm) is amplitude of cart's SHM
that's true but not the question i asked
oh I read "cart"
03:28
though starting from there is perfectly fine - we can do that too
horizontal speed of paper is related to period?
because it moves 8cm / period
sounds good to me! it's the only thing i see that's related to the horizontal speed of the paper
so now we need to find period
yeah, that seems like a more approachable goal, and would let us use SHM stuff
how does the 0.5kg in the bucket affect the SHM of the cart?
since then there is a force from something that's not the spring
that was what I was getting stuck on
I do have T = 2pi * sqrt(m/k), but I don't know T or k, and I'm not sure what mass to use for m - cart mass? cart mass + bucket mass? something else?
03:32
well, let's figure it out!
we can't just use that equation directly here - it's not just a single object on a spring
(though it may be useful later)
something that might help: when the system is at rest, the pencil is 5cm below where it was without any extra weights
yep, that's very good to know
If pencil is 5cm below, that means cart's middle position is 5cm out
So the starting U_s would have x increase by 5cm
and the bucket would have U_g decrease because h decreases by 5cm
does any of this help?
U is... potential energy?
yes, U_s = spring potential energy, U_g = gravitational potential energy
03:36
ah alright
that's what my teacher uses
I have no idea why
right, i think that's what we used back when i took physics too, but just forgot the variable name
well obviously it's u for "uotential"
unintentionally confusing?
alternatively: because P stands for "momentum"
Makes perfect sense
03:39
anyway! hooke's law says that the restoring force is proportional to the amount of displacement
@Deusovi why is that so funny lol
F_spring = -kx
right
so can we calculate that spring constant
so this will increase because x increase by 5cm
and so F_tens will increase by same amount (to keep at rest)
and this will be the same amount that F_grav for bucket increases, to keep everything nice and at rest
hey wait, that's useful!
yep, looks useful to me!
03:42
what's the initial mass? 0kg? are we assuming that pencil + bucket weighs nothing?
no idea what the initial mass is -- let's give it a variable
from problem:
and hope it works out nicely
> The thread passes
over an ideal pulley and supports a very light bucket. She
attaches a pencil to the bucket; the marking end of the pencil is
in light contact with a piece of paper.
ah, "very light bucket" likely means we should approximate it by ignoring its mass
03:44
Also, they say mass of cart = M and mass of bucket = m, so let's use those variables
sounds good to me
F_grav = mg
F_tens = -F_grav = -mg
F_spring = F_tens = -mg
wait, did I mess up some signs?
there, fixed it, right?
you know directions, so let's talk in terms of absolute values
|F_spring| = |mg| = |kx|
|F_spring| = |F_tens| = |F_grav| = mg
and m/g/k are all positive, so you know mg=kx (where x is amount of displacement to the right)
03:46
I will say x without any mass = x_0, x with mass is x_f
because they are different
well where are you measuring position from
where is your 0-mark
oh wait x_0 would just be 0, right?
if x is "displacement from starting position", then yeah
which seems reasonable to me
so then k = mg/x, and all those are known (m = 0.5kg, g = 10m/s/s, x = 0.05m), but we don't plug in yet
why not?
03:49
because my teacher says don't plug in? are we allowed to?
would it be okay to plug in now?
it wouldn't produce a false statement, would it?
no, guess not
it may be more convenient not to plug in and to keep working with variables
but it wouldn't make a false statement if you do
the only potential issue with plugging in numbers early is building up rounding error as you go
just in case it's not convenient: k = mg/x = 0.5kg * 10m/s/s / 0.05m = 100N/m
hey look the numbers are nice so we don't have to worry about rounding error
almost like this is a problem designed for physics homework or something
3
03:51
oh wait, it is
can we use T = 2pi * sqrt(m/k) now? or is it still invalid?
when is that equation valid?
when we are in SHM
which, I guess we can decide to be in now?
not just that
when no external forces? but that's also required by SHM, I think
03:53
depends on what you mean by "external forces"
I'm still confused by SHM in general, not entirely sure how I got so far in the homework
(to clarify: i'm thinking through this as we speak. i'm not convinced we can just directly apply that formula here, though it's possible it will still work)
I think SHM is valid if force is proportional to position, which it still would be, since the bucket pull is constant
I think
SHM just means you're in a situation where the restoring force is proportional to the distance from a certain position
and that produces a sinusoid, because the solution to the differential equation " f′′(x) = k·f(x) " gives you a sine wave
(which you may or may not be familiar with, but hopefully you vaguely understand what i'm saying)
(for negative k)
03:58
(yes)
the made-up scenario says this:
> Dominique’s precalculus teacher asks her to make an exact
graph of y = sin x using a real-life process.
(well something something complex numbers. i think.)
So I assumed that the cart would be in SHM because that would make a sine graph
makes sense
alright yeah pretty sure it will work
because without the mass in the bucket, force is proportional to the distance
if we add a constant force, that'll add a constant distance, but the result will still be proportional
okay, so T = 2pi * sqrt(m/k). What is m?
04:03
m is the mass that the spring is moving
how much mass is the spring moving?
so M + m
sounds good to me
T = 2pi * sqrt((M + m)/k)
T / 2pi = sqrt((M + m)/k)
T^2 / 4pi^2 = (M + m)/k
k * T^2 / 4pi^2 = M + m
oh wait why did I do that?
silly bobble
T = 2pi * sqrt((9.5kg + 0.5kg) / 100N/m)
T = 2pi * sqrt(10kg / 100N/m)
T = 2pi * sqrt(10s^2)
T = 2pi * sqrt(10) s
progress!
horizontal speed of paper = v, according to problem
v = 0.08m / T
v = 0.08m / (2pi * sqrt(10))s
v = (0.004 * sqrt(10) / pi) m/s
wait, is that it?
04:09
seems good to me
let's double-check -- did you use all the information? if not, is there a reason you didn't?
yay, thanks!
I'm pretty sure I used everything
mass of cart, mass of bucket
original height of pencil
new middle height of pencil
the only thing you used the heights for was finding out the center position of the pencil
so it wouldn't matter if they were, say, 4 and 1 instead of 2 and 3
does that make sense?
period in centimeters
yes
the fact that it's SHM, the set-up in general
by "does that make sense" i don't just mean "do you understand the words i'm saying" but "does it make sense in the context of the problem, that if you changed those heights the answer wouldn't change"
yes, that makes sense. all we cared about was how much the cart moved out, which was determined by how much the pencil moved down
04:14
right, the amplitude shouldn't be a factor in it - shm's period doesn't care about amplitude
so yeah that seems to be everything, looks good to me
Thank you so much, Deusovi!
no problem!
 
2 hours later…
06:09
@bobble Okay lol
 
15 hours later…
21:22
@bobble you made a math error here :) Seriously, me, 10/100 does NOT equal 10
21:36
@Deusovi, are you available now? I have quick further question on the same physics problem. Sorry for poking :)

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