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is the following interpretation, of the deduction-theorem, correct?
No. What you write is
If $T \cup \{P\} \vdash Q$, then if $T \vdash P$, then $T \vdash Q$.
This is the same as saying
(1) If $T \cup \{P\} \vdash Q$, then $T \nvdash P$ or $T \vdash Q$.
But this is not equivalent to
(2) If...