« first day (507 days earlier)      last day (830 days later) » 

3:17 AM
@Anonymous yeah... I don't really know...
 
3:47 AM
 
4:23 AM
"One "insight" is all it takes"
- Me, 2022 😎
@Spectre I do. Quite often, in fact.
Not everyone who gives JEE wants to become an engineer, there're a couple of "JEE aspirants" who want to become scientists :/
But yeah, IISc's are most probably a better option.
@Spectre Kind of rare, if you ask me :/
@Spectre Don't have bro 🙂
 
 
1 hour later…
5:31 AM
Hemlo gaiz.
Ze seintest here 😎
So, assume that for some messed up reason, you're making something in python and speaking of randomization, the only function you have is a function that is capable of giving just 0 and 1 as it's outputs.
But you need a function that gives a random natural number from 1 to any number you want.
That's where my program comes in handy 😎
Here's the code
#Program to give out a random natural number between two given natural numbers by only randomizing between 0 and 1.

import random

def randomize(a):
    p1 = 1
    p2 = a
    while (p1 < p2):
        d = p2-p1+1
        if (d%2 == 0):
            r = random.randint(0,1)
            if (r == 0):
                p2 = p1+d/2-1
            else:
                p1 = p1+d/2
        else:
            r1 = random.randint(0,1)
            r2 = random.randint(0,1)
            if (r1 == 0):
                if (r2 == 0):
It basically uses the random.randint() function only to give a random 0 or 1 and based on that, gives a random natural number between 1 and the user's input
This version of the program gives 10 outputs.
Now, if any of you is interested, here's a small demo of how it works.
Let's say that the user enters $8$.
Now, the program will use the random.randint() function to give a 0 or 1.
Let's say that it gives a 0, so we choose the first half of 8...1 to 4.
The next time, let's say that it gives a 1, so we choose the second half...3 to 4.
Now let's say that it chooses 1, so we get the second half...aka 4, and that's it, the program will end and return 4.
In case of odd numbers, there's a slight problem. The probability that the program's output is the middle number $\left(\dfrac{n+1}{2}\right)$ is much more than any of the other numbers.
Now if our entered number is, say, 7.
then it randomizes between 0 and 1 twice...let's say that the outputs are 0 and 0 respectively.
first, it divides 7 into three parts...1 to 3, 4, and 5 to 7.
since the first output is zero, we work with two of the three parts...1 to 3, 4.
The second output is 0 too, so we work with 1 to 3. Now 3 is odd again. so the program will randomize between 0 and 1 twice again..let's say that we get 1 and 0 this time. the three parts are 1, 2 and 3. since we get 1, it means we're working with the two parts : 2,3. The next random number we got was 0, so our final output is 2.
 
6:05 AM
itna sarcasm
xd
@RajdeepSindhu too lazy to read through it 💀(for now)
 
6:24 AM
@RajdeepSindhu (Spectre claps) 👏
 
Friends this problem 🙂
 
@Anonymous is that a PRMO problem??
 
Some sort of telescoping it mustb e
 
@Spectre not sure
 
@Anonymous Okay whatever... I'll try
Btw @Anonymous I have a small doubt regarding the website
Do you guys encounter timeout errors while messaging these days? Also what about the "site can't be reached" thing??
I've been having it nowadays (not sure why; didn't try to remove anything to see if the problem is resolved)... even now!
It's a heck lot of itchy for me, a person who has almost 0 patience
 
6:30 AM
@Spectre Ummm.... I've not encountered any such issue.
 
@Anonymous Ohh... that's sussy then, in my case... thanks anyway
 
@Spectre Yeah
 
@Anonymous Why not state that this can be approximated to a difference of integrals??
Just guessing
 
Ah
 
@Spectre I'm not sure.
 
6:33 AM
I think you're on the right track
 
@Buraian It's almost the same case when it comes to approximating factorials
 
x^{-4/3}, consider this function's integral over the bounds [4,1,000,000]
And compare that with a rienman sum with step size x=1. I think it can work.
 
@Buraian Don't make me think about things that are out of my level 😂 ... I know nothing about Reimann sums
 
Basically you can approximate the integral as sum of rectangles
I didn't see factorial approximation thing xD
have to head out to IKEA for buying some furniture right now. I'll check this back later into the day
 
@Buraian Okie dookie!
@Buraian That's what I learnt at Brilliant about the backstory of integration... summing up areas of rectangles of infinitesimal areas
 
6:41 AM
@Spectre lol I'm noob for integrals.
 
@Anonymous Which grade/standard are you studying in??
I'm in grade 11
Prepping for entrance as well
 
@Spectre I'm also in 11th
 
@Anonymous Oh goodie!
 
@Anonymous try 2016 PRMO Q12 first
 
@Arjun I'll try too!! Thanks bud!
@Anonymous try the following code in Python
def integral(x2,x1):
return 3*(x2**(2/3) - x1**(2/3))/2
def summit():
sum_it = 0
for i in range(4, 1000001):
sum_it +=1/(i)**(1/3)
print(sum_it)
summit()
print(integral(1000000,4))
Ahh
The alignments aren't kept well
Nvm though
Anyway, I have 3 projects to complete and an exam to prep for and appear as a villain on the rank list 😈
So byee guyzzz
 
6:55 AM
@Spectre Can use sympy library to integrate easily.
 
@Arjun Luv it! Got me fired up! Thanks
 
@Arjun Hmm solved
 
@Anonymous Oh man, I know... but can't we just do a bit of written work as well? Learning comes there automatically :D
 
@Spectre Yeah
 
@Anonymous congrats!! 🎉
 
6:57 AM
@Spectre 🙂
 
@Anonymous That's why I did so... plus I needn't spend time learning to use that
Anyway byee
 
Byee
14996.545577951716
14996.220236850308
 
 
1 hour later…
8:17 AM
@Anonymous with/without the hint?
@Spectre same ;)
 
8:56 AM
@Arjun Without hint
 
oops chat.stackexchange.com/transcript/message/60220902#60220902 , this should be x^{-1/3} and it is actually less than the sum so it doesn't give a bound
 
 
2 hours later…
11:27 AM
Is it possible to find range of f(x) = x² - x³ "without Calculus"? Maybe using AM-GM inequality?
 
@Anonymous what about adding (x²) and ( -x³) graphs ,if you know graphs of both
 
@YashAgrawal Hmm
@YashAgrawal local maxima without derivative?
 
12:09 PM
@Anonymous Ok , so this is what I was able to come up with , see any line of type y = k would be cutting the whole graph at either 3 or 2 points , it would cut at 2 points only for y = 0 and one other y which is unknown , let it be y = k , so x² - x³ = k cubic should have 2 solutions only and condition of cubic to have repeated roots is give here :
4
Q: condition for a cubic to have a repeated root

user221707To write a condition for a cubic to have 2 real roots, can I equate the fuction to its derivative? I.e let $y=ax^3+bx^2+cx+d$ $\frac{dy}{dx}=3ax^2+2bx+c$ setting y and the derivative equal to 0 gives: $ax^3+bx^2+cx+d=0$ $3ax^2+2bx+c=0 \Rightarrow 3ax^2+2bx+c=ax^3+bx^2+cx+d$ however, this equati...

substituting the values , k that we would get would be 4/27 and this is essentially the ordinate of our maxima
So, solving x² - x³ = 4/27 would also give you x-coordinate of the maxima
though it's not a very good solution as even knowing that condition is a challenge itself
 
@YashAgrawal oh okay!
 
12:34 PM
@RajdeepSindhu whatya up to ._.
 
 
4 hours later…
4:54 PM
@Arjun Zukam hai, kaafi lambe time tak so raha tha 🙂
@Arjun I would have the same reaction 💀
@Spectre I faced the timeout errors before we had a wifi connection, on mobile data. Most probably due to a slow speed. How fast does fast.com say your connection is?
I thought you were in 12th 💀
Hemlo, fellow 11th grader 🙂
@Spectre You can use the "fixed font" button to the right of the textbox for that.
 
@RajdeepSindhu omicron?
@RajdeepSindhu 97 ;)
 
5:58 PM
@Arjun 💀
@Arjun mostly 30 😎
Bhoiya aap ki internet speed itni hai fir bhi fortnite khelte hue lag kyun 💀
Sounds pretty interesting.
 
@RajdeepSindhu PC?
 
Yeah, having a PC with low specs explains why you would be getting low FPS but you were lagging in my game too ._.
That usually indicates network issues, or a high ping or something.
 
@RajdeepSindhu ping around 10
 
I'm getting unstable af FPS nowadays 🙂
It's 70 fps one moment and as soon as I see an enemy, bam, 30..they pull out their gun, bam, 15, they start shooting..bam, 8. I start building...still 8 🤡
Bro wtf 💀
I get approx 80 ping every game. Middle east servers.
 
@RajdeepSindhu lmaoo
 
6:03 PM
I can still build well though (if my FPS allow me to 🤡)
The new shotguns are trash 🙂
New sniper is too.
The red dot MK-7 AR is pretty cool, though. And ofc, e-spiderman 😎
 
@RajdeepSindhu i don't get any of it
 
Alright so basically, there's this new sniper and it has some insane bullet drop. At medium range too, you have to aim the crosshair above someone's head so that when the bullet drops over the distance, it hits their head.
And the bullet is also slow af so you have to aim the crosshair towards the direction the enemy is moving in. Like, if they're moving to the right, you place the crosshair not on their body, but to it's right...cus well, slow af bullets 🤡
The new MK-7 assault rifle has a red dot sight, like in COD or PUBG. It shoots fast and is very accurate so most people love it.
The new striker pump shotgun has a slow fire rate, it's extremely inaccurate and extremely weak.
The new auto shotgun takes ages to reload and feels clunky.
r/overdid_it
🤡
 
kinda lol
 
Typing karne ka man kar raha tha 🙂
So, on your laptop, I assume?
 
@RajdeepSindhu yes
 
6:10 PM
Typing race karen, vmro? 🤡
 
@RajdeepSindhu thak chuka hu
haar haar ke
 
I'll take that as a yes 🤡
btw Sidharth types pretty fast. I'm pretty sure his average now is 100+ WPM. Used to race with him back when he had time 🙂
 
@RajdeepSindhu da fuk
when
 
On WhatsApp ._.
Like, a lot of months ago.
 
ofc
so howz life
 
6:16 PM
Or....
<rant>
</rant>
 
school exams?
 
Nah, dummy school. No exams, whatsoever.
 
moj
 
Vmro 6th ko agla test hai 🙂
 
@RajdeepSindhu you must be getting some revision modules n stuff
pdfs
?
 
6:19 PM
Nope, nothing at all.
Getting as in from the dummy school, right?
 
@RajdeepSindhu alun
from alun
so that real analysis book is waay more interesting that i thought but time nahi h🙂
 
@Arjun I get recorded "boards classes", yeah.
That has been happening for a few months now.
 
intro into real analysis by Wiley (publisher)
 
@Arjun I'm afraid I'm not as interested in maffs nowadays but I sure would enjoy it tons more than ALLUN 🙂
 
@RajdeepSindhu mfs not sending any revision modules wtf
@RajdeepSindhu Z lib pe dekh lena bhoiya
0 level se liya h
 
6:24 PM
@Arjun matlab? :/
 
and oh btw i saw NWM till aunt may dies
wtf
couldn't continue
 
Told ya it's darker than usual.
 
@RajdeepSindhu nothing needed to study the book from scratch
 
And dude, just watch for like, 10 more minutes. Some SERIOUSLY EPIC SHIT's gonna happen. Trust me, bro, just trust me.
@Arjun Oh yeah, that's interesting. Gonna check it out soon, hopefully 😎
 
@RajdeepSindhu tomorrow it is cus mummy yahi h
 
6:25 PM
@Arjun I mean, I got a message today about 12th class second term boards pdf's or something but I think they sent it out to every kid whose number they have, irrespective of their class.
@Arjun Sure! It's a good movie. Some plotholes and stuff that you realize later but during the first watch, it's awesome.
 
@RajdeepSindhu telegram go brr
@RajdeepSindhu but peter is dumb af
really dumb
i wouldn't have done that for like a million dollars
plus MIT ka re offer is at stake for the kid
 
@Arjun That as in cure the "bad guys" before sending them back?
 
@RajdeepSindhu do anything to/with them before sending them back
 
@Arjun It's complicated, I assume :/
I don't remember the plot too well, trying to recall it makes me uneasy 🙂
 
@RajdeepSindhu normal ig
 
6:30 PM
Anyway, the fight at the end with the goblin was pretty cool too...gets dark, considering it's an MCU spider man movie 🙂
@Arjun Happens pretty often. A major side effect of binge watching :/
 
@RajdeepSindhu stopped that months ago
 
@Arjun Stopped as in stopped watching things completely or stopped binge watching to watch them normally? 🤡
Dude, look at the comment section.
 
@RajdeepSindhu binge watching mainly
@RajdeepSindhu schrinzo?
 
I was confused about what that means for a good 10 seconds 💀
*Schizo
@Arjun Multiple personalitij hai phrans 🤡
Gtg to bed now. Gumd naight, bhioya. 🙂
 
@RajdeepSindhu i'll plan my sewer side
 
6:39 PM
@Arjun bhoiya abhi bhi fc0achingInstitut3s ke operations baaki hain 🙂
Cya!
 
7:11 PM
@Spectre Wait a min ... How is this integral able to solve the problem? I mean what's the logic behind this?
 
 
1 hour later…
8:33 PM
@YashAgrawal Hi! got a small doubt..can you please help?
ignore, i got it :)
@RajdeepSindhu congratulations
@Arjun hahaha😂
 

« first day (507 days earlier)      last day (830 days later) »