@sai-kartik Bro.. There is no hybridised orbitals.. you just combine different amounts of atomic orbitals to achieve minimum energy.. So in short, hybridisation and MO theory are on different planes of theory..
This is what I thought would happen in that q. Middle compound has two isomers (exo and endo) and compound on right would have 4 (exo, endo and one chiral center on the methylpentane attached to the boron. Coudn't calculate DU for middle and right compounds.
@RahulVerma I thought the larger ring would have an up-down orientation (somewhat similar to chair/boat forms of cyclohexane), but you're right: there are no exo/endo isomers for this compound.
