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00:00 - 08:0008:00 - 19:00

08:00
@CalvinKhor fluid simulation
im more busy today but depending on what it is i could have an answer in a few days
@NoseBleed no ty lol
Just a minute, I will give you an example
@CalvinKhor do it with ur every last memory on ur pc until GPU melts
if you actually simulated all the fluid particles you'd get just a tiny tiny microscopic fraction of a second of a movie
@CalvinKhor See this video at 0:37
That helical trajectory
08:04
@Knight even a kid can do that lol
0
Q: Why the color of light observed dark (almost no light) from section of overlapping of two different colored plastic sheets?

user69608Two transparent plastic sheets say of red and blue color overlap as shown in figure . An observer looks at a clear sky through the sheets. He will observe light coming through sections as, SECTION 1: Red color, less bright than usual SECTION 2: Blue color, less bright than usual SECTION 3:Dark,a...

what about it?
@NoseBleed Okay done! so you will do it for me, deal.
i did not understand the question no. (1)
08:05
@Knight but but my pc is dead
@CalvinKhor That helical trajectory of particles, is it hard to simulate (i mean to program)?
@NoseBleed You can remote log in my computer.
I made too much 3d models there
@Knight who will give me mouse and keyboard lol
@NoseBleed How are you typing now?
I m usin my smartarse phone
I can create a gif
the helix is just constant circular motion + constant horizontal motion
08:07
or I can program it
the rates of the two have to be linked, but there's nothing else to it
just don't know good ide
for android
if u ask me about codeskulptor I can't even access the gui
@CalvinKhor Can I (who knows nothing beside Latex) do it by some software?
thus I will not know how to debug or what really happened
What I want is the trajectory of COM of a regular triangle when it rolls.
08:09
hi! @JohnRennie
this is circular, not triangle :P
that can be done directly in desmos with a lot of patience
@user69608 hi :-)
the helices in that video are just (r cos(k t),r sin(k t)) + v(t,0) for some appropriate parameters r,k,v
@JohnRennie Goody Morning
@user69608 ... @JohnRennie
08:10
@CalvinKhor When the triangle gonna roll, I want the animation to trace the trajectory of its COM
yes, you can do this in. desmos, with a lot of pain
if you allow a side view anyway
3d view well you probably want to spend a lot longer time
How can I do it? Is there a guide for doing it in Desmos?
desmos has a user guide but its not gonna guide you to do that directly
if i was to do it, i would work everything out on paper, then do it
I have no experience, whatsoever for designing simulations. Where should I start from?
πŸ™ˆπŸ™‰πŸ™ŠπŸ‘‹πŸ‘πŸ€“πŸ‘ŠπŸ€œπŸ’ͺπŸ™ˆπŸ™‰πŸ™ŠπŸ‘‹πŸ»πŸ‘‹πŸ»πŸ‘‹πŸ»πŸ‘‹πŸ»πŸ‘‹πŸ»πŸ‘‹πŸ»πŸ‘‹πŸΌ
08:14
well desmos is just making a moving graph
the fact that its a simulation is decided by the creator
i guess you just need to know how to plot parametric curves, make a moving paramter, and how to plot regions of space via inequalities
that should be enough
and a lot of paper to work out the details
Okay!
πŸ™ŠπŸ™‰πŸ™ˆ
@user69608 you mean why does the red sheet transmit only red light?
@JohnRennie yes
if you want to be able to make one demonstration that works for arbitrarily shaped triangles, i think that may require a lot more work, should still be doable
08:17
@user69608 Isn't that a tautology? A red sheet looks red because it transmits red light.
but any one fixed triangle can be done rather simply
@CalvinKhor Yes, it's an equilateral triangle.
@JohnRennie "This is due to the atomic levels of the material. I suppose that the band structure of the red sheet is such that the occupied states are not coupled to unoccupied states by all wavelength (in the visible range) except red. Thus, all wavelength get absorbed except red." what is this?
@user69608 Have you studied the hydrogen atom yet?
@JohnRennie yes
08:20
So you know that a hydrogen atom will absorb light if the wavelength of the light matches the spacing between energy levels. Yes?
@JohnRennie yes
@user69608 a hydrogen atom only absorbs at exactly the wavelength that matches the energy difference, but in solids the energy levels get broadened out into bands. That means light can be absorbed over a range of wavelengths. i can draw a diagram to show what I mean if you want.
waht does being affine and respecting distance has to do with homeomorphism?
@CalvinKhor As I have drawn this graph how can I set $y\gt 0$?
08:24
@JohnRennie yes please
@NoseBleed i think those are "additional properties"
@Knight do you mean you want to draw only the upper circle?
YEs
at the end of your equation, write {y>0}
or {y>=0}, its almost the same thing
Oh Wow!
Thanks
08:25
Now, how can I make it move?
lol
I want the next circle to begin from where this one has its right end
you want to introduce a parameter
@CalvinKhor Kinda πŸ₯Ά
pick your favourite letter say K then just use it in your equation, maybe (x-K)^2+y^2=2{y>0}
desmos will detect that K is not defined, and will suggest to make a variable for you
make it, then click play
looks like it is additional property
looks like... hmm..
@user69608 here:
08:28
@CalvinKhor You're really great
lol glad to help
@JohnRennie Sir, Calvin is helping me so much.
I am half brain dead lol
yes it is additional property
@JohnRennie thats an incredible diagram that i never saw before (I dont generally study physics), its got an aha! built right into it
08:30
@user69608 the green line shows the transition in an atom where the energy levels are sharply defined.
In a solid the levels broaden out into bands, so we can get transitions from the lower band to the upper band over a range of waelengths.
@JohnRennie oh
"occupied states are not coupled to unoccupied states by all wavelength (in the visible range) except red." what does this mean?
@user69608 that's an unnecessarily complicated way of saying something that is actually quite simple.
If you look at the right side of my diagram then you see that any energy in between the red and blue lines will excite electrons between the bands.
If the light has less energy that the red line then even if the electron starts at th very top of the lower band it still won't have enoghh energy to reach the top band, so that light won't be absorbed.
If the light has more energy than the blue line then even if the electron starts at the bottom of the lower band the energy will take it past te top of the upper band, so again this light won't be absorbed.
So only light with a limited range of energies will be absorbed, and light outside that range of energies won't be absorbed.
Your red filter uses some chemical that has the energy bands positioned so they absorb green to blue light and don't absorb light with an energy less than green light.
That means red light isn't absorbed and it passes through the filter.
08:53
@Knight what grade r u studying in?
09:11
@CaptainBohemian should I ask math in English 😈
english chat
@NoseBleed people in English chat are not interested very much in math.
I think English chat people are interesting
since they are off topic most of the time
They are interested more in politics, literature, art.
thay have this awesome post there
Don't know if it is accurate or not lol
09:46
go ahead and try that
10:14
which chat is english chat?
10:25
@CalvinKhor english chat is English chat
confused is me
Ok I will call u confused from now on

 Language Overflow

This is the main chat room for ell.stackexchange.com. Welcome!
Confused this is the one
enter the portal
go go go!
oh i see
but my english is perfect ;)
how dare u say so...
imperfection is beauty
@CalvinKhor did u see that guy has kinda same profile pic as mine?
M.A.R
I forgot to ask
lord confused how is your kingdom doing?
10:48
lol but you just changed it
my kingdom is confusing
wait kingdom of confusing
Do you cite a research paper after reading it?
what do you mean?
i cite it when its relevant to the paper im writing?
Lol never knew that R feyman got arrested for prank
10:59
Reading a paper takes a lot of time
@CaptainBohemian that doesn't apply to lord calvin lol
I don't know what witchcraft he uses
nah it takes a long time
If I cite 50 papers after reading each one, how long can I submit my paper to a journal after writing it?
arent those completely decoupled things, i dont understand your question
when can you not submit to a journal?
11:17
Because you need to determine which references to cite before submission.
11:36
@abhas_RewCie I have not particular knowledge of astronomy. (I am not active on that site.)
@abhas_RewCie, sup
cool
you?
@abhas_RewCie, come in other room
Life on earth
 
1 hour later…
13:12
@Knight this is very far from a final answer but i messed around for a bit for your thing desmos.com/calculator/vfq2bzlct7
Or this one desmos.com/calculator/ua8yilrphc . The triangles are not adjusted correctly, but its a start i suppose
@CaptainBohemian oh, i guess you can/should adjust citations for journals, but why is there a time factor?
13:47
@CalvinKhor It's awesome Calvin
:) i was too lazy to compute things on paper, forgive me
But the triangle need to be a little below, because where it is standing right now the center of mass isn't denoted by the vertex of the half circle
yes, or you can move the line
there are many many problems with the graphs haha
But it's a very good one
but i think if you arent familliar with desmos its got enough to get you trying your own things
13:50
Can we make that triangle to roll ?
@CalvinKhor Yes.
yes, you can, you can apply a rotation matrix to the lines that generate the triangle
you can see, i defined the triangle as an intersection of three half-planes
if you rotate all 3 half planes, the triangle will rotate
Yes
also, if you replace x with (x-x_0) in the triangle, this will shift the triangle to the right by x_0, so if you choose x_0 correctly you can get it rolling
i shall do something with it
@CalvinKhor I did something like this
user434058
14:08
@Knight Well, the trajectory of the triangle's COM is just gonna be circular arcs placed beside one another.
user434058
TBH, it isn't an interesting case (Interesting paths only come up when you deal with bodies with smooth surfaces). Or else (for polygons), it'll always be a circle/circular arc.
user434058
Yo!
user434058
Nm
user434058
14:19
U?
inorganic chem :((
user434058
May God give you the strength! :P
user434058
@satan29 ik, i've been through that, and am also currnetly going through that.
14:41
@FakeMod Are you good with computers?
@FakeMod he is satan who doesn't need God's strength lol
my intro blessed the chat 🀣
send me flower
have u seen indian fairy with butterfly on it
@Arjun do you know that scene name
@NoseBleed ,what scene?
blue butterfly on a girl
I think on waterfall mountain
I have seen this scene somewhere
Baahubali
let me check
I saw somewhere in youtube
that was best I have seen
very artistic
14:51
Baahubali, tamanna bhatia and prabhas scene
its called divara
Witha song on a waterfall
do u like it?
intro is badarse
didn't see that 🧿🧿 what was written that got removed lol
That scene
waht do u think about the scene?
though Bollywood has good reputation on breaking law of physics I think it's great scene
beautiful
14:57
@NoseBleed ,worst scene
In movie
The movie was fantastic tho
well different people different thought ;P
haven't watch the movie
@CharlieShuffler hi
I was wondering if any of you know of a function similar in shape to $f(x)=\ln(1+\exp(x))$
just off of the top of your head
sounds probabilistic
I think I have seen that function before don't remember
15:00
its like $f(x)\approx x$ for x>0 and $f(x)\approx 0$ when x<0
may be in indices lecture
@CalvinKhor u might try this
I mean that question
I need to go for a throat singing
good night guys ! Have fun
good ni8
@CharlieShuffler Use Taylor series, you'll get better approximations.
$f(x) = \ln (1+ e^x)$
use $\ln (1+x)$ approximation, then put $e^x$ in it.
2
Q: Taylor series $\ln(1+e^x)$ about $x=0$

GoodsWhat's the best way to determine this up $x^3$ terms? I thought it would be to take the series for $\ln(1+x)$ and the series for $e^x$ up to $x^3$ and sub the second series into the first. $$\ln(1+x) = x - \frac {x^2}{2} +\frac {x^3}{3} + \cdots$$ $$e^x = 1+ x + \frac {x^2}{2} +\frac {x^3}{6} +...

Same as @abhas_RewCie said
@Knight +1
15:08
@CharlieShuffler You can see that as $x$ gets larger $1+e^x \approx e^x$ and it natural log is of course $x$.
@CharlieShuffler $max(x,0)$
Here is the graph:
if $f=\max(x,0)$ and $\phi$ any non-negative function with integral 1 over $\mathbb R$, then $f*\phi$ is another example. In particular if $\phi$ is chosen to be $C^\infty$, this lets you create uncountably many smooth examples
Yeah I need liked a smoothed out example of max(x,0)
I will give what you said a try, thank you
If you need better approximation of $\text{max} (x,0)$ then there are limiting ways of doing it.
15:37
so many ants
15:53
help me drive ants
16:12
Can somebody beat me up so that I can be like this
@CaptainBohemian it went from so how to so many ants lol
I do have lots of ants in my home
very eco friendly
very eco friendly tough guy
now sleepin
power off......(makes windows sound)
sorry it's so hot not so how
how to work with so many ants around?
@CaptainBohemian , make them friends
17:18
15
Q: Is the number of possible Bravais lattices a mathematical fact?

CampsAlmost anyone that has taken a Solid State Physics course will know, that any 3D crystal must be in one of the 14 Bravais lattices due to symmetry operations and space filling. In 2015, a paper was published in Scientific Reports1 (from Nature publishing group) that reports the findings of a crys...

@NikeDattani ,what do you want us to do, or were you just sharing a good question ;-)
@Arjun You're free to do anything you want! I just thought it was a question that would be interesting to the mathematical physicists here.
17:33
@NikeDattani , i read the question tho
it's very nice
@Arjun What did you think?
@NikeDattani , i am still in high school, so i cannot really understand it fully
but was a nice to know
@Arjun The answer is really what I think is great.
@NikeDattani ,well if it wouldn't have been, it shouldn't have got 15 upvotes:-)
communication of mathematics
17:41
@Arjun I guess you don't have enough rep there to upvote?
@NikeDattani , misconception, I have quite a bit of it to both upvote and downvote ;-)
@Arjun It seems you only have 101 on Matter Modeling, and you need 125 to downvote?
@NikeDattani , thought you were talking about MSE
@NikeDattani , anyway I did upvote the answer
You do have a lot of rep on Math.SE !
2
18:05
@NikeDattani ,I have a feeling you are teasing meπŸ˜‚
That was a joke
haha i guess he is just being nice
2
@satan29 , I know
I have not been very interested in gaing rep
Let's see, I have a +100 rep awaiting me on mse
2
651 is pretty good. More than me probably!
2
@NikeDattani , please see now!
Did u see?
It's mazik
@CaptainBohemian hi!
18:18
@satan29 what's up?
chemistry. you?
I am writing a summary.
Secrets of the cosmos?
00:00 - 08:0008:00 - 19:00

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