Has there been any work on homotopy Nambu brackets or even better on strong homotopy Nambu brackets?? Ordinary Nambu brackets appear most recently in work of Takhtajan.
I don't know -- can anyone make a case for these single use tags existing for more than a month? edit: I am convinced this is a useful cleanup task, to remove these orphaned tags from the system automatically. I've implemented a routine that removes tags created more than 6 months ago which have...
Single-use tags automatically expire after a few months. This is arguably the right thing when the tag is a misspelling (though I'd prefer some way of reviewing the process — but this post is not about that). However, if the tag was clearly deliberate, the default should be not to delete it. I pr...
Has there been any work on homotopy Nambu brackets or even better on strong homotopy Nambu brackets?? Ordinary Nambu brackets appear most recently in work of Takhtajan.
The tags on convexity are convex-geometry ($\times$560), convex-analysis ($\times$ 266), convexity ($\times$ 420). Here the number is the current (2019/02/23) number of uses and I ignore some more specific tags whose meaning is quite well-identified such as convex-polytopes or convex-optimization...
research.att.com/~njas
or maybe even research.att.com/~njas/sequences
rather than just research.att.com/
.
Given the base case $a_0 = 1$, does $a_n = a_{n-1} + \frac{1}{\left\lfloor{a_{n-1}}\right \rfloor}$ have a closed form solution? The sequence itself is divergent and simply goes {$1, 2, 2+\frac{1}{2}, 3, 3+\frac{1}{3}, 3+\frac{2}{3}, 4, 4+\frac{1}{4}, 4+\frac{2}{4}, 4+\frac{3}{4}, . . .$} and so ...
I know that $f : R^n \xrightarrow{} R$ and $g : R^n \xrightarrow{} R$ are quasiconcave functions. How can I prove that the function $h(x)=\min\left\{f(x),g(x)\right\}$ is also quasiconcave? $\\$ $\\$ edit: (1) $f:D\xrightarrow{}R$ is quasiconcave if and only if the following holds for all $x...
Given the base case $a_0 = 1$, does $a_n = a_{n-1} + \frac{1}{\left\lfloor{a_{n-1}}\right \rfloor}$ have a closed form solution? The sequence itself is divergent and simply goes {$1, 2, 2+\frac{1}{2}, 3, 3+\frac{1}{3}, 3+\frac{2}{3}, 4, 4+\frac{1}{4}, 4+\frac{2}{4}, 4+\frac{3}{4}, . . .$} and so ...
Polynomials $p(x) \bmod N$, where $p(x)$ is of integer coefficients and $N$ is a composite of two distinct primes $p, q$, form a cycle --- usually leaving a tail because the cycle tends to close not on the first element of the sequence. The cycle size is called the period of the polynomial. Try...
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