Hello!! Let $P(x, y) \in \mathbb{Q}[x, y]$. We consider the equation $P(x, y)=0 (1)$. If $a, b \in \mathbb{Q}$ such that $P(a, b)=0$ then $(a, b) \in \mathbb{Q}^2$, is called a rational solution. If $K$ a field, $\mathbb{Q} \leq K$, then if $(a, b) \in K \times K$ and $P(a, b)=0$ then $(a, b)$ is called a $K-$rational solution.
When $(a, b)$ is a $K-$rational solution does this mean that $(a, b) \in \mathbb{Q}$ ??
For example, $x^2-2$, is $\sqrt{2}$ a $\mathbb{R}-$solution ??