Could anyone help me with a problem? Basically: A person falls off a ridge into a snow bank. Distance from ridge to snow bank is $3.6\,m$. Person descends into snow bank $0.80\,m$ before stopping. What is the acceleration in the snow bank?
I figured the first $3.6\,m$ follows the position function $y(t) = -1.635t^3$. Therefore, it takes $1.3\,s$ to fall from the ridge to the snow bank. $\vec{v_0}$ in the snow bank is then $-8.289\,m/s$. How do I figure out $\vec{a}$ in the snow if I don't have time?