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vzn
12:01 AM
@0celo7 "PE"? physics engineering?
 
@vzn Professional Engineer
 
vzn
cool, good idea ;)
← (software) engineer
 
@ChrisWhite I'd be more interested in the grad school data
 
@0celo7 metric affine spaces do
 
@ChrisWhite Well I'm quite sure there are a whole lot of statistics on how education affects pay. I'm not sure if this is a good measure of actual value added as different educational backgrounds will often lead to different jobs, as well.
 
12:07 AM
@0celo7 an affine space is a set of points, a vector space, and an operation +:E x V --> E
That obeys like 3 axioms: modfied versions of identity, associativity, and uniqueness of a vector linking two points a and b
Something like that
 
@StanShunpike Of course, the metric is the isomorphism to the dual space. This allows for an inner product.
In a sense, the inner product defines our notion of perpendicularity.
 
Dual space of what?
 
the vector space
idk if dual affine space is a thing
@StanShunpike How far along are you in Wald?
 
@dmckee I am so screwed if I don't end up doing research... :\
 
12:32 AM
@0celo7 I have read bits of 2,3,4,14 lol
@Danu what do u mean?
@0celo7 I don't think my differential geometry is where it needs to be. Wald is great but I feel like I'm not getting as much out of it as I would if I were more comfortable with certain diffgeo concepts
 
@StanShunpike You read the appendices, right?
At least the first three
What concepts are you missing?
 
Flows for one.
I only just got that the other day.
And I'm still not comfortable with the math just the idea.
 
@0celo7 no good answers on your question on the perihelion shift of Mercury yet! :(
Well, joshphysics's comment is pretty much an answer but
 
@NeuroFuzzy Yeah, I don't care that it's all numeric, I want to see the concept of the calculation. I have no idea how the 3+ body problem works.
 
french!
 
12:37 AM
@StanShunpike What exactly don't you get about it?
 
@0celo7 another is my underatanding of lightlike vs nulllike vs spacelike. Like I read in Hartle that if Bob stays still and Alice moves in the x dimension and comes back. They meet at rhe same spacetiem point. But Bobs path is longer. And that doesn't make sense to me.
Like on paper Alice's path is longer. I can fins the diagram
 
@0celo7 maybe I'll sift through some books in the library here for (English) references
 
But supposedly Bobs path is longer
 
it's probably just sitting there in some book on perturbations
 
And like I think this would be obvious to me if my diffgeo was better
 
12:40 AM
@StanShunpike The distance for straight lines in one-dimensional Minkowski space is $$x^2-t^2$$ right? (modulo a sign)
 
Yes exactly
 
This is just the line element integrated accordingly.
 
@Danu I left academia after my PhD not because there weren't positions available (post docs at least were easy to come by), but rather because I was just bored with the work itself. When I was younger I didn't think that would happen, but it did. So... all the more reason to focus on more than just one thing, I suppose, especially if you don't have a lot of experience doing research and publishing it yet.
 
@StanShunpike Thinking.
I might have a reference.
You have Zee's gravity book? (IIRC you do.)
 
Yessir
 
12:42 AM
p.175-6
Read that, then come back.
 
Brb
@0celo7 wow, you're right. Okay, I keep forgetting about the non-positive definite. See, for me, although correct, its counterintuitive because we day light is moving yet it travels 0 length curves right because of equal space and equal time. Doesn't that seem counterintuitive like....how can something move and yet travel no distance? Because if light moves I unit space and 1 unit time, you get zero for the interval
 
@StanShunpike 1 unit in $c=1$, yes.
 
I guess though if I am at point p on a manifold, p' is a different point. But what does 0 length curve mean then?
 
@StanShunpike Note that this is not a Riemannian manifold.
"Length" really has no meaning.
 
Yeah! This is where I am confused. Good. So how can an object move from p to p' and travel along a 0 length curve. Are u saying we don't use length? But people always talk about proper time lengths... Don't they?
Isn't that a length?
 
12:55 AM
It's a length in the sense that it has dimensions of length. As you've seen, it has no intuitive connection to our concept of length.
@StanShunpike Oh, proper time! Sorry, misread.
 
So distance / length here doesn't actually represent the length between points?
 
@StanShunpike The proper time is defined as the line integral $$\tau=\int_\gamma d\tau$$ along the path $\gamma$. This is equal to the time measured by the particle traveling along $\gamma$ in its own rest frame.
@StanShunpike It is (modulo a sign and a factor of $c$ or two) the time in the rest frame.
It's just the time elapsed in the rest frame, not really a distance.
@StanShunpike What don't you get about flows?
 
Okay, so according to my book.. Hang on let me get the def
A flow of a vector files is a collection of maps
That map from subsets of a manifold to a manifold
Such that \mu_s m = \gamma_m s for each m in the subset set of the manifold
Where gamma is the integral curve of the vector field starting at m
 
Is $m$ a point?
 
1:09 AM
Is $\mu_s$ the flow?
What is $s$?
What book are you using?
 
Tensor Analysis on manifolds
page 125
he cites the initial symbols on page 116 but I think you can probably get it from context
The flow of a vector field X is the collection of maps {\mu_s: E_s -> M | s \in R}
 
@StanShunpike What does $\gamma_m s$ mean?
 
taht's the integral curve
\mu_s m = \gamma_m s for each m \in E_s
where \gamma_m is the integral curve of X starting at m.
Thus m and \mu_sm are always on the same integral curve of X
and the difference in paramter values at \mu_s m and m is s'
sorry
that should be s;
in other words, \mu_s is the map which pushes each point along the integral curve
by an amount equal to the parameter change s
the domain of \mu_s , E_s, consists of those points m such that \gamma_m is defined at s
hang on
I'm gonna post photo to end the confusion
 
Ok. The general idea of flow is that it is a one-parameter family of diffeomorphisms generated by a vector field $X$. The integral curves of $X$ are of course $\dot\gamma =X$. The flow is defined by $\phi_t(x)=\gamma(t)$. The flow operator $\phi_t$ is just a map from the point $\gamma(0)$ to $\gamma(t)$ along the integral curve.
 
Yeah, okay. There you go.
What does this map do?!?
 
1:18 AM
@StanShunpike Get chat MathJax.
It maps stuff along the integral curve.
 
Like does it just take the vector field at that point and move it along?
Or is this just a general map
of something
 
@StanShunpike That's the pushforward $\phi_{t*}$.
It's just a diffeomorphism.
It is best understood in terms of how it acts on vectors and forms.
It pushes vectors along the integral curve and pulls forms back along the integral curve.
 
AH! that's so cool!
So that's why it's called that.
I didn't get how they were related, but that makes a lot of sense.
So does the flow operator do both at the same time?
Pushforward and pullback
oh wait not
it would depend on what it's operating on
 
Lol: Eagles just got rid of their best player for a LB: nfl.com/news/story/0ap3000000476192/article/…
 
@KyleKanos lmao chip kelly. did they make the playoffs? no right, they lost to Dallas at the end of the season.
@0celo7 So if I am at a point m with a vector defined there, and I act on that point with the flow operator and push it forward to point m', is the vector from point m now at m'
 
1:25 AM
@StanShunpike You act on it with the pushforward of the flow, but your idea is correct.
@StanShunpike Now the Lie derivative is just a derivative that uses the flow operator instead of the normal $f(x+dx)$
 
@StanShunpike They did go 10-6
But no, they didn't make the PO
 
@0celo7 So you use the flow operator instead of the function f?
@KyleKanos They petered out. I thought they looked good. But obviously having Sanchez instead of of Foles didn't help.
@0celo7 LOL that's so cool. Lie derivatives are the next section after flows
 
@StanShunpike No you use $(\phi_{t*}v-v)/t$ instead of $(f(x+dx)-f(x))/dx$
One is a vector, the other is a function
The Lie derivative is connected to the directional derivative.
 
Oh, you subtract the non-operated on one from the operated on one.
That makes sense. That's awesome. I've wanted to learn that for ages. Coool
Alright, let's see if I can get this notion of length correct. So if I have a point p on my manifold, don't I have to travel some length to get to some other point o'? Or am I being too Euclidean here....and not thinking manifold enough. I just don't see how the metric $ds^2$ could be 0 and yet travel between to points...hang on I think Wald has a section on this
Yeah, page 59
He says "Thus, the labels at $t = x^0, x^1, x^2, x^3 of a given event do not have any intrinsic meaning"
Is this related to why I see a contradiction between.....on the one hand, traveling between points on a manifold....and on the other....having distances whose interval is zero
 
@StanShunpike I have to go now. Homework. Note that this is an artifact of having a metric that is not positive definite. It is perfectly possible to Wick rotate, i.e. $t\rightarrow -it$ and then work in $E^4$.
In Wick rotated space there is no such thing as null.
 
1:39 AM
I got that! :)
lol
 
You are very limited now, however, because there is no light cone.
This trick is pulled in QFT and String Theory a lot, when we don't care about causal structure.
(Don't shoot me for saying we don't care about causal structure in QFT or ST. You know what I mean.)
 
lol I know what you mean exactly
QFT is all about bending rules enough but not so much logic breaks
 
 
3 hours later…
4:27 AM
@0celo7 I still don't think that guy answered my question. He explained how different particles can only travel along certain intervals. But that didn't explain how we could measure a curve on a manifold and have the spacetime interval distance traveled be 0 and yet move from one point to another. I know it must work somehow, but I still don't get it.
0 distance should imply same point. That's like having a line connecting two points and shrinking it to 0. Same point then.
from a one dimensional space to a zero dimensional one
 
4:41 AM
For anyone else interested, here's the question: physics.stackexchange.com/questions/168296/…
 
4:52 AM
I mean, @StanShunpike , you're thinking of a metric space, which is the good meaningful sensible extension of euclidean geometry
The crux of special relativity is that invariant interval, so...
actually if you google "pseudometric space" you get en.wikipedia.org/wiki/Pseudometric_space for which the very first sentence is... "is a generalized metric space in which the distance between two distinct points can be zero."
The way I see it, first you use special relativity and all those weird experiments to establish that yes, you can consider such an invariant interval. From the invariant interval you get lorentz transformations and all that nice stuff
which is all just trying to understand what you've defined when defining the invariant interval
"geometry" means that metric here
"Why do we take that [pseudo]metric" is met by experiments in special relativity. "Why is the value zero" is met by "because we took that [pseudo]metric"!
QED!
 
5:20 AM
@NeuroFuzzy Okay, so I have a spacetime interval. this interval is invariant for all reference frames. Is this interval measuring the distance between point on my spacetime manifold?
 
@StanShunpike consider this: how do you define "distance"?
 
5:43 AM
@DavidZ Okay, I define distance as.....in the metric space way.
WAIT
Let me get a specific definition so I am not vague this time.
If M is my space
and d is my distance function
d: M x M --> R
where R is the real numbers
So,
(1) $d(x,y) \geq 0$
(2) $d(x,y) = 0$ iff $x =y$
(3) $d(x,y) = d(y,x)$
(4) triangle inequality
That's what I think of distance as. But the question is, does this actually work for the structure of spacetime? If not, what do we have to relax or add in order to make it work?
 
It does not work. It is not a metric space. You have to relax positivity and neq 0 as detailed on the wiki pafe for pseudo metrics.
 
@StanShunpike You're mixing up two different definitions there: one is the metric space definition, and the other is the enumerated set of properties (1)-(4) in your last message
At least where pseudometric spaces (like Minkowski space) are concerned.
 
6:10 AM
@DavidZ I thought those four properties were the definition of a metric space.
So I am mixing up pseudometric space vs metric space?
@NeuroFuzzy Right, so what we have is a pseudometric space.....so maybe you are right. maybe I am just not familiar enough with that idea.
 
They're the definition of a distance function on a metric space. But in order for a space to be a metric space, the metric has to be positive definite.
 
Correct. So by definition it doesn't work here. So what I am asking then is, does that mean we lose our ability to define distance? or do we have to change what we consider distance to be to one of a pseudometric space?
 
When the metric isn't positive definite (e.g. Minkowski space), you can still define a distance function from the metric, but it doesn't satisfy those four properties.
Or you can define a distance function that satisfies the four properties, but then it's not related to the metric.
 
What properties does it satisfy? Because the metric space ones match my intuitive sense of distance.
 
I believe only property (3), out of the four you mentioned.
 
6:15 AM
Wow. That's very different then.
Is there a name for this new kind of distance function?
or is that the pseudometric space neurofuzzy mentioned
 
This is why I asked how you defined "distance": If you want a definition of distance that satisfies the four properties, i.e. one which matches your intuitive sense of what a distance is, then you cannot use the definition that comes from the Minkowski metric.
@StanShunpike I guess we generally call it the "interval"
 
Okay, let me try this approach. On a spacetime manifold, can I move between points? By move I mean like with proper time. That is, if I am at point $p$, I can move to point $p'$. Assuming that's true, there must be some way of measuring how far I went. Is that what the "interval" does?
 
Define "far" (or "how far")
 
Which translates into your original question to me...define distance
It's like we need a way of establishing some sort of unit of length or distance traveled
If the usual definition of distance doesn't work, how do we measure distance?
 
@StanShunpike Yes, exactly. My point is that you need to decide on a definition of distance before you can meaningfully talk about how far one point is from another, but the reason you're confused is that you haven't decided on a definition of distance to use. You're picking pieces of two incompatible definitions.
 
6:24 AM
or are u saying that's a meaningless concept.
I'm starting to see your point.
 
@StanShunpike maybe we don't need to measure distance at all?
 
Well, maybe I'm being to Euclidean, but I always like to think of distance as a way to gauge whether I've traveled between two points.
 
I'm guessing you mean, if distance traveled is zero then you haven't moved to a different point? Yeah, you'll have to dispense with that notion if you want to use the definition of distance that emerges from the Minkowski metric.
 
Okay. So that idea doesn't work anymore. Hence, you said those axioms of a metric space no longer work.
Hmm....well, at the very least, I am learning my personal definition of distance is quite inadequate at the moment for the things I seemed to be interested in.
 
@StanShunpike you mean the items (1) through (4) you listed earlier? Yeah, those don't work for Minkowski space.
At least, not all of them do.
That's why they technically call such spaces "pseudometric spaces" rather than "metric spaces".
 
6:33 AM
True. It's still a very different intuition compared to the normal sense of distance.
@DavidZ So when massless particles moves along light-like intervals, they don't travel any distance?
 
Again it depends on how you define "distance".
If you define distance as the spacetime interval, then no, they don't.
 
Are there multiple common ways of defining distance? I mean, correct me if I am wrong, but for Euclidean spaces we usually have one way of defining distance right? For Minkowski space, do we have multiple ones? What besides the spacetime interval could one use?
 
In my experience, when people talk about distance in Minkowski space they usually mean the difference in spatial coordinates between two events. This is reference-frame dependent, of course.
 
Huh, that's interesting. I must be using the wrong words then.
Like when a particle travels along a geodesic, isn't that "distance"? Are you saying, people don't usually talk about it like that?
 
Not in my experience. But then again I don't work in GR.
It's also worth noting that people will sometimes use "distance" in a sense other than the proper technical one.
 
6:44 AM
Yes, I may be running into that. I also don't know if there's some issue with the fact that...some of the math texts I read only address Riemannian manifolds...and those involve distance functions I think in the original 4 point definition I gave.
 
For instance, you can talk about the proper time elapsed for a particle moving on a (timelike) geodesic, or the change in affine parameter between two points on a lightlike geodesic (given a particular parametrization of course), and these things correspond in some intuitive sense to what we consider a "distance" so people may call them "distance".
e.g. "the particle moves a certain distance along the geodesic"
but this is not the sort of distance that satisfies the properties (1)-(4) of a distance function.
 
REALLY oh I assumed it did!
No wonder I am confused!
oh, so it doesn't? wow that explains a lot.
 
Or actually, I think I misspoke: it's more likely that this "distance" does satisfy the properties (1)-(4) but it's not related to the metric
 
You mean the metric as in metric tensor field or metric as in distance function of a metric space?
 
When I say "metric" I mean the metric tensor field. If I mean the distance function I'll say "distance function".
$$d(A,B) = \int_A^B \sqrt{g_{\mu\nu}\frac{\partial x^\mu}{\partial s} \frac{\partial x^\nu}{\partial s}}\mathrm{d}s$$
$g$ is the metric, $d$ is the distance function
wait a sec...
ok there we go
 
6:54 AM
I just figured out how to use ChatJax that's really convenient lol
anyways
So here $A$ and $B$ are two points
 
Yep
 
So this is a notion of distance that does or does not satisfy the 4-point metric space definition? Presumably not since you said it doesn't work on Minkowski space.
But it is a "function" and in quantifies the "distance" in this other sense people use regarding proper time
 
This does not satisfy the 4-point metric space definition.
For example, for lightlike separated points it gives zero.
 
user54412
(see also answer I just wrote :)
 
Amazing answer. Thanks Chris!
@DavidZ Chris raises a good point
If the distance you measure between two points is path dependent, then distance really is an unreliable measure of where you are on a manifold.
I hadn't considered that possibility.
Now, it makes me wonder whether distance is all that useful.
 
7:03 AM
Yeah, I was also going to bring that up: the value of the distance function as I defined it above is path-dependent
 
I couldn't tell whether you were being just thought provoking or literal/serious when you said "maybe we don't need to measure distance at all?" If the path influences the distance, then almost certainly distance wouldn't be very useful. That would be like saying if I walk 5 paces east and 5 paces north, then the point I arrive at is different then if I walked 5 paces north then 5 paces east.
 
That could well be the case.
Like on the surface of the Earth, if you go 3000 miles north and then 3000 miles west, you wind up at a different point than if you go 3000 miles west and then 3000 miles north
which in turn is different than going 3000 miles north, turning left by 90 degrees, and going 3000 miles in that new direction
@StanShunpike I was kind of going for both, actually. Distance is just not such a useful concept when working with arbitrary pseudometric spaces.
 
Clearly, in a way I've never really appreciated.
I mean, now that you mention it, I feel like I'm starting to see how limiting that Euclidean viewpoint can be because there are plenty of examples without even considering spacetime of non-Euclidean geometries where path influences distance.
It's like a the wrong paradigm that becomes exaggerated in its inadequacy for
when you consider spacetime.
But without distance, how do I know where I am on the manifold? What are our tools for defining location in spacetime?
by location, I mean (t,x,y,z)
 
That's what coordinate systems are for
You don't need distance to define location, you only need some way of labeling points
 
What about polar coordinates? Isn't that an example of a coordinate system requiring distance?
But I suppose if you have Cartesian
and those don't require distance, then you could always simply convert to polar
 
7:17 AM
Why would polar coordinates require distance?
 
Well, I have always thought of $r$ as the distance from the origin of the polar coordinate system. Is that the wrong way to think about it?
 
Well... maybe not so much wrong, as it will help you if you are able to think of $r$ more generally.
What I mean is that $r$ is really just a number that forms part of a label for a point.
 
Like as just labeling a point as opposed to being a distance?
 
Yeah.
If you are working with polar coordinates in Euclidean space (or you can make this work for other kinds of spaces as well), then that label happens to be the same as the distance from the origin.
But you don't need to have any notion of distance to use a number as a label.
 
Oh......this maybe why I am so confused about coordinate transformations.
 
7:22 AM
Could be.
 
Because in many differential geometry situations I've come across, people talk about tensors and how if they are invariant in one system, they are invariant in all.
and I never understood how you could test all possible coordinate transformations.
to know if they were invariant.
But maybe if I just think about them as labels and not like distances....or at least pursue that train of thought, I might find a better answer to this confusion I've had.
 
Perhaps. I think what you're talking about might be getting into something else a little bit, but it's useful to think about.
Here's something to think about: if you allow $r$ to just be a label, then you can easily deal with a space that has a circular or spherical region cut out of it
 
Like a donut?
 
Not what I had in mind (although I guess you can use this for a donut too, it's just more complicated)
Imagine a 2D plane with a circular piece missing
 
A disc cut out
 
7:26 AM
Yeah
 
For such a space, I wouldn't be able to make reference to some central origin right because it wouldn't be part of the space.
 
Yeah, exactly
So you can't have a coordinate that is the distance to the origin. But you can still have a coordinate that is a label.
 
You're right that is a good example. It's got the same geometrical intuition, but without the luxury of relying on that central point as the means for defining everything in the system.
Instead, you have to accept it for what it is. Coordinates not distance.
 
This is very relevant for black holes, incidentally. You can't readily define $r$ as the spatial distance from the singularity because the space inside the event horizon is so distorted. But it's straightforward to use a different procedure to come up with a label that you can call $r$ for any sphere of points centered on the hole.
 
Ah! That's why I've been having trouble with that too.
I couldn't visualize the geometries.
And it's made it hard to get started learning about them.
It's funny because MTW make it sound like coordinate-invariant approaches to everything is a more useful way to think about many concepts in GR, yet here we sit talking about many applications of coordinates. Really, of all the tools, it seems like distance is the tool that loses the most value as a determination of where you are.
 
7:37 AM
I'd agree with never relying on distance as a determinator of location
 
Amazing stuff! Well, I'm off to bed. To quote ACuriousMind, Good #TimeofDay! And thanks for the help DZ.
 
No problem
 
8:04 AM
@StanShunpike good morning
 
 
4 hours later…
11:58 AM
@KyleKanos You asked for pics
But now I have to leave to picket again.
 
I hope you are picketing the cold, miserable weather
That does not look like fun
 
I'm Canadian. It's always like that
 
@JimdalftheGrey That looks miserable
 
 
1 hour later…
1:21 PM
@JimdalftheGrey Nice, thanks!
 
This might be the coolest way to visualize the nodes in the waves from your microwave:
 
That makes sense -- a friend posted that link on FB, and they would be the type to read what-if
 
Oh, I thought you actually picked that out of the What-If
I posted the link in case others were unsure of where it came from
 
Nah, I hadn't read it yet
Been in "fixing my shitty co-workers mistakes" mode since 5am
First time I've had to run a ridiculously large problem (and it's only a fraction of the size I need to run)
And all kinds of things don't work
And this is only 64,000,000 cells. I need to get closer to 1 billion but our tools don't even work well at this stage
Now it's class time... back to my coding hell in 2 hours!
 
2:16 PM
@JimdalftheGrey I don't see any signs - what is this about?
 
People over at UToronto went on strike
Jimdalf went with them
I find it kinda fascinating.
 
People are mad because Jimdalf created a small black hole in his lab which is slowly devouring Toronto.
 
My dad worked on the US Gov't side of Union negotiations
In his 30 years of work, he never once was faced with a strike at his facility, despite others across the nation seeing them
So to see this level of failure of negotiation is what is fascinating to me
Questions like, "Why was my dad so successful?" pop up each time.
And, apparently, he was approached multiple times to write a book about his methods and rationale
He declined each time saying, something along the lines of, "It would give the Unions access to negotiation/leverage tools that I need."
 
@KyleKanos Thanks!
 
2:33 PM
Jimdalf is a teaching assistant?
 
Now, um, what happened here? John Rennie used "possible duplicate" as an "other" off-topic close reason because he couldn't actually use the duplicate close reason because the other question doesn't have an upvoted/accepted answer? And nobody thinks this is a wrong use of the other field?
 
2:44 PM
@ACuriousMind I'm pretty sure that's not the first time I've seen that.
Obviously not having the linked duplicate at the top isn't a good idea
 
I'm pretty sure it is intentional that you can't close as duplicate of unanswered questions, though I question the value of that.
And I don't think I've seen that before, but I'm not 100% sure
 
That makes sense why it wasn't done as the normal duplicate method
But it makes you wonder: is that duplicate worth it if no one has upvoted it in the last year
 
Well, the duplicate is oddly closed as "homework" although it definitely isn't homework like - it's a conceptual question, just one that is easily answered by typing the phrase into a search engine of your choosing.
 
Neither question about drift velocity is very good. A quick google search or flip through an introductory college physics text will give the answer
 
Let me say again that I wish more people would downvote these questions
2
 
2:51 PM
I'm starting to think that we could make the "closed as homework" one into a slightly better question and reopen it
0
Q: What is drift velocity? And how to find the equation for it?

UzairWhat is drift velocity? And why in some books it is expressed as drift speed and not drift velocity?Are these different ? Does it mean that the electron will have extra velocity opposite to the direction of electric field i.e thermal(random) velocity + drift velocity=Total velocity of electron,...

 
Why do you even close a question for a reason that doesn't even match it? Obviously because you think it's a bad question, so why did no one downvote it?
 
It does not appear to be HW at all, IMO
 
@KyleKanos You thought differently a year ago, apparently ;)
 
And seeing that it was a year ago, I forget the rationale
I don't think we were closing under the "insufficient effort" rationale (which I still kinda disagree with) at that point
So it may be that "Homework" was the closest thing we could do for it
But I think I'm going to try editing it and getting it reopened
 
It seems that questions still get closed for insuffient effort even though that's not a real close reason
Just based on what I've seen in the past
 
2:54 PM
You can't close a closed question ;)
 
@Sean Yeah, in most cases, I disagree with it.
 
So worst case is my edits go for naught
 
But if some literally asks "What is X?" where X has a good Wikipedia article, then I'm kinda willing to close it
 
+ leaving a comment along the lines of, "Did you read the <wikipedia entry> on it? What in there confuses you?"
 
3:11 PM
I started editing the 2nd answer and realized it's a jumbled mess of ideas
 
3:29 PM
@KyleKanos There was a problem about a spinning mirror. I voted for closing, but also I wanted to give some advice to the OP, just because I saw that he/she is going to work too hard. But the question disappeared. Not only it is no more in the unanswered list, but neither is it in the questions list. Do you have any idea if it was migrated? I don't know the address of the question, and didn't have even time to post my comment. I would appreciate help.
@KyleKanos although I voted for close, because this is the rule, I feel sorry for just working hard without even knowing where to leads the work?
 
@Sofia I don't know the post, but I don't see it in the "recently deleted" 10k+ tool, nor do I see it in the close queue
 
@KyleKanos it disappeared, as simply as that. Smells of a bug in our software.
 
No, probably not
What probably happened was the OP deleted the question themselves
 
Are self-deletions not shown in "recently deleted"?
 
@KyleKanos Aaaaa, yes? And in this case nobody can see anymore his/her question. Not even high-reputation users as you?
 
3:37 PM
@ACuriousMind It does not appear that way, which is kinda depressing
 
@KyleKanos I feel sorry. I will never vote for close again, before seeing how to help. But, if you speak of self-closing, that's something else.
 
@Sofia Why do you feel sorry? And why is that making you not want to vote to close?
@Sofia If you find me the link, I'd be able to see it
 
@KyleKanos Recalling the black hole question John Rennie got us to undelete, I'd say that's a major flaw
Possible feature-request on mother meta?
 
I'm looking now
 
36
Q: Improve the "recently deleted" tool

Georg FritzscheThe "recently deleted" 10k tool is too limited: it only includes a fixed number of deleted posts (45 apparently?) it only displays posts in a certain time-span (haven't seen anything older than 1h) it includes spam posts etc., making it hard to filter out deletions for review it doesn't allow t...

Related, and unanswered
 
3:42 PM
So, do you lose points for responding to inane questions?
 
@Jiminion Only if "responding=answering" and your answer is downvoted
So, no, generically
 
You can always delete your own bad answers.
 
And deleting answers loses all rep on it: up and down
 
Yes. Additionally, the correlation between votes and quality is unreliable
BTW I'm slowly doing Chris' quality-vote thingy, expect a new answer on that meta post sometime soon
 
@KyleKanos yes, you are right. The recently deleted queue is empty. Strange! But, tell me, you, the users with very big reputation points, also don't see self-deletions?
 
3:48 PM
We indeed can see them; finding them is different
 
@Sofia Whatever you are looking at, you cannot see the recently deleted queue, because that is only visible to 10k users.
 
@ACuriousMind I can get into the recently deleted queue, it appears at the end of the list of my questions.
 
@Sofia Oh, these are only your own recently deleted questions. You cannot see any deleted stuff from other users there.
 
@ACuriousMind no! Not true! I do see deleted questions which are not mine.
 
Now that would be a bug in the system.
Do you have an example?
 
3:53 PM
@KyleKanos , @ACuriousMind just for you to know, there are other bugs too that I noticed. Yes, I will look right now, and tell you.
 
Post the link you're looking at
 
@KyleKanos wait a minute. The recent deleted queue is empty.
 
What we're trying to say is that there isn't a deleted queue for you because you don't have 10k+ rep
And if you did have 10k+ rep, you'd see that there are deleted questions in the "recently deleted" list.
 
@KyleKanos do you want to say that while for me the recent deleted queue is empty, while for you it isn't?
 
I'd rather the link you're going to in order to see the "Deleted queue"
 

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