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12:00 AM
Oh I had it written in my master thesis
 
for fuck's sake
:D
 
We need more :D's
 
$R = \frac{1}{2} g_{ab,c} g_{de,f} g^{ac} g^{de} g^{bf} - \frac{1}{2} g_{ab,c} g_{de,f} g^{ab} g^{de} g^{cf} + g_{ab,c} g_{de,f} g^{dc} g^{be} g^{af} + g_{ab,c} g_{de,f} g^{df} g^{be} g^{ac} + g_{ab,cd} g^{ac} g^{bd} - g_{ab,cd} g^{ab} g^{cd}$
Hm
Might not have enough room to paste it here
Let's open a tex doc
 
do it
this chat is pretty stupid
all we do is troll and laugh at with Slereah
 
@0celo7 Using the royal "we", eh? :P
 
12:04 AM
@ACuriousMind I'm a fucking holy emperor, you peasant.
@ACuriousMind you're the second biggest troll in here!!!!!!!
after @HDE226868
 
@0celo7 I feel like you write a lot of relevant chat messages, then quickly and randomly sub in my name whenever I drop in here.
 
you...you think I write relevant things??
oh how sweet of you!
well you're the only one in here who's impersonating an American
@Slereah are you literally writing out the Ricci scalar with every component?
 
I am
It is p. long
 
lol
pic of progress?
 
12:11 AM
jesus
 
Gonna need to do a lot of factoring
 
haha the title of the image :D
do we know more about solving the Einstein equation than Navier-Stokes?
 
Probably not
But Navier Stokes tends to be more used for real problems so we usually can't assume a bunch of symmetries
 
woo
real problems are woo
 
When we will do the flow of spacetime in a pipe we will probably study it more
 
12:17 AM
so is energy really when you inject more spacetime into space?
or do you pour some gin into space
or is it spacetime?
eh, whatever, they're the same
I've been wondering something
How much math does JR really know? I haven't seen him using anything fancy.
 
I have mostly seen him use $E=mc^2$ and $E = h\nu$
Multiplications are his forte
 
JR
not JD -.-
you have a habit of mixing the two up
 
oh
 
1:16 AM
This is just one term :(
 
obe
1:41 AM
speaking of handwriting
want to see mine @0celo7
shankar behind it for reference.
@0celo7
 
user54412
2:18 AM
@DanielSank I've been meaning to ask you about your first comment under the question. Is it "just" a warning about propagation of errors in any real calculation, or is there something there more fundamental? In particular, are you referring to the loss of phase information in having just the power spectrum on hand?
 
user54412
@NeuroFuzzy That's basically right. What wikipedia calls the Gauss-Faraday law is the evolution equation I use for E&M on curved spacetimes.
 
user54412
Sometimes you see it written $\nabla_\mu {}^*F^{\mu\nu} = 0$ (that epsilon contraction is the Hodge star in index form), where because $F$ (and thus its Hodge dual) is antisymmetric and rank 2 you can convert covariant derivaives to partials and all the connection coefficients vanish identically.
 
user54412
btw, it works on all stationary ($\partial_t g_{\mu\nu} = 0$) spacetimes, not just static (stationary + $g_{ti} = 0$)
 
user54412
If you really want to do this in practice, though, there is an extremely important but subtle numerical issue with the evolution.
 
user54412
There is a constraint in maxwell's equations (call it $\nabla \cdot B = 0$, or $\nabla_\mu {}^*F^{0\mu} = 0$ or whatever). And naively evolving a system according to the evolution equations tends to lead to violations in this constraint that accumulate over time. This is separate from the numerical stability of the integrator per se, and there are many volumes of literature written on how to properly evolve the electromagnetic field.
 
user54412
2:33 AM
Basically, treating the 4-divergence of an antisymmetric tensor as the flux-conservative evolution of 3 (ideal MHD, perfect conductor case) or 6 independent scalars is... morally wrong. We do it anyway, but we have to be extremely careful.
 
user54412
I actually wonder if some mathematician has figured out the right way to evolve tensors numerically, yet no one in physics or engineering has read the poor person's neglected thesis.
 
@obe you have issues
@ChrisWhite Hmm, interesting!
Sounds like a mission for thesis-topic searching me in a few years
 
obe
@0celo7 we already agreed on that...
 
user54412
@0celo7 If no one has done it (and certainly no one I've spoken too has heard of such a thing) it would be an extraordinary breakthrough. I'm not even exaggerating -- solving this problem would get you instant job offers from hundreds of research groups and industrial teams.
 
@ChrisWhite Hmm
 
2:40 AM
Do you currently just reimpose the constraint after a few steps, or what do you do?
 
German outta nowhere
 
user54412
@ACuriousMind You clearly didn't read my paper ;)
 
Current goals in life:
Get some form of PhD
Tell Zee his QFT book is shit
Tell Weinberg his explanation of cluster decomp is shit
Learn analysis
That's pretty much my bucket list.
@ChrisWhite Link?
I'll save the pdf to my iPad and read it when time permits.
 
user54412
You can project onto a divergence-free solution after each timestep, which amounts to doing a global elliptic solve akin to poisson's equation. Or people figured how to achieve similar results with parabolic or even hyperbolic operators. Parabolic damps monopoles away, but kills your timesteps in the courant condition. Hyperbolic is best from a performance standpoint, but it introduces unphysical waves carrying monopoles off your grid.
 
user54412
Alternatively, you could evolve the vector potential itself, though this comes with all sorts of subtleties about gauge choice.
 
user54412
2:45 AM
Or you could do crazy prestidigitation with your discretization scheme.
 
user54412
@0celo7 its just this one; bottom of page 2 I (very briefly) summarize what people do, at least in relativistic codes
 
user54412
the references show that people have been worrying about this for 40+ years
 
is that your PhD thesis?
or is that still in the wind
 
user54412
It's the numerical basis for my thesis. Certainly the most time-consuming part.
 
user54412
No amount of math or numerics without applications will get me a degree -- my thesis committee has made that abundantly clear.
 
2:48 AM
Do they like you?
That might be a stupid question
But it would be something I'd worry about
 
user54412
Let's put it this way: my adviser (who's really nice) said I should have tough people on my committee to balance things out. And whenever I tell people in my department who they are, the response is "wow, they must ask really tough questions."
 
Is Stone your adviser?
 
user54412
yes
 
@ChrisWhite It is not just an error propagation issue.
This is a very fundamental issue about the difference between noise and not noise.
Suppose I have a process such as the emission of radiation from a black body.
This process has certain statistical properties.
One way to describe these properties is through the power spectral density.
We typically denote this $S(\omega)$.
This function is related to the correlation function of the process.
Call the process $x(t)$.
 
user54412
But this is just the ... two?... point correlation, right?
 
user54412
3:00 AM
For any non-gaussian statistical properties there's more to be learned from higher-order correlations?
 
user54412
(I'm phrasing this in cosmology terms, not sure if it makes sense outside that field)
 
Then it turns out that $S(\omega) = \int (d\omega/2\pi) \langle x(0) x(\tau) \rangle \exp[-i \omega \tau]$
where the average is over realizations of the process.
@ChrisWhite Yes, more or less.
@ChrisWhite I believe that is correct.
 
user54412
---
Apparently I'm missing Einstein-related festivities in Princeton right now (100th anniversary of GR). Not just talks, but independent films, a theatrical play by Brian Greene, a performance by Joshua Bell, ... Wouldn't surprise me if there's a look-like-Einstein contest.
---
 
@ChrisWhite: Now here's the thing everyone forgets: If you actually record a realization $x(t)$ and compute it's power spectrum, it will not be exactly $S(\omega)$.
$S(\omega)$ is an average, and there are fluctuations about this average for any one realization.
 
user54412
That makes sense. I think.
 
3:10 AM
You can actually compute things explicitly! Check this out:
 
user54412
@DanielSank Is the integral over $\omega$, or should it be $\tau$?
 
2
Q: What is the statistics of the discrete Fourier transform of white Gaussian noise?

DanielSankConsider a white Gaussian noise signal $x(t)$. If we sample this signal and compute the discrete Fourier transform, what are the statistics of the resulting Fourier amplitudes?

@ChrisWhite Oops, definitely over $\tau$ and without the $2 \pi$.
@ChrisWhite: the Fourier transform $\tilde{x}(\omega)$ of a white noise signal is a Gaussian distributed complex number.
It turns out that this means that the mod square of the Fourier transform is exponentially distributed.
So now suppose you want to generate a realization of so-called black noise (black body radiation noise).
You have to generate your frequency domain data according to the Planck law, but with the fluctuations built-in. In other words, the mod square of each frequency component should be drawn from an exponential distribution with the mean determined from the Plank law!
And, if I remember all this correctly, the phases should be uniformly random.
 
user54412
For the phases, that sounds ok. Though in the end the simple theory of human hearing is that we don't distinguish relative phases between frequencies anyway. (There was a really good post here that linked to a claim that that's not quite true -- can't locate it now.)
 
user54412
@DanielSank But what happens if we don't do this?
 
@ChrisWhite I don't know, but surely the statistics of the resulting noise realization won't be right.
@ChrisWhite if you use enough samples in frequency space it may be that the noise in the Fourier amplitudes doesn't matter much, now that I think about it.
I'm just not sure.
@ChrisWhite We should do an experiment.
 
user54412
3:34 AM
I like the sound of that.
 
user54412
I also like the taste of food, so I might bow out for a bit.
 
signals is strange
 
3:56 AM
things can only be as strange as The Evidence suggests :P
::looks around for The Evidence::
 
 
1 hour later…
 
2 hours later…
7:33 AM
@JohnDuffield When I was reading Purcell's Classical EM book, I was under such an impression that fields are more fundamental than charges (and what we exactly measuring really), and really left me wondering if it is all about fields changes obeying some kind of laws (such that makes us think there are charges)
 
@HDE226868 .. My logic. I f you look the old horse power definition you will find my logic; en.wikipedia.org/wiki/Horsepower#Definitions_of_term if something happens in certain time, it just need a certain power. And this power need certain amount of energy. And energy just don't come "somewhere". I am challenging the LOD change be searching this source
 
7:53 AM
; If 25.4 TW change is happening with 47 TW (x0.3 through mass) source or with 200 TW source, which would you accept? physics.stackexchange.com/questions/214042/… with variable energy source must be prepared to instabilities; which makes this question very interesting; physics.stackexchange.com/questions/216411/… I hope you find it worth re-opening.
 
8:15 AM
@Shing : IMHO you should be a little wary of Purcell, there are some issues with it. But yes, I would agree that the electromagnetic wave is more fundamental than electromagnetic charge. We make electrons and positrons from photons in gamma-gamma pair production. We can diffract electrons. And in atomic orbitals "electrons exist as standing waves". Standing wave, standing field. The wave nature of matter is not in doubt.
@0celo7 : now it's -6, even though I refer to Einstein and WMAP and more. It's a demonstration of the downvote problem we have here at stack exchange. Do not take comfort from it.
 
 
1 hour later…
9:43 AM
@JohnDuffield It merely indicates that most people on the site think that you don't know what you're talking about.
 
merely strongly
 
Sorting by average post score is quite telling
 
telling of what?
 
(sort it in ascending order)
 
:O
3rd place
what a surprise
:P
 
9:52 AM
Also note the % of posts that got any upvotes at all
 
noted
 
For most >3k rep users it lies ~80% or higher
Lubos has 97.8%
 
Sorting by # of posts places John right next to Sofia...
 
she was an outlier with a different intention
Wow! both have been down voted for two days for -50 each
 
10:34 AM
Can you check SE for number of downvotes and upvotes rather than reputation?
 
10:52 AM
 
11:37 AM
Is the limit $c \rightarrow 0$ of a torus ($c$ the radius of the torus to the center) a sphere?
 
seems so, as a sphere is a degenerate case of a torus
It should be able to be proved by writing out the equation of a torus and then set the major radii c to zero, and you should recover something like $x^2+y^2+z^2=r^2$
Yup, setting the major radius R to zero give you the parametric form that coincides with spherical polar coordinates, which the other params can be eliminated to give the cartesian equation of the sphere
 
12:17 PM
Good thing I have that Mathematica program to compute Christoffel symbols
 
what's your current CTC project?
i.e. what CTC spacetime metric you are computing atm?
 
$S\times S \times \mathbb{R}$
 
Torus x line?
 
Yep
More specifically $(S^2 \# T^2) \times \mathbb{R}$
 
where is the time component pointing in this metric, is it along one of the circular bits in the torus?
 
12:25 PM
Nope, time is just $R$
Nothing too fancy
 
i see
so if that's the case, it means the torus part is spatial components only and I don't see how you can get a CTC from this metric
 
It is in several steps
 
# is connected sum?
 
yes
 
i see
 
12:40 PM
What does S^2#T^2 look like
 
Iam guessing...
and since I cannot get something that looks like a CTC, the drawing must be wrong
$S^2$ is a sphere and any 2-manifolds connected sum with a sphere gives a manifold topologically <insert word> itself (because the sphere acts like an identity in #)
 
Exactly. So why bother putting it on there
Homeomorphic
 
yes, that's the word
 
The bird is the word
 
Because of the SEMANTIC you dolt
A wormhole is generally defined as a topological handle
Also ugh I have rational functions of trig functions
The horror
 
12:47 PM
How's the Ricci scalar coming?
 
One thing at a time
Hm
I guess technically I don't need all that jazz
The basic idea was to have a wormhole on a sphere
But I wanted it to be quite wormholesque
So the path on the inside was shorter than the path on the outside
But for that I need a nowhere vanishing periodic function such that one half is smaller than the other
 
One thing at a time?? What the hell happened to your PDE
 
And $(1 + \frac{1}{2}\sin(\theta))$ is a bit of a pain to deal with
@0celo7 : So it turns out the PDE is a slightly worse version of Mathieu equation
With which I already tangled
And it did not work out so well
 
Did you ask on MSE or PO?
Or even MO?
 
Maybe I should yeah
I mean I specifically bought a book on Mathieu function to deal with this
But not much luck
The problem is basically that the Mathieu function is usually only defined for very specific values
And I need the solution for arbitrary values
 
12:56 PM
Solve it for general values and get a PhD out of it, then
 
*Reading it now* Ah I see, I thoughout you are working in 3+1 spacetime, (whcih is why I end up drawing a 4D projected sematics)

But anyway, now that I know I get the wrong sematic and the actual picture is basically a handle attached to a sphere, I still cannot quite find where the time component is pointing.

You said time is just $R$ here which is a line, and if we want to make CTC we need to be able to loop the time component back so that it forms a closed curve. Is the time component forming a loop by running along the handle?
 
@Danu : er no it doesn't, because what I'm talking about is what Einstein said.
 
@Secret : Recall that you can generate CTCs from wormholes just by accelerating one mouth
 
O I see, I forgot the relativistic factor...
Ok so if we have wormhole mouths at two different times, then after passing form one end and then go via the long way back to the entrance mouth, then it is the same as going back to the past
 
1:04 PM
@skillpatrol : yep, downvoted for telling you what Einstein said, by the guys who will tell you all about wormholes and the parallel antiverse.
 
@JohnDuffield Drop it with that Einstein quote.
He either misspoke or didn't know what he was talking about.
 
No. Einstein knew what he was talking about.
 
Dude. Stop appealing to 100 year old authority.
Even if you're correct, which you aren't, you're never going to convince anyone with this. You need to show me where my math is wrong. Simple as that.
I don't understand why that's so difficult to comprehend, @JohnDuffield .
 
You stop appealing to a 30 year old authority. I showed you where your math was wrong, in your definition. You said a spacetime is said to be isotropic if at each point there is a congruence of timelike curves. Then you used that to "prove" that homogeneous isotropic space (not spacetime) has constant curvature.
 
"Prove"
It's a rigorous proof. What is wrong with the definition?
 
1:19 PM
The problem is that he does not know what it means
 
What's wrong with the definitions that they talk about spacetime rather than space, and elevate abstraction above reality. A better definition1 would say something like space is homogeneous if its metrical qualities are the same at all locations. In that situation there's nothing to cause a light beam to curve.
 
Lol you really don't understand GR!
You're mixing up spacetime and space XD
 
Now I see where (one group of) the CTCs came from
 
Do you
 
0celo7: no, you're mixing up spacetime and space. Curved is not some combination of curved space and curved time. It's a curvature in your plot of those metrical qualities. For example you place optical clocks at various elevations and plot the clock rates. Your plot is curved, but space isn't. Instead the inhomogeneity of space is non-uniform, such that space gets less inhomogeneous the higher you go.
 
1:28 PM
I'm not sure I do now!
 
So we should be able to get a family of CTCs depending on how we accelerate one of the mouth relative to the other, and the different worldlines that mouth take will give a different CTC,

To be checked with the maths...
 
chat.stackexchange.com/transcript/message/25175866#25175866 is still correct; this all just shows that the (large!) majority of people are not impressed by your references to Einstein or others, because they think you don't know what you're talking about.
 
@0celo7 : and there's a reason why those optical clocks don't tick at the same rate.
 
My guess: I don't think there are CTCs that are geodesics here, because an acceleration is needed to 'displace' the mouths in the time coordinate
 
@Secret : the thing to appreciate about CTCs is that you don't travel along a worldline. A worldline is an abstract thing that models your motion through space over time. It's a line in spacetime, and spacetime is a "block" universe that represents space at all times. It's static.
@Danu : what it shows is that there are 17-year-olds etc who treat some 30-year-old textbook like it's a bible, so much so that they declare that Einstein "didn't know what he was talking about".
 
1:33 PM
@Slereah If a CTC is a geodesic, how will the geodesic equation reveal that?, i.e. what terms am I expect to appear and how are they arranged?
 
@JohnDuffield You can keep telling yourself that all your life; it won't gain you any recognition.
 
@Danu : shrug. What it will do is tell those 17-year-olds who think they know better than Einstein, that they don't.
@Secret : you don't travel around a CTC either. See this:
 
Easiest way is just to look at a closed geodesic and check if it's timelike
 
@Secret : re the above, and suppose there was some CTC that was 24 hours in circumference. It isn't anything like Groundhog Day. You don't go travel round and round the CTC reliving the day time and time again. Your worldline is 24 hours long. Your life is 24 hours long. And causeless. It's more like Mayfly Day than Groundhog Day, where you're born from your own egg or somesuch similar nonsense.
There is no way you can move such that everything else not only moves back to where it used to be, but never moved at all.
 
1:51 PM
0
Q: Is a schematic type question acceptable on this site?

count_to_10As a completely self studying student, with no friendly post grads around when you need one, I wonder is a question of the format outlined below acceptable here: An example of what I mean is: I currently understand say, the basic role of the Lagrangian in QFT and the math behind it. From there I...

 
@Slereah
Attempt failed
I am not good at solving ODE of this type...
Will investigate later when I have time
 
@Secret Dude, drawing formulae like that can't be easier than TeXing them or handwriting them.
 
My tex typing is still slower than my writing, thus not today (unless it is short)
(PS K is an arbitrary constant)
I have only a few minutes before I must get back to spectroscopy stuff
Wish I can spend more itme analysing CTCs
 
But your tex cannot possibly be slower than that!
 
I am slower on average because I keep making typos with the $$ and fonts and matrices
it's the typos that slow me down, causing me need to first type it in the MSE answer box, then copy paste to here
 
2:03 PM
No, you need to just bite the bullet and work to improve, it'll be worth the small time investment
(note that I am wayyy too into TeX)
 
I will, my hounours project will give me more chance to practice because they recommend me to type my thesis in latex
 
Yeah, thesis typing is a good exercise :)
 
Help
My metric is becoming a swamp of trig functions
 
2:19 PM
Pics or it didn't happen
@JohnDuffield There are 17 year olds in here?? This is no place for children
 
There are 15 year olds in the math room
 
People like @ACuriousMind are way too profane
 
and a 65 year old math prof from MIT teaches them multivariable calc from his textbooks
 
2:39 PM
Anyone have a good way to remember that $\sqrt{2 \alpha}$ is the coefficient in the bosonic string wave solution $X(t,\sigma) = x_0^{\mu} + \sqrt{2 \alpha} a_0^{\mu} t + i \sqrt{2 \alpha} \sum_{n \neq 0} \frac{a_n^\mu}{n}e^{-in t} \cos(n\sigma)$?
 
@skillpatrol 1) those are smart individuals 2) they don't have hooligans like @ACuriousMind and @Danu over there
 
1) True 2) no comment :P
 
I prefer to be referred to as "real mothaphucking G"
 
G = ?
 
Damn, I didn't manage to get the spelling right.
 
2:52 PM
you see the cap he's wearing?
OG
O = Original
:D
 
@Danu No, you're a hobo homeboy hooligan
@skillpatrol gangster...
@JohnDuffield I still don't get how you can, with a straight face, tell me to stop using a 30 year old book when you quote 100 year old material!!
@JohnDuffield And other books such as Straumann (2013) use similar definitions.
 
@0celo7 let it go
 

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