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8:00 PM
A node like that could split into a pair of branch points under a perturbation e.g. $x^2-y^2=a^2$. I presume that to be the generic case, and the node surviving said perturbation to be nongeneric.
But I don't know what the terminology for the node to 'survive' a given perturbation is.
 
Because this doesn't work in any field, does it ? @Tobias
 
@Astyx Sure it does, you just need the right topology
 
Right, @Semiclassic. I'm just saying that to me saying "the singular point $(0,0)$ is stable under the perturbation" means that the point itself stays singular, not that it moves.
 
Yeah, I understand.
Question is whether there's a proper terminology for that.
 
I would say something like "perturbation among curves with nodes" ...
Consider a family of curves with ordinary nodes ...
 
8:01 PM
You would say that.
 
@MikeM: Do you disagree (seriously)?
If you say a singular point is stable, what does that mean?
 
Nah.
 
@Tobias What topology would that be in, say, $\Bbb Z/p\Bbb Z$ ($p$ prime) ? I'm intrigued
 
The usual differential topology language is that a property is stable/generic.
 
I'm just agreeing with you.
 
8:02 PM
@Astyx The Zariski topology
 
Oh, ok ...
 
@Ted I don't get what you mean
 
Forget about it, Astyx.
 
Let me look that up :) @Tobias
Ok
 
Trying to get to my hotel via london transit before my phone dies.
 
8:03 PM
Good luck!
Stop chatting.
 
indeed
 
The specific case I've got consists of a family of curves with parameters $g,\gamma,E,x$.
 
$x$ is a parameter? seriously?
 
by physics standards that's perfectly fine
 
8:04 PM
Hrm, yes it is in this context.
 
LOL
 
Which is rather silly
 
Not when I'm writing equations of plane curves it's not.
 
What do you expect me to do for the next hour?
 
In the defense of the preprint I'm reading (It's their notation)
The variables on the curve would be $(t,\epsilon)$
 
8:05 PM
Oh good grief
 
i wouldn't be surprised if $\slashed{\phi}_{ijk}^{lm}$ was a parameter instead
 
And they're not doing any plane curves, I'm bringing that in myself.
 
@Balarka: Go finish Gauss-Bonnet.
 
But yeah, for the purposes of this conversation it's rather silly.
 
meh, I won't fix this
 
8:06 PM
Hence, I'll instead say I've got parameters $a,b,c,d$. :)
(They also have $e$ as a parameter. Even I can't abide that.)
 
It seems like you have too many parameters for a hyperelliptic cubic.
 
I'm going, good day to everyone
 
Bubye, @Astyx
 
Eh, it's more symmetric than you'd think.
 
Anyhow, I'm leaving in a few minutes for lunch. So get to the punchline.
 
8:08 PM
@TedShifrin Alright, thinking about it.
 
It's the characteristic polynomial in $x$ of the matrix $$\begin{pmatrix} a-y & 0 & b c & d \\ 0 & a+y & cd & b \\ bc & cd & 1 & 0 \\ d & b & 0 &-1 \end{pmatrix}$$
 
@Semiclassic: Did you mean for it to be almost symmetric but not?
Hi, DogAteMy.
 
Fixed.
 
OK.
 
8:12 PM
When $c^2=\frac{1-a}{1+a}$, the resulting curve $f(x,y)=0$ has a singular point.
 
Now what?
So you want to perturb along that hypersurface in the parameter space?
 
Yeah.
 
OK, no problem.
You could explicitly substitute $a=a(c)$ and get rid of one parameter.
 
And I want to know how one refers to the fact that the curve remains singular along that line.
...which, maybe one just says that.
 
Not line. It's a hypersurface.
Yup, you just say that.
 
8:13 PM
Right, I've got b,d still.
 
This is analogous to the discriminant subvariety which parametrizes multiple roots.
 
Right.
 
So we're done for now? :)
 
I'm interested, then, in perturbations which preserve singularities of the curve.
 
No, that suggests that the singular points don't move.
Which preserve the singular nature of the curve.
 
8:15 PM
Hmm, okay.
 
Language is subtle.
I'm out of here for now. Back later.
 
I'd say "perturbations which preserve the singular-ity of the curve" except that one already has "singularity" as a noun not as an adverb.
later, @ted
 
does induction work for statements about matrices?
 
@Socrates You could do induction on the dimension $n$ of a matrix, yeah
 
(not adverb. I should've said: "singularity refers the points on a curve, not to the curve itself.")
 
8:24 PM
@Krijn for a practical example that's how you usually prove that symmetric real matrices are diagonalizable
 
Hello chat
 
@AlessandroCodenotti Linear algebra seems ages ago, it was so much fun tho
 
I've said it before, but I always find it a bit funny how 'linear algebra' means different things depending on what level you're talking about.
 
everything is linear algebra
2
(which explains why i am bad at everything)
 
To a high-school student, linear algebra would be "simultaneous systems of equations." To a college student taking an intro course (not a full one), it'd probably mean "matrices." And to someone taking a serious course in linear algebra, it'd be stuff like vector spaces.
 
8:28 PM
on a more serious note, i really need to get some of my linear algebra straight: i don't really use a lot of linear algebra.
 
I use certain parts of linear algebra a lot.
Eigenvalues-eigenvectors, diagonalization, etc.
 
I don't really use it because every time it comes up the prof will wave his hands and say "this is just linear algebra"
 
with linear algebra do you mean finite dimensional linear algebra?
 
And there's stuff which I don't say a lot but which I know is there, e.g. null space. (An eigenvector, for instance, is nothing but an element in the null space of a particular matrix.)
 
@Semiclassical yeah, that's the kind of thing i don't use
 
8:32 PM
@KajHansen hi, how is it?
 
Can't do quantum mechanics without eigenvalues/eigenvectors.
 
does anyone actively use that?
like that theorem
 
btw if I'm looking a space $C$ of maps $X\to Y$, whats the topology called that makes all the evaluation maps $ev_x: C\to Y$ $f\mapsto f(x)$ continuous?
 
Which theorem?
 
or rather fact... doesn't really deserve "theorem"
@s.harp pointwise convergence?
 
8:34 PM
@MikeMiller huh, right that makes sense as a name
 
the new neighbors are making hella racket.
 
Functional programmers, huh?
 
i dunno what they are. having a party it seems
 
back to advance wars til i get there i guess
 
It was a joke if they're making "Hella Racket"
 
8:36 PM
can't much work
 
i wish they'd just conk out after drinking to their fullest
 
I finally broke down and downloaded VBA-M so that I could play advance wars.
 
cool
 
I then got a bit annoyed with it and decided to download Castlevania: Aria of Sorrow instead :)
 
@Daminark ah i see
@Semiclassical traitor
 
8:39 PM
lol
 
I'm going through the war room in aw2
 
Hi, i got a question im not sure of:
Let F be a field. i need to prove that in the ring $F[x,y] $ $f \in (x,y) $ iff $f(0,0) = 0 $

Assuming $f \in (x,y) $ then $f(0,0) = a_{0,0} $ why does $a_{0,0} $ must be zero?
 
Sie
8:54 PM
So in the context of sets what is the appropriate way to say inbetween? The way I've been doing it is B = { x|x ϵ 1-100 }. Is that acceptable or is there a proper way to do it?
 
@MikeMiller Have you ever saved both the T- and B-copter in the Green Earth mission? I can't seem to be able to do it
(was replaying that one)
 
@Sie $B=\{x\in\mathbb{R}|1\leq x\leq 100\}$ or with N, if you want integers
 
nvm, did it
 
In the context of blowing up singularities, does anyone know what is meant by $\mathcal{O}(-2)$?
 
9:06 PM
It's the cotangent bundle over $\Bbb P^1$
Equivalently tensor product of the tautological line bundle with itself
 
@BalarkaSen Thank you :) Can I ask why the notation is as it is?
Oh I see
 
If you take a generic section of it as a real 2-plane bundle, it intersects the zero section at two points, with opposite orientation each
aka the zero section of the underlying 2-plane bundle has self intersection number -2
or it's a bundle with Euler class -2, whatever you want to call it
 
I'll go with the Euler class then, I'm more differential geometry minded :)
 
Me too :)
 
@BalarkaSen On an unrelated note: Would you by any chance know of any resources you could point me to that discuss how to compute the period matrix of an algebraic variety $X$ defined as the zero set of a polynomial, which is a smooth manifold?
 
9:12 PM
I don't really know what a period matrix is. But you can wait for @TedShifrin, who's the resident complex algebraic geometer/differential geometer here.
Also I misread your previous "differential geometry" as "differential topology". I don't really know much about the former :P
 
@JamalS You might look at Carlson's 'Period mappings and period domains' book. The first chapter, at least, is pretty readable.
 
@Semiclassical Thanks, I'll have a look.
 
@BalarkaSen The period matrix of a smooth genus-g curve has matrix elements $\int_{\gamma_i}\omega_j$ where $\{\gamma_i\},\{\omega_j\}$ are bases of cycles and co-cycles respectively.
 
@Semiclassical Yes, I'm aware of the textbook definition so to speak, it's just that evaluating it by that means is not always possible, or at least not the easiest way.
 
Don't I know it.
 
9:18 PM
Hehe
 
@Semiclassical Ah
 
The main tool I know is to find the Picard-Fuchs equation for the given elliptic curve and solve the resulting ODE.
That only works in cases where you've got a family of Riemann surfaces parametrized by a parameter, though, and even there it can be pretty hard to actually find the Picard-Fuchs equation.
 
Hi
Can someone help me understand how to go from the first equation to the second - imgur.com/a/tH7Gh ?
 
@JoeSlater You can work backwards, using the formula for the sine of a sum.
The phase shift is physically meaningful, and perhaps it's better if you understand this in the context of RLC circuits, as in your problem; Young and Freedman have a good section it.
 
It may also be useful to compute $e^{i\phi}=\cos \phi+i\sin \phi$ given that definition of $\phi$.
 
9:30 PM
Ok thanks. I will try to read more about it. But I am not able to see how using the eulers formula or formula for the sine of sum is useful in this case.
 
Say, should I delete this? :
-12
Q: Interesting patterns to the algebraic solutions of polynomials

Simple ArtIn yet another attempt to find the solution to the quintic polynomial, I started looking backwards at the solutions to the quartic, cubic, quadratic, and linear polynomials to see if I could pick up any patterns. $\left\{ \begin{aligned} 0&=ax+b \\ 0&=ax^2+bx+c \\ 0&=ax^3+bx^2+cx+d \\ 0&=ax^4+...

 
Keep in mind that $e^{i (\omega t+\phi)}=e^{i \omega t}e^{i \phi}$.
 
:D Euler's formula
 
So you can write $\sin(\omega t+\phi)$ using Euler's formula, and then compute $e^{i\phi}$ from its definition.
 
@SimpleArt could you even, if you wanted?
 
9:39 PM
@Socrates Yes, I definitely could, but I do not want to do so rashly
 
@BalarkaSen one question was titeld "doubt in linear algebra" for what it's worth lol
 
hi guys
 
@TedShifrin When you have time on here, could I ask a question about period matrices?
 
@KasmirKhaan Hi!
 
in a tripple integral when we have x+y+z = 1 to define a region
and when we have it as function
can i set it to equal 1 and integrate?
tripple integral of 1/ (1+ (x+y+z)^3 , over the region x=0 , y=0 ,z=0 and x+y+z=1
my question is if we can replace x+y+z with 1 and get 1/2 as integrand
 
9:46 PM
@JamalS What kind of curve do you have, out of curiousity?
 
@Semiclassical I actually don't have a particular one in mind; the question is motivated by reading I'm doing into the Kawazumi-Zhang invariant of a Riemann surface, which turns out for certain genera to be written as a Fourier series in the period matrix.
 
Ah. Yikes.
 
In these cases, I believe it can also be related to the Faltings invariant.
 
The only cases I know how to calculate turn out to be (generalized) hypergeometric functions
 
anyone can help me plz?
 
9:49 PM
@Semiclassical Do you have a resource to point me to on that? Sounds interesting too.
 
@KasmirKhaan While I may be able to do random integrals with complex analysis, that's just a side thing, and I can't do triple integrals (at least not very well)
 
It's a survey, but you might appreciate this: maths.ed.ac.uk/~aar/papers/kontzagi.pdf
See 'Chapter 2' in particular.
 
@KasmirKhaan No, because the volume that you are integrating over is bounded by several surfaces, one of which is the plane $x+y+z=1$. On this plane, the equation holds, but your integration includes points in the interior (after all it is a volume integral) that do not satisfy, $x+y+z=1$. Does that make sense to you?
 
yes we get like level surfaces
or planes
@JamalS thank you ! :)
 
Hi, in $F[x,y] $ is it correct that $(x,y) = \{ f_1 *x + f_2 *y : f_i \in F[x,y] \}$ . (im not sure if that is the definition)
 
9:56 PM
how to integral 1 / (1+u^3)
 
@KasmirKhaan Oh, wait, I got you!
The answer to your question is in my top questions list
18
Q: Evaluate $\int\frac1{1+x^n}dx$ for $n\in\mathbb R$

Simple ArtI was wondering on how to evaluate the following indefinite integral for all $n\in\mathbb R$. $$\int\frac1{1+x^n}dx$$ It seems to be peculiar in that we have $$\begin{align} \int\frac1{1+x^{-1}}dx&=x-\ln(x+1)+c\\ \int\frac1{1+x^0}dx&=\frac12x+c\\ \int\frac1{1+x^{1/2}}dx&=2\sqrt x-2\ln(1+\sqrt ...

:D There you go @KasmirKhaan
 
@SimpleArt thank you sir! :)
 
@KasmirKhaan If you want to go through the algebra, you should use PFD with $u^3+1=(u+1)(u^2-u+1)$ with an arctangent integral.
 
@KasmirKhaan In general, $\int \frac{dx}{1+x^n}$ is $x \, \, {}_2 F_1 (1, n^{-1}, 1+n^{-1},-x^n)$.
 
lol
 
10:01 PM
thank you again but that is way to hard for me at this point =p
 
@JamalS Could also just take geometric series if one is headed that way
 
Hehe
Actually, the fun way to do this integral is Risch's algorithm ;)
 
are these algorithms easy to learn ?
 
Noooooooo
 
because we are doing many integrals ><
 
10:02 PM
The Risch algorithm requires some mathematical preliminaries other than calculus and takes 100 pages to cover a summary of it.
 
LMAO!!!!!!!
@KasmirKhaan I feel you though :P
@JamalS That is why we have WolframAlpha and such
 
haha okay ill keep using what I know
 
It's definitely worth knowing the details though; I always like to know what my tools are doing. Furthermore, it can be used to prove in certain cases that no closed-form exists, which Mathematica won't do for you.
 
Lol
If it looks solvable, but Mathematica doesn't give an answer, I conclude it doesn't exist @JamalS
 
Yeah, but we know that's not always the case.
 
10:04 PM
Yeah, that won't fly in a grad-level physics class :)
Lots of hard integrals which are best handled by citing a table of integrals.
 
I always feel like I've cheated if I've used a table, though if I'm doing an immense problem where the integral is the least of my worries, then not so much :)
 
@JamalS Wolfram and mathematica are my table of values
 
@SimpleArt Yeah I use Mathematica a lot
It's fun to just play around with it as well
 
;) yup
 
@TheGreatDuck that's why i deleted
you know, it has a reason why I deleted :P
 
10:13 PM
@Socrates which I posted before you deleted. Otherwise, I couldn't tag you.
 
ah
makes sense ;)
I can not really say what's your question?
 
huh?
how does one prove proof by contradiction doesn't work?
 
do you seek a proof that fails only because we look at the equivalent contrapositive?
 
huh? is the question @Socrates
 
@Socrates i don't understand. We try proof by contradiction and it fails either because the original statement is false or because the statement is not provable. How does one prove it's the latter and not just lack of ability of the prover to find the contradiction?
 
10:17 PM
@TheGreatDuck Reminds me of proof by exhaustion
 
can someone explain to me how even and odd functions work when we integrate
 
I think those are called conjectures
and it would be really cool to have a way for your question, but obviously this way doesn't exist. Or why are there still conjectures?
 
@KasmirKhaan $\int_{-a}^aeven(x)\ dx=2\int_0^aeven(x)\ dx$ and $\int_{-a}^aodd(x)\ dx=0$.
 
i meant more like
is the product of even and odd = ?
and such things
does it work like normal even and odd with numbers?
 
$even\times odd=even$
lol, just like numbers XD
 
10:19 PM
okay thank you =p
 
Oh wait, even times odd is odd
Oops, it's backwards, my bad
 
we did not prove this
omg dont comfuse me
 
You just check this:
 
am allready comfused
check what ?
 
$$\text{even}(-x)\times\text{odd}(-x)=-\text{even}(+x)\times\text{odd}(+x)$$
So it is odd.
 
10:20 PM
@Socrates what...? We can prove that contradiction shows independence in the case of the parallel postulate of geometry. Or do you claim otherwise? Surely there was a method used in that?
 
@TheGreatDuck but there is no(known) method for all conjectures, if there was, we wouldn't have conjectures.
Suppose the following: i try to prove Riemann Zeta by disproving the contradiction. Now I fail, but does it mean that Riemann Zeta is true(or indeed false)?
The fact that anyone tries and fails says absolutly nothing
If there where a method to show that it's only my lack of ability, then Riemann would be proven
 
@Socrates Yes it does
It says that the first one to do it will probably get rich
 
fair enough
Russians tho, tend to disagree.
 
Lol
Fair enough
 
my conjecture: if all 7 billion humans on the planet would sit down to solve math, we would have went from the mathematical stone age to feudal age
 
10:28 PM
@Socrates We'd probably all die though
 
I survived till now, because someone else gave his life, not even knowing me.
 
@Socrates who, cause if I read that right said person did know you.
 
@Balarka Level 6 or whatever? Doubt it.
 
If some soldier dies to save the lifes of his country, he saved my life, but he (probably) didn't knew me.
 
10:41 PM
ah
i thought you were making a religious reference
nvmd
 
ah, no thanks Jesus^^
 
@Socrates regarding your point, we don't have algorithms to find all possible solutions to differential equations with closed forms. We don't know how to reduce any given number into it's factors without brute force. I'd argue that we know how to solve some of them and reduce many of them by memory. Surely a method exists. Whether it applies to everything is obviously expected to not be the case.
However, I'd imagine that one was able to prove the parallel postulate was independent therefore, some kind of method exists for at least some statements and situations.
 
@TheGreatDuck We have differential galois theory though
 
huh?
 
Hi all, I'm looking for a confirmation on an attempt to answer a question of mine. It concerns the estimation of mean value of a function of random variables. @Batman provided me with precious info, but it would be nice if anyone else could also take a look. Could you check Second attempt? Thank you very much.
 
10:46 PM
@SimpleArt I don't follow?
 
Hi, I just looking for a solution manual for Folland real analysis, Is there a free link??
 
You said that there is no algorithm to find all possible solutions to differential equations, so I said differential galois theory @TheGreatDuck
 
thanks for your help...
 
@SimpleArt fine then. What is the solution to y'' + 2floor(x)y' + floor(x)^2y = 0?
or better
y' = e^{x^2}
thought the latter has none
that we can physically but on paper
 
@TheGreatDuck I didn't say it can solve all differentials, but I do can tell you the latter can be shown to have none
with DGE
 
10:51 PM
no
i meant FINDING the solutions
 
the latter has one, if I remember, or it was $e^{-x^2}$
 
not determining if they exist
 
@TheGreatDuck :| But if they don't exist, what am I supposed to do?
 
@Socrates perhaps the latter. the first is the textbook example.
@SimplyBeautifulArt that's why i said ONLY the one's that exist. but you still have to find it using the algorithm. I'm merely saying nonexistent things give any result. Don't worry about the case of no closed form.
 
10:53 PM
well
depends on what you mean with solution
 
it's just an analogy
things work sometimes and sometimes not
 
@TheGreatDuck Idk, perhaps you could try the Risch algorithm
 
and since someone has done it in the past
 
in my physics class we weight paper to measure the integral
 
there must be a way to prove a statement is unprovable
 
10:54 PM
was accurate
 
(and uncontradictable)
i.e. neither true nor false
 
no, some statements are true, but unprovable
some statements are just nonsense
think about it this way: can you prove to 100% that the universe didn't start 5 seconds ago?
 
@Socrates Yes, assuming the universe started some time ago
 
@SimplyBeautifulArt I don't think this is a valid proof
 
Then just warp the thing you call a "second" into what I call a "second", such that 5 of my seconds equals the beginning of the universe
 
11:03 PM
If we do that. Why does "think about it this way: can you prove to 100% that the universe didn't start 5 seconds ago?" not mean "Good day fellow, how are you"?
 
like i said
we're talking about math for starters
and also, the idea is "provable from what you are given"
 
Hi ! I want to know something
 
i think it's a bit bridging on absurd to bring in philosophical questions.
after all, we can then rule out everything as given
and then nothing is provable
 
Do you guys know from where does all formulas you know come from ?? Or you just know they are like that and dont know their origins ?
 
there is mathematical truth, because we can try axioms
that doesn't mean those axioms are good, it just means we can prove something
like the 5(?) axioms of euclid
he derived alot of that
 
11:18 PM
if $a^2+b^2=c^2$ and $(a,b,c)=1$ then one of a,b is odd and the other is even, and c is odd. Let $a\mapsto 2a$ then $a^2=\frac{c+b}{2}\frac{c-b}{2}$ and if a product of two coprime integers is a square then both are squares. Let $\frac{c+b}{2}=p^2$, $\frac{c-b}{2}=q^2$ then $c=p^2+q^2$, $b=p^2-q^2$, $2a=2pq$ which means all pythagorean triples are parametrized by Euclid's equation
I came up with that proof after this one didn't satisfy me en.wikipedia.org/wiki/…
 
what means (a,b,c)=1?
 
(x,y) is short for gcd(x,y)
 
ok
why can't all be odd?
 
odd^2+odd^2=even
 
ah -.-
yeah
 
11:38 PM
hi @TedShifrin how does the even and odd functions work in doing integrals
like if we multiplay odd * even what do we get?
does it work like normal numbers?
even *odd = even ?
 
Well, check it out. If $f$ is even and $g$ is odd, what is $(fg)(-x)$?
 
even
 
Huh?
Write it out.
 
g(-x) = -g(x)
 
And $f(-x)=$?
 
11:41 PM
f(-g(x)) = f(g(x))
 
We're not composing. We're multiplying.
 
oh okay
 
At least, you said you were multiplying.
 
yes i did
-f(x) g(x)
 
So even times odd is ?
 
11:43 PM
odd
 
And what is odd times odd?
 
even
hmm thinking about x and x^3
we x^4
so it is not like numbers =p
 
So the right analogy with integers is with addition, not multiplication. Can you think of a reasonable explanation?
 
oh that is good let me think
no i cant think of why
 
Look at the example you just did a moment ago.
 
11:46 PM
x and x^3?
well in power functions we add exponents
but how does it work with sin and cos
 
Well, note that the Taylor series for an even function has only even powers, and the Taylor series for an odd function has only odd powers.
 
oh yeah :D
so we can reduce it all to powers
 
@TedShifrin Can you point me to any resources on computing the period matrix of algebraic manifolds (specified as the zero set of a known polynomial)?
 
As a mathematician, you should try to figure out more of these puzzles.
 
yes i should =p but having hard time learning about the other new topics
and i got another question about periods
 
11:50 PM
No, @JamalS, I've never even thought about this. But what do you mean by a period matrix for a general algebraic variety? This is normally used for abelian varieties (so these are algebraic varieties that happen to be tori).
 
is it the same to go from 0 to 2pi and from -pi to pi ?
i know we go around once but is it a legal step ? :)
 
@Kasmir: If the period is $2\pi$, you can integrate over any period ... $[a,a+2\pi]$.
 
because that way i could use odd functions add up to 0 on symmetric intervall
 
Right.
 
Thanks Ted ! that would be handy :)
 
11:52 PM
@TedShifrin Well, an example would be the Burnside curve, $y^2 = x^6-1$ with automorphism group $S_2 \times \mathbb Z_2$; I'd like to compute, for example $\Omega$ for that curve.
 
Oh, you're talking about curves, so then it's the Jacobian variety of the curve which is the abelian variety.
You can probably do that bare-hands. What's the genus?
If you haven't looked at it before, you might try Phillip Griffiths's beautiful little book An Introduction to Algebraic Curves. He does a lot of concrete stuff in that book.
 
I think it's genus 2.
 
I think it's bigger than that. $g=(d-1)(d-2)/2$, no?
 
Ah, yes, sorry.
 
But look at Griffiths's book. He works out a lot of examples in there.
 
11:58 PM
I'll download it now, thanks.
 
Good luck. I've actually never done this sort of computation.
 

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