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r9m
5:04 PM
@robjohn I check the tags real-analysis, complex-analysis, inequality, integral-ineqs, sequence and series, integration and a few others .. I used to look at the new-questions tab but that mostly made my head spin 'coz there are so many questions coming in each second ! =P so I decided to check only the tags I like .. :)
 
@r9m Very simple. Just don't upvote another person more than 5 times a day. That is all.
 
r9m
@WillHunting ah ! okay :-)
 
@Hippalectryon How was your exam?
 
5:21 PM
@rehband Not too hard but I did bad :c
@rehband Want me to write the exam down for you ?
 
@Hippalectryon Sure
 
@rehband mathb.in/20184, i'll write the other questions while you start :)
 
@robjohn that step is exactly the thing I just did, but I didn't go further. I also have a drawing here ... that small contribution kills me.
 
@Chris'ssis which step?
 
$$\begin{align}
\sum_{k=1}^\infty\left|\,xf(kx)-\int_{kx}^{(k+1)x}f(t)\,\mathrm{d}t\,\right|
&\le \sum_{k=1}^\infty x[f(kx)-f((k+1)x)]\\
&=xf(x)
\end{align}$$
@robjohn exactly what you posted.
 
5:32 PM
@Chris'ssis @robjohn i'm writing the full test for @robjohn, so you'll be able to have a look at the in between questions in some minutes
 
@Chris'ssis Oh, my hint to Hippalectryon
 
@robjohn Yeap. There is a small contribution that seems hard to measure.
 
@Hippalectryon Thanks
 
@rehband Here more questions, still not done yet mathb.in/20185
 
@Hippalectryon I'm amazed you remember it so well
 
5:36 PM
@rehband xD I have the sheet under my eyes
 
@Hippalectryon Slightly less impressive then
 
I feel the need to share once in a while my opinion about @Hippalectryon. Who is @Hippalectryon actually? In my very humble opinion, @Hippalectryon is a professional, a good one! :-)
OK, I let him say he's just a kid, 11 years old or so ...
 
16 :P
 
@Hippalectryon OK, 16 ... :-)
 
@Hippalectryon I don't understand the integral bounds for the definition of $c_k (x)$
Is this an uni analysis exam btw. ?
 
5:42 PM
It's the really first exam of da year :P
@rehband Oh typo it's $x+k+1$ (upper bound)
 
@Hippalectryon Gotcha
It's quite hard for a 1st exam
 
1st exam of 2nd year of prep school
In France's best prep school
:D
 
I see
 
@Chris'ssis No, don't say I'm not there ;-)
 
U going to Ecole Polytechnique then?
 
5:47 PM
Lol not everyone in that school goes there :)
Each year we send about 100 people there
90-100
 
Ah okay
 
Half a sheet left :) mathb.in/20186
 
How much time did you have for this?
 
Ok
 
5:53 PM
half an hour? :-)
 
Lol Chris
 
Onwards to Part III (the one with the problem I gave you @Chris'ssis @robjohn ) mathb.in/20187
 
Thx
 
@DanielFischer do you know how to tackle @Hippalectryon's question? Asking just out of curiosity.
Initially I was tempted to say the limit is $A$, that was more of a rough approximation.
 
I think there is a typo in that question:
$\displaystyle\lim_{x\rightarrow\infty}=0$ ??
 
6:05 PM
Here, full exam minus the last exercise which is unrelated : mathb.in/20188 @Chris'ssis @robjohn You might wanna look at the end
@rehband Which one
 
@Hippalectryon Thank u
 
Fixed
 
Ok :)
Intimidating question hehe
I would attempt it but since Chris doesn't seem to have a solution yet, I'll let it be :)
 
@rehband Try the full exercise, it should be easier
 
@Hippalectryon Yea
 
6:08 PM
What I have to @Chris'ssis was a condensed version of the last question, because he's good and because I hadn't found it myself
 
Ok
 
Hahah Wtf
 
@Hippalectryon: I agree with that decision.
 
bashes @Nick
 
6:19 PM
So my amazon shipment got delayed because I removed the credit card details after ordering, lol.
 
Which sounds logical -__-
 
They said it can be removed once order has been placed.
 
But now they say it is better to remove it only when everything has shipped.
Anyway, from now I will leave it there until the items have arrived, then I will delete it for security.
 
It's quantum
 
6:21 PM
It's probably a bug in the system, so I don't blame them.
 
I love blaming. And bashing.
 
I intend to order all my math books from amazon from now on.
@Hippalectryon How old are you?
 
@Hippalectryon: Hey, I believe people are rebelious and would wish to find out what is hidden from them.
@WillHunting: 16
 
So @hippa is still in high school?
 
@WillHunting @Chris'ssis How old do you think I am ?
 
6:24 PM
61
 
@Hippalectryon I never guess. Do you have a girlfriend?
 
Lol
 
:O
@Chris'ssis me, not @ted
@WillHunting No time for that ;-)
 
Don't ever get a girlfriend
2
 
@Hippalectryon ;)
 
6:25 PM
@Hippalectryon OK. I am still deciding between learning French or German, lol.
 
@WillHunting Pfft, obviously German is the way to go
 
FRENCH $\mathcal{FRENCH}\mathbb{FRENCH}$
 
Just imagine being able to read Riemanns work in the original language
or Gauss, Landau,...
A lot of that hasn't been translated
 
Everybody wanna be french of course
Such charisma
 
@Chris'ssis First find out what the limit probably is. Taking $f(x) = \frac{A}{x}$, we see that the limit for that is $A\cdot \gamma$. Then to prove that that is the limit, I guess one can show that only the behaviour near $0$ is relevant, but I don't see yet how. It may take some fiddling with estimates. But there may also be a nice trick.
 
6:28 PM
@DanielFischer Did you look at the full questions ?
 
@DanielFischer Indeed. I also think of an original approach.
 
@Chris'ssis Personal approach?
 
@Chris'ssis Btw., have you ever written up a proof of that problem from yesterday ($L = \frac{u_1 + 2 u_2}{3}$)?
 
Hey, I need to show the intersection of $\left(-\infty, 1\right)\cup\left(3,\infty\right)$ and $\left(-1,5\right)$ on the number line for an answer I'm doing. Anyone have any ideas how I can draw one up ? (I'm too lazy to use MS Paint)
 
Pencil and paper, @Nick, the old-fashioned way is most simple.
 
6:31 PM
@rehband I'll write it in latex when I have time, and maybe I add that problem to my book.
 
@DanielFischer: No way to upload it to my computer.
 
@Chris'ssis Thank u sir
 
I am bored. I need to find a gf, lol.
 
@WillHunting Don't you mean math book?
 
6:35 PM
@rehband Nah, for some reasons, I will only start studying math next year.
 
@WillHunting Hmm ok, weird
 
@Hippalectryon: I do not understand japanese
 
Chinese
 
Exactly
 
6:38 PM
Better not post any more pics.
@Hippalectryon So did you watch that movie, The Covenant?
 
Never watched it
@WillHunting Wow even better. The true Ted. i.gyazo.com/47f6d9b87827ac767abfe7dc5ce5b2df.png
 
Where can I find Ted say 'All the math you've learned uve forgotten?' ?
 
On my profile :P
And on a video
 
ok
 
6:53 PM
I'll find it
@rehband FOUND IT :D
 
@Hippalectryon Let's see it
 
10
That moment when he says I'm shocked. - I'm shocked ! - I'm old !
 
Hahahaha
Pure gold
 
Interesting chat going on :O
@Hippalectryon Oh lol :D
 
7:09 PM
@rehband: In brightest day, in darkest night, all with mathematical sight, hail the Ted Shifrin delight!
6
 
@Nick Wow! Beautiful!
 
Ya'll will soon be in his ignore list.
2
 
why?
 
We probably are already :\
 
I am there for sure :/
 
7:11 PM
Lord, death!
Lively, lively pirates swiftly view a warm, small sail.
Faith, adventure, and death.
The cold reef roughly desires the shark.
Sail quietly like an old captain
 
hello
 
@rehband: I stole it from Hal Jordan
 
@VibhavPant hello
 
@VibhavPant hi
 
herro @Vihbav
@Hippalectryon wretched grammer. an old captain.
 
7:12 PM
I have my social science exams and I am chatting :'( :| :\
 
isliye bye
 
@BalarkaSen: I am on everyone's ignore list including my own. If you received this message then the others must have forgotten to give you the memo.
 
Shh don't break da dream
 
How would I prove the convergence of $\sum_{k=1}^{\infty}\frac{n\cos^2(n\pi /3)}{2^n}$
 
7:16 PM
@Sawarnik chatting is social, but it's not science :/
 
Im pretty sure I dont have to integrate anything
 
@VibhavPant What do you know of $\displaystyle\sum_{k=1}^{\infty}\frac{n}{2^n}$ ?
 
@IceBoy: Who says Social Science was a science?
 
@VibhavPant $\cos^2(\text{blah})$ is bounded
And what @Hippa said.
 
@Hippalectryon $\int\frac{n}{2^n} \to 0$ as $n\to \infty$, so the integral test works
 
7:17 PM
@Nick it's in the name.
 
Ted Shifrin likes bashing people

With an exercise in mass poetry.

We dream of dark things, nightshade and purple

Pundit plots of putrid poetry
2
 
@BalarkaSen: I have slowly begun to understand the meaning of bounded
 
@BalarkaSen So, can $\cos^2(\text{blah})$ be removed in some way?
 
@IceBoy: Names lie.
 
@VibhavPant No, but you can compare.
(It $\Omega(1)$ in any case, so...)
 
7:20 PM
ah
 
@BalarkaSen What about $\cos^2(\nabla)$ ?
 
@Nick yes, they may deceive, but in social science it is not the case, my friend.
 
@Hippa should I summon nablablah?
 
I feel very restless now.
 
7:21 PM
@BalarkaSen: You sound like YuGiOh! summoning mathematicians instead of monsters.
 
I summon Ted Shifrin !! I bash all your cards !
 
@WillHunting exercise
 
@IceBoy Today I watched a great movie. "If I live".
 
@WillHunting who's in it?
 
So, $\frac{n\cos^2(n\pi / 3)}{2^n} \le \frac{n}{2^n}$, and since $\sum_{n=1}^{\infty}\frac{n}{2^n}$ , so does the original series?
 
7:23 PM
@IceBoy Nobody I know of, lol. But it is the best movie I ever watched.
 
@IceBoy: You need to tell him the page number for the excercise.
 
@VibhavPant yep
 
\o/
thanks
 
@VibhavPant yes, as $0 \leq \frac{n\cos^2(n\pi/3)}{2^n}$
 
@WillHunting Wow! that is high praise.
 
7:24 PM
@IceBoy Yes, you must watch it.
 
@WillHunting: Please make your previous statement more passive.
 
The best movie I saw was Escape to Victory.
Have you seen it, @Will?
 
@HippalectryonI think I know what happens there, your solution comes from a system of 2 equations, but I need time to explain that mathematically.
 
@BalarkaSen Never heard of.
 
You should see it, @Will.
 
7:26 PM
I feel that my life has yet to begin, sometimes.
 
The best movie I ever saw was ... my life so far
 
@Nick surreality much?
anyone ever seen Shutter Island?
 
@WillHunting: Life never begins, Mr. Loy. We just pretend that our existence is as lucid as life sounds.
@BalarkaSen: Yeah, Dicaprio was a good nutjob. I saw it right after inception, and it got me thinking a bit abut life.
 
@Nick For me, it is because of my mental illness. I feel that a new life is waiting for me when I get well.
 
@Nick I presume you have also seen Truman Story?
That'll make you think about reality even more.
 
7:29 PM
@BalarkaSen: That's how I met Jim Carrey.
 
Oh cool.
 
@BalarkaSen: No, that was a figure of speech. I never met him
 
heh
 
I got that much, @Nick
I was referring to the fact that you have seen that movie.
 
@WillHunting I can't find "If I live"?
 
7:31 PM
You can't find what if you live?
 
I found "If I stay"
the movie
 
If you stay?
 
@IceBoy Sorry, you are right. "If I stay"!
 
>8(
 
Hahahahaha, I got the title wrong!
 
7:32 PM
heh heh
 
eeueuhghghghj
 
LOLLOLLOL
 
I need to drop discrete
cant take it
 
If $n\to \infty$, $s \ge 0$, $\frac{1}{n\ln n (\ln \ln n)^s} \le \frac{1}{n\ln n}$, right?
 
@Alizter what happened?
@VibhavPant $s \leq 0$ or $s \geq 0$?
 
7:33 PM
 
@BalarkaSen It's hard. Because if you screw up early in the exam you get no marks.
 
@BalarkaSen oops, typo
 
and it is tedious
just apply this algorithm
 
@IceBoy Thanks for telling me. I just watched it today and I forgot the title, lol.
 
apply that
arhghgh
 
7:34 PM
@WillHunting Yes, "If I STAY" looks really good :)
very emotional
 
@IceBoy I was like crying through half the movie.
It made me think of my past too.
 
@BalarkaSen corrected
 
anyway. I am trying to opt to replace it with some mechanics or statsitics
 
then yes. $\log\log n \geq 1$ for large $n$s
 
@WillHunting what did you think about your past?
 
7:36 PM
@Alizter i heard that mechanics is good
 
@IceBoy For one, how I almost could have gone to Cambridge but did not.
 
@BalarkaSen It is fun
 
@WillHunting do you regret that?
 
@IceBoy Yes. It is one of my deepest regrets in life.
 
@Will did you come to this chat after your illness?
 
7:38 PM
@BalarkaSen I have had mental problems for 15 years, before you were born.
 
oh man
 
why do you want to live with regret @WillHunting, why not make it your dream to go there one day?
 
No words can describe the suffering and loss I have experienced.
@IceBoy Yes, I will try to get well and go to grad school. Cambridge is only good for undergrad, not grad school. Hehe.
 
go there and conquer :)
live for your dream
 
@IceBoy Do you have any more wishes in life?
What are they?
OK.
Although I don't consider myself a real Buddhist now, I still believe in rebirth.
 
7:41 PM
good night!
 
later
 
@Chris'ssis Meh I give up on my problem for now. Time to read some more Appendix A.
 
is that an appendix of a book?
 
Which book?
 
nice
 
^^
45€ though
 
What is that converted to Rupee? or even $ would do.
 
not too expensive
 
7:48 PM
Still
 
Ooof. That's like 3500 Rs. to us.
 
Buy two, it makes $100
 
I spent 1000 USD on my 12 math books.
 
why buy two?
of the same
 
After all, it's 260 pages long :)
@WillHunting But you're rich
 
7:49 PM
@Hippalectryon Not rich. I only spend on books.
 
I'm poor
 
I actually am poor too.
 
@Hippa Me too
 
me three four
 
But if I did not go mad, I would be rich now.
 
7:51 PM
how?
 
I would have been working the past few years, earning much.
 
I'll have H2O three, please
 
mathematicians are never really rich. people usually throw tomatoes at them.
 
lol
 
7:52 PM
@Hippalectryon radioactive water! ahhh!
@Hippalectryon any tomato emoticon you have in mind?
 
how strike?
 
If my enemy comes to chat now, I wonder what I would do...
 
( ˘▽˘)っO @BalarkaSen
 
@IceBoy
 
@Alizter ?
 
7:54 PM
how do i strike out
 
--- here ---
 
@Hippalectryon eh, how's that a tomato?
 
like this?
 
Unicode plz
 
7:54 PM
heh
 
@IceBoy thak than tank thank yuo you
 
:D
 
@Hippalectryon
ahhaha
 
hahaha
 
@Alizter
.------.------.------.
 
7:55 PM
@you
$math$
 
@IceBoy Do you have any regrets in life?
 
noo
 
this sentence has not been striked out
 
^ he is not a liar
 
not not a liar
 
7:57 PM
ლ(ಠ益ಠლ)
 
d u even lift?
()>---ლ(ಠ益ಠლ)---<()
 
( .)ヘ(゜Д、゜)ノ(. )
 
please delete
 
@IceBoy
 
:-O
 
7:59 PM
Hi @Hakim
 
Hi @WillHunting
 

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