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12:05 AM
"Do you feed the man, knowing that in the future he will be able to prevent the trolley problem if he becomes fat?"
Also, there is an area of philosophy in which they argue over the best action to take in the event of a disagreement.
 
12:32 AM
I'm sure Hamlet could have benefited from that
 
1:10 AM
Alas!, poor trolley! I knew it, Horatio.
 
Hamlet didn't pull the lever. RIP Yorick
 
hi
I am solving the problem 2.14
Determine whether there exists a short exact sequence $0 \rightarrow Z_4 \rightarrow Z_8 \oplus Z_2 \rightarrow Z_4 \rightarrow 0.$
you should try it out @AkivaWeinberger
 
decides to keep mouth shut
 
Oh, yeah, I didn't really finish that because I didn't really know enough group theory
Either that, or I finished it, but Balarka provided most of the details
But what you quoted was just part (a), right? @Adeek
 
yeah
 
1:18 AM
I think that was a "yes"
 
Yeah
it is yes
 
(Also, you're not up to Chapter 3 already?)
 
No, I got busy towards the end of semester
But I am graduating next month and I will not do anymore electives so I can concentrate on math :D
 
Really? 'Cause you were talking about a bunch of stuff in the appendix of chapter 2
 
yeah I finished chapter 2
but didn't do the excerises
 
1:20 AM
Ah.
 
had to study stupid stuff like economics and anthropology
 
hi
 
So, so far you don't know how to prove that $\rm\Bbb CP^2$ and $S^2\vee S^4$ aren't homotopically equivalent
Apparently cohomology proves that, but I don't understand it all that well yet
@Cosinux Hey
 
i have a question:
is
oup sorry
i am a programmer. So i wondered: how can we express programming with math? for example: how would we say (if x > y:)
(if x > y: z = 0 else: z = 1) in math
if you understand me
 
$z=\cases{0,&$x>y$\\1,&$x\ge y$}$ should work
(if you have LaTex enabled)
Uh, typo
 
1:33 AM
are you on a plane right now?
 
ok but how would you write down an equation containing only pure mathematical operations (like you would write it down on paper and then solve it)
 
@MikeMiller Not quite yet
Soon
 
so lazy
 
I'm at the airport.
Still have my suitcase. About to hand it over.
@Cosinux You could probably cobble something together involving absolute values
but, generally, writing "$z=0$ if $x>y$ and $z=1$ otherwise" is fine for mathematicians
 
yes but on a higher level. i really want to know for example how to turn an if statement into math. But i'm only still in secondary school and so all i really know currently is +-*/,p
+, *, -, /, power, absolute, sum, angular features,...etc.
im not really a math pro
 
1:42 AM
Those are the operations and functions that we use the most, but there's no reason to limit ourselves only to those things and combinations of those things
But, uh, if you have learned about piecewise functions
then "if" statements most directly translate into those
So look up piecewise functions if you haven't learned about them yet @Cosinux
 
i understand but to me operations +-*/... represent basic operations, thats why i would like to know it that way
of course i am only curious
there is no urge for me to know
 
wtf @Akiva the cube is gone
 
@MikeMiller "Cube"?
 
the one at Astor place
 
@Cosinux z = 1/2 - (x-y)/|x-y| works for your example, I think (though I may be wrong)
 
1:56 AM
it's gone and good odds say that's your fault
 
And when X=y it's not defined
@MikeMiller I don't know what you're talking about
And I live in Brooklyn; I don't visit SoHo often
(Is it in SoHo?)
 
It's in the village
 
Yeah; when I'm in Manhattan I'm usually in the Upper East Side
And when I'm not it's usually the Upper West Side
(I mean, when I'm in Man. but not the UES)
 
That was a hell of a cube, man.
 
My brother says "Yeah, they took it down, it's a shame, it was kinda cool"
 
2:02 AM
There's a picture of me in front of that cube somewhere
There's also a cool speakeasy nearby, Angel's Share
I'm probably not dressed well enough to go tonight
 
Did you know, the biggest park in NYC is not Central Park
It's the biggest park in Manhattan, but Manhattan is only 10% the area and 20% the population of NYC
 
I'm aware.
 
Pelham Bay Park in the Bronx is the biggest
 
@AkivaWeinberger Sounds like a good place to go touring.
Part of the tour is getting your wallet stolen, right?
 
I've never been, but the train I go on every day ends there if I stay on it long enough
@PedroTamaroff In fact, it's probably me that's stealing your wallet
(Those math books don't buy themselves :P )
 
2:11 AM
Theft is not as much a problem as it used to be.
 
Right, 'cause I'm not in NYC right now
When I return it will be
 
 
1 hour later…
3:28 AM
Does the map $\mathbb R^2\to\mathbb R^2$, $(x,y)\mapsto(x^2-y^2,2xy)$ have an inverse when restricted to some open ball? I think no and have it somewhat worked out, but am not sure.
 
@EsX_Raptor Yes. It's Jacobian matrix is $\begin{pmatrix} 2x&2y\\ -2y&2x\end{pmatrix}$ which has determinant $4(x^2+y^2)$ which is nonzero whenever $(x,y)$ is nonzero. Hence the inverse function theorem says $f$ is a local diffeomorphism at every point not the origin.
This is in fact the map $\Bbb C\to\Bbb C$ that sends $z\to z^2$, and one can in general show that a complex polynomial is a local diffeomorphism (in fact biholomorphism) in any point away from its roots (which are "branched" points).
 
3:43 AM
Thank you, @PedroTamaroff. It took me a bit to digest that, but I roughly get it now.
 
 
1 hour later…
5:08 AM
does anybody have good suggestions of math objects to put on a graphic to a math-oriented friend for his birthday?
i want to make him a poster
 
"Prove that $\{f_k\}$ converges weakly, but not in the $L^{\infty}$ norm." What does this mean?
 
@JesterTran What are $f_k$?
 
@MikeMiller Take it as a general question, let's say $f_k \subseteq C[\mathbb{R}]$ and I need help interpreting
 
What does it mean to converge weakly?
 
5:18 AM
What is the inner product?
 
@MikeMiller some inner product, why does it matter?
 
@JesterTran Presumably because you asked what the sentence means, and that's implicitly part of the sentence.
 
@MikeMiller I should have specified my interpretation issue: "but not in the $L^{\infty}$ norm"
 
Do you know what the $L^\infty$ norm is?
 
5:21 AM
yeah, supremum |f|
 
So what does it mean to converge w/r/t a norm?
 
$f_k$ converges to $f$ in the ?-norm means $\| f_k -f\|_{?} \to 0$ as $k \to \infty$?
 
Yeah. So, then, as applied to your question...
 
$\| \pi (f_k) - \pi(f) \|_{\infty} \not\to 0$ as $k \to \infty$? where $\pi$ is the inner product
 
Huh? 1) Inner products take two inputs, not one. 2) Where did the inner product come from in the first place? That shouldn't be part of the input in "Blah does not converge in the $\infty$-norm" - it didn't show up when you were talking about convergence in norm above.
 
5:26 AM
right
yeah, it's $\| f_k - f\|_{\infty} \not\to 0$ as $k \to \infty$
 
Well, that's specifically "$f_k$ does not converge to $f$"
 
 
2 hours later…
7:38 AM
@B
@BalarkaSen
I am on fire today.
10
Q: When can we recover a topology from its connected sets?

goblin Definition. Let $X$ denote a set. Whenever $\tau$ is a topology on $X$, write $\tilde{\tau}$ for the collection of subsets of $X$ that are connected from the viewpoint of the space $(X,\tau)$. In general, we cannot recover $\tau$ from $\tilde{\tau}$. For instance, let $\tau$ denote the usual...

you can call me the king of counterexample
 
Huy
certainly not king of camera quality
 
Heh.
 
how dare you!
yeah my phone is very old
and my apartment is not well-lit
 
hhh
Is someone good here in graph theory? Puzzling on this where trying to find the proper jargon.
Somehow turning graph to tree.
It should be here sufficient to consider undirected graphs so wondering whether block graphs and cliques could be useful (just reading their wikipedia).
 
I constructed two amazing counterexamples today
I AM THE KING
 
7:54 AM
good job
but it's also useful to prove a few things once in a while. just sayin'.
 
well hopefully counterexamples lead to better understanding and then maybe proof
it means you have to assume more
for a theorem to hold
but in these cases I don't really see what additional assumptions would be useful
 
fair enough, but the theorem itself (it's modified form maybe) needs to be proved.
 
maybe there isn't a theorem
 
maybe there is!
 
I mean, maybe you have to assume so much that there is only like 1 space that would satisfy everything
 
7:59 AM
i am not talking about statements that fail so drastically. i have in mind say like the conjecture of erdos you're working on.
maybe there are no ctrexamples and you need to prove it at some pt of time.
 
yes that may be the case with the Erdos problem
obviously it is much harder than these I solved today
 
In Ä°stanbul; eventually gonna go on another flight to New York
 
@AkivaWeinberger Safe flight.
OK, so what's next?
 
i dont know I am tired
 
I want to think about something but I don't know/can't decide what to.
 
 
2 hours later…
9:54 AM
@robjohn Happy Easter!
Easter is God’s blessing to the world. It is his way of telling us that, love and hope still exists in the world. May you have a learned Easter.
Then, the wisdom comes from God, by His will ONLY, including, of course, mathematical wisdom.
Back to my work.
 
 
1 hour later…
11:10 AM
Hi @Kari.
 
Hey, @BalarkaSen!
Doing anything interesting today?
 
What're you working on?
Not much, been thinking a bit about differential forms.
 
Right now, I'm looking at the theory of ODEs.
Picard-Lindelof, contraction mappings, global Lipschitz stuffs.
 
That's pretty cool! I don't know anything about that.
 
Differential forms. Is that like wedge products and stuff?
It's quite interesting. The lecturer at the time didn't enthuse me so I didn't attend many lectures but it's a nice area of math.
 
11:17 AM
@Kari Yeah. I don't know of a concise way to put it (because I don't understand the story yet), but it's like a formalization of vector calculus. The fundamental objects there are vector fields, and you integrate vector fields along paths (line integral) or surfaces (surface integral) and do stuff. But the fundamental objects in this context are, well, differential forms. So turns out what you integrate, differentiate, etc are not vector fields but differential form.
@Kari Nice, anything interesting that you can tell me about?
 
Sounds wicked! I think you recommended a pdf a while back (or maybe it was Soham).
 
Probably not me.
 
So far I really haven't seen much as I started reading yesterday, but I've just been looking at equivalent ways of forming initial value problems. There have been a few errors in the lecturers hand-written notes so I haven't been able to make much progress.
 
I see.
Let me know if you have something interesting to tell.
 
We began looking at $(\mathcal{C}([-\tau,\tau];\mathbb{R}^n), \| \cdot \|_{\infty})$ being a complete vector space but the supremum norm he defined looked like: $$\| f \|_{\infty} = \sup_{t\in[-\tau,\tau]} |f(t)|. $$
 
11:21 AM
I suppose he means sup of $\|f(t)\|$?
 
That led me to believe that he meant $\mathbb{R}$ instead of $\mathbb{R}^n$ or the Euclidean norm instead of the absolute value. Probably the latter.
$\| \cdot \| \equiv \| \cdot \|_2$?
 
It'll become clear which one he means depending on context, I suppose. I too think it's the latter.
@Kari Yup.
 
Everywhere in the working, he wrote $|\cdot|$ so I guess he just means that it's a placeholder for the appropriate norm depending on the context.
 
@Kari Note that not much is lost in assuming that he means $\Bbb R^n$ and Euclidean norm of $f(t)$. Because if he really means $\Bbb R$ and the absolute value of $f(t)$, then that'd just be a special case of what you assumed for $n = 1$!
 
Indeed!
 
11:24 AM
Easily done ;)
I find it a bit annoying that I can't explain what's the deal with differential forms in a few words. There is something fundamental missing in my understanding of those, I think, because most of the time what I really understand I can explain in a motivating/easy way.
 
Just read the intro of the pdf. What you said makes sense.
We can establish between vector fields and differential forms.
 
Mhm.
 
 
1 hour later…
12:44 PM
morning chat
 
morning, @SemiC.
 
user147690
On a phone, so cant respond much. Does anyone know what an injection of bialgebras requires? Does it do anything to preserve bialg structure, or just two bialgebras and an injection?
 
how goes differential forms?
 
learning, but not sure if understanding the whole business yet
 
gotcha
 
12:50 PM
@user1618033 Thanks! You, too! We had Easter here a month ago.
 
@balarka taking a look at the pdf that kari linked, what i notice is that i basically understand the range of material surveyed
but what they don't touch at all on there is the nature of differential forms as forms, i.e. as objects which act on vector fields
 
yeah, i think you do.
 
and it's the latter where i'm weak.
 
@Semiclassical really? i haven't seen the pdf, but that's more or less a how think about differential forms i think.
 
as objects which act on vector fields?
 
12:56 PM
a form on a vector space eats parallelpipeds and spits out scalars. a form on a manifold eats a smoothly varying parallelpiped sticking out of each point and spits out a smooth varying scalar, i.e. smooth functions.
 
the link is still up there, so it might be worth quickly skimming through the whole thing to see what i mean
 
@Semiclassical mhm
 
Huy
what do you eat @BalarkaSen
 
biscuits.
 
Huy
and what do you spit out
4
 
12:58 PM
right. the way i might say it is that i know my multivariable vector calculus quite well
and i do know how exterior algebra works. but while i know the two are supposed to link together into one idea, i don't really know how that works
 
the vector field thing is linear algebra though
@Semiclassical how do you think about forms?
 
as differentials, i suppose. i wouldn't say i'm internally consistent, though
 
i am not sure what you mean when you say "linking the two". one is the eating k-vector fields thing. what's the other?
@Semiclassical eh, what do you mean by differentials?
 
well, let me put it like this. formally, i can manipulate 2-forms and i know how they show up as exterior derivatives of 1-forms
but at the end of the day, when i think of a surface integral $\int_A dx\,dy$ i have in mind a Riemann sum
 
@MikeMiller Is it true that given any manifold there exists a vectr filed with finitely many zeros?? For compact manifold it is true (followed from tansversility theorem)
 
1:03 PM
or if i'm doing a flux integral, my mental picture is one of "pick a small area element, compute the flux going through it, and then add them all up"
 
@Semiclassical I am confused. So you're asking for a reason why the eating k-vector fields interpretation links with "things which can be integrated"?
 
i guess so.
 
@Semiclassical Sure, but this doesn't actually use anything special about differential forms. You might as well use vector fields and integrate them on surfaces.
The physical picture doesn't tell me why I should use differential forms and not vector fields.
@Semiclassical I think that's a good question.
 
sure. my point is only that the formal aspects don't enter into my picture of a flux integral---the differentials themselves, as 'infinitesimal contributions' to the flux, are what i fall back on
i'm not saying it's internally consistent, mind. just that it illustrates the limitations of my thinking.
 
I see what you mean, but what I am trying to pin-point is why differential forms is not just a formal thing. I "feel" that it isn't, but I can't find the precise reason.
It seems like an answer to your question would contribute a lot to the understanding, but I haven't thought about it.
 
1:11 PM
i should also remind that, as a physicist, when i hear the phrase 'vector field' i read that as "a vector function on a space."
e.g. an electric field in 3D as a vector function on $\mathbb{R}^3$.
 
unfortunately that's only true for euclidean spaces. for smooth manifolds in general, a vector field is no more a function with target R^n.
 
sure.
 
(the fancy reason is "nontrivial tangent bundle")
 
to put it a somewhat different way, i tend to think of the basis elements of such a vector field as stuff like unit vectors (possibly position-dependent, if i'm working in spherical coordinates)
rather than having the basis elements be differential operators
 
1:15 PM
Yes, but that works only because there is a canonical identification of tangent space of a point in $\Bbb R^n$ with $\Bbb R^n$.
I wouldn't always like to think about it like that, because most of the time I try to see what happens for arbitrary smooth manifolds.
For arbitrary smooth manifolds there's no canonical identification of tangent space of a pt with R^n.
 
understandable. my point is more that, in most applications of multivariable calculus in physics, you really are working in Euclidean space
 
Fair enough.
 
though it's funny. i stress that i think of unit vectors rather than differential operators, and yet if someone asked me how my vector transforms under coordinate transformations, i interpret said unit vectors as transforming in precisely the same way as differential operators would naturally
but then they're not unit vectors anymore
 
1:34 PM
@Semiclassical I think I got an answer to your question. Note that a form eats an oriented parallelpiped (equiv. a bunch of vectors) and spits out it's oriented area (that's what the determinant does), not just an arbitrary scalar. So if I have $f dx_1 \wedge \cdots \wedge dx_n$, and integrate it over some parameterized surface formally by removing the wedges, it shouldn't be too surprising that it should be a natural thing to do, right?
Well, not quite a very satisfying answer yet, but it's intuitively understandable that a form should have something to do with volume.
E.g., if I take a parametrized n-manifold $M$ inside $\Bbb R^m$, and I have the form $f dx_1 \wedge \cdots \wedge dx_n$, then evaluating that at a point $x$ in $M$, it spits out $f(x)$ times the volume of the parallelpiped on $T_xM$ spanned by a bunch of tangent vectors $v_1, \cdots, v_n$ I have fed it to.
 
had to step away for a bit
i think i'd be happy with understanding the very simplest setting, namely that of a line integral.
 
I am not sure what I am trying to find an answer to anymore to be honest.
@Semiclassical do you think you can state your question again?
 
let me state it in the line integral setting, i'm typing that out
 
mhm, ok.
 
there i have two ways of thinking about $\int_C \mathbf{F}\cdot d\mathbf{x}$: either as a riemann sum $\sum_k \mathbf{F}_k\cdot (\Delta \mathbf{x})_k$, or via the FTC using some locally-defined antiderivative
in neither case do i seem to be appealing to the nature of $\mathbf{F}\cdot d\mathbf{x}$ as an object which acts on vector fields.
(i should have some kind of limit in front of the Riemann sum, but w/e)
the first one is just direct summation of infinitesimal contributions, and the latter makes use of some 0-form in order to compute the result.
now, i suspect that what i'm missing is that i'm not treating $C$ with sufficient respect (whatever that means)
@balarka does that make any sense? not sure it does.
 
1:51 PM
yes, it does. I think there should be a way to interpret the integral using the fact that $\mathbb{F} \cdot d\mathbb{x}$ eats the tangent vectors of $C$.
 
right.
 
I am trying to figure out what it is.
 
2:04 PM
@Anubhav.K For noncompact manifolds you can pick one with no zeroes.
 
@SemiC If I feed in a tangent vector $\mathbf{T}$ in $T_x \mathcal{C}$ to $\mathbb{F} \cdot d\mathbf{x}$, then $\mathbb{F} \cdot d\mathbf{x} (\mathbf{T}) = \mathbb{F} \cdot \mathbf{T}$. I am pretty sure this should somehow mean that the integral is really $\int_C \mathbb{F} \cdot \mathbf{T} ds$ where $ds$ means an infinitsimal patch of the curve $\mathcal{C}$, and that is exactly it. But maybe I am thinking too hard.
This is a good conceptual question I don't really know the answer to.
 
could work.
 
Thanks, @Semiclassical. I never thought about this story.
 
glad to be a source of interest, heh
 
2:25 PM
what'd i miss
 
morning @MikeMiller
we were discussing how the interpretation of differential forms as something which eats k vector fields and spits smooth function links with something which can be integrated over parametrized submanifolds.
 
Sure.
 
If you have something/want to say about this, I'd like to hear.
 
You already said it. ds is the vector you're feeding it.
 
trying to remember: if one works in arc-length parametrization, is $\mathbf{T}=\frac{d\mathbf{x}}{ds}$?
 
2:31 PM
And the Riemannian field = 1-form correspondence is "w(v)" <-> "<v,w*>"
 
nvm, seems the RHS is the unit vector associated to $\mathbf{T}$
 
@Semiclassical Yes. It's $\gamma'(t)/\|\gamma'(t)\|$ isn't it, where $\gamma$ is a parametrization of $C$?
That's the same as what you wrote ($ds = \|\gamma'(t)\| dt$)
 
right.
 
@MikeMiller What's a Riemannian field again?
 
2:35 PM
ouch
 
I am interpreting the "no" as "none of your concern". OK ;)
 
No = parsed the sentence wrong
 
"The Riemannian correspondence of vector fields to 1-forms is..."?
 
Ah, I see.
You use the Riemannian metric to give a correspondence between vector fields and 1-forms. Sure.
We discussed that before. Inner product on a space gives a natural isom between V and V^*.
 
btw. where i was going was that, if one uses the arc length parametrization, then $\int_C \mathbf{F}\cdot d\mathbf{x}=\int_0^L \mathbf{F}\cdot \hat{\mathbf{T}}\,ds$
 
2:39 PM
Yup, @Semiclassical.
That was how I was trying to answer your question here.
Feeding the tangent vector $T$ to the 1-form $F \cdot dx$ gives $F \cdot T$.
 
yeah, i understood. i just wanted to write it out
 
Ah, ok.
 
though i'm not convinced it quite satisfies me: one still has $ds$ left, after all
and so it still seems to require at some point switching from $ds$ as a 1-form to $ds$ as something used to define a Riemann sum
i'm not entirely sure I'm being fair, though.
 
I don't know of a rigorous way to fill that bit in. One can think of $ds$ as an infinitisimal patch on my curve $C$, and the intuition is more or less what it should be.
Also $ds$ is not a 1-form.
 
isn't it? it should act as $ds(\partial_s)=1$.
(i should probably be using the word 'pullback' in here, eh)
 
2:46 PM
It's defined as $\|\gamma'(t)\| dt$. $\|\gamma'(t)\|$ is not a smooth function. It's just a notation.
 
I guess a good question could be "if it's not a 1-form, what the hell is it?". That is, how to make the expression $\int F \cdot T ds$ rigorous. It's not clear to me how one would do that.
 
well, $F\cdot T$ is just some function
 
Sure.
 
so really just $\int g(s)\,ds$ is enough
@balarka this answer looks useful for the present discussion
 
3:03 PM
Thanks, enlightening.
@Semiclassical I looked again and essentially the guy is saying what I wrote above. Pulling back say the form $fdx$ by some smooth function $g$ gives $f(g(x))g'(x)dx$, and $f(g(x)) g'(x)$ is precisely what you get when you feed in the vector $g'(x)$ to $f dx$.
 
$g'(x)$ is a vector?
 
It's a tangent vector to $C$ at $g(x)$, sure. You're just parametrizing $C$ by $g$.
 
@robjohn Thanks. Remembering this event is OK, not matter the day.
People should think (once in a while) of a simple fact if talking about God: what is the mathematical probability that all 12 apostols were highly gifted and spread the gospels in such an amazing way with so poor knowledge they had, and they also did many outstanding miracles.
This is for those that said Jesus didn't even existed, or he was just an ordinary person.
 
There is no randomness in it. It's just a matter of good sense to accept such facts. The existence of God is so obvious!
 
3:18 PM
that $ds$ has to do with the metric, apparently.
 
@balarka hmm!
 
It's not so surprising, but admittedly the formal aspect is not clear to me. That is, it's not clear to me how to do the integration and things in the setting of symmetric tensors, formally.
 
same.
 
In any case, thanks, @SemiC. We should have these discussions once in a while. ;)
 
agreed @balarka
 
3:22 PM
I'm off to work. I have got to waste a positive proportion of my time watching a movie tonight so I better get some work done by that time.
 
what movie?
 
I haven't decided :)
 
@Semiclassical Today I established another generalization for those series. :-)
 
Feel free to recommend anything.
 
@user1618033 nice
 
3:24 PM
1
Q: What explains the asymptotic and the pattern in this sequence related to Riemann zeta zeros?

matsgranvikAs the starting point for my experiment I assumed that the imaginary parts of the Riemann zeta zeros are of the form: $$\Im \{ \rho_n \} = \frac{2\pi}{\log x_n}$$ where $x_n$ is unknown. Therefore I solved for $x_n$ and got this integer sequence: $$\Large a_1(n) = (n+1) \left(\left[\frac{1}{e^...

Is this question of mine research level or math se level?
 
@BalarkaSen I guess you veto'd Adam Green's Aladdin
 
Yes, I did.
 
How old are you?
 
lol
 
Not rhetorical.
 
3:26 PM
15 or 16. don't remember precisely.
 
lol
anything written by charlie kaufman
synecdoche, ny is an extremely good movie
in my top 5
 
One last question on religion: is the modern world today able to turn 12 simple, uneducated people into persons like the apostles in the time of Jesus such that they are able to change the world? There are 12, each one very special and able of doing amazing things!
 
thanks. what sort of movie is that? as in what genre?
 
i don't know what genres are
 
me neither, to be honest.
 
3:30 PM
naked lunch is another good movie i saw not long ago. most things by cronenberg.
you're probably old enough for all that.
 
mhm. but i'd rather not watch something "too adult", if you know what i mean.
 
nah
 
Nobody cares!
 
there's also "the man who fell to earth"
i've enumerated everything I wish to right now
 
alright, will have a look at those.
for a minute i thought you wrote "the man from the earth", which btw is one my favorites.
 
3:40 PM
@Semiclassical I was looking through the I. S. Gradshteyn and I. M. Ryzhik table and I found nothing interesting yet ...
Let me ask you all a question
What is the easiest way to calculate $$\int_0^{\infty} \frac{\log(\sin^2(a x))}{b^2-x^2} \ dx,\ a,b>0$$ you are aware of?
How about finish it in one line? No need to be finished under 2 min, say.
 
hello. i see someone has recently seen naked lunch. so have I
I feel it needs a second run, though. It's too weird for only one
@BalarkaSen I also like that one a lot
Cool people here, good tastes
so, anyone have a few minutes to help me with something I'm working on?
 
3:57 PM
Just ask; don't ask to ask. Someone will help eventually.
 

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