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12:46 AM
hi all
 
Hi @mixedmath
 
how's it going @Hakim?
 
Really good @mixedmath How about you?
 
I'm doing pretty well. I'm halfway through moving, which is pretty exciting (of course, I hate moving too, but so it goes)
 
@mixedmath Hey.
 
12:49 AM
:-)
 
hi @AlexYoucis
 
@mixedmath It says on your profile that you're interested in analytic number theory.
Ever looked into any of the Bhargava stuff?
 
@AlexYoucis yep, that's right
actually, my first attempt at a dissertation was on Bhargava's work on densities of quartic and quintic number fields
except with Dirichlet series instead of geometry-of-numbers stuff
(it didn't work out)
 
@mixedmath Ah, interesting!
 
I still have an untapped, cool thing relating to the effort, about Dirichlet series over classes of quadratic and cubic forms, etc.
things that haven't been done... but which I couldn't quite get to work out... but there's cool stuff there!
what do you do @AlexYoucis?
 
12:53 AM
What does a Dirichlet series over classes of quadratic or cubic forms mean, precisely?
@mixedmath That's TBD :)
 
so, let's think of just quadratic forms.
 
@MichaelAlbanese You a fan of the albanese variety?
 
@AlexYoucis I'm sure I would be if I understood what it was.
 
@MichaelAlbanese lol, fair point.
 
a quadratic form $Q(x,y) = aX^2 + bXY + cY^2$ can be acted on by two by two integer matrices, by having the matrices act on the vector $(x,y)$
 
12:55 AM
@mixedmath Sure, sure.
 
certain things are invariant under this transformation, like the discriminant
 
mhmm
 
in fact, the algebra of invariants is 2 dimensional
 
and a polynomial ring
more specifically
the representation is coregular, no?
 
consider two quadratic forms equivalent if there is some integer matrix taking one to the other
@AlexYoucis yepyep!
 
12:56 AM
Ok, so go on.
 
then one might consider the Dirichlet series $\displaystyle \sum \frac{1}{I_1(q)^{s_1}I_2(q)^{s_2}}$, where $I_1$ and $I_2$ are the two generators of the invariants (there is a cannonical choice), and where we sum over equivalence classes of quadratic forms
 
Ah, I see.
 
this is very similar to how Shintani found asymptotics for cubic discriminants in the 70s, which were the first results of the time
 
Yeah
I believe I have heard a talk on this
actually
 
but he did it just over the discriminant. My advisor's thing is multiple Dirichlet series, so we're all about more complex variables
the idea is that with more invariants, we should have more information. If we understood poles, residues, and analytic continuations, we'd be golden in many ways
 
1:01 AM
So, you work in the more pure analytic side
|you-Andrew Granville|<|you-Bhargava|
 
well, it turns out that binary n-ic forms (not just quadratic or cubic), analyzed in this way, can always be written as sums of zeta functions and L-functions, which are lovely amazing things that everyone wants to understand. And I played with that
@AlexYoucis that's one way to put it ;p
 
@mixedmath I think Ive heard a talk about this stuff, from Frank Thorne.
 
cute fluke: originally I was interested in additive number theory, and worked under Ernie Croot at my undergrad. Croot is one of Granville's students
ah, Frank Thorne is perhaps the world expert on Shintani zeta functions. I've talked with him about this quite a bit
 
Yeah, he seems like a super nice dude.
@mixedmath Analytic theory has always somewhat perplexed me. It seems super interesting, but I just can't bring myself to dig the methods sometimes.
 
since then, I've gone even more analytic. There's representation theory and algebra in that, but now I look more at moments of L-functions in critical strips, subconvexity bounds, working on Lindelhof-hypothesis type stuff
@AlexYoucis ah that's fascinating. i really like the methods, but I often don't care about the results
 
1:06 AM
With all due respect, that makes me vom a little
:)
 
I just managed to show that a particular set of coefficients has infinitely many sign changes. Really beautiful theory, clear flow of ideas. Amazing cancellation. But really, who cares about these sign changes?
@AlexYoucis that's funny
 
@mixedmath Well, math wouldn't be a beautiful mosaic if we didn't have different tastes :) My dislike is most likely really just a function of ignorance.
 
Qiaochu's at Berkeley, right?
 
@mixedmath Uh, guy Qiaochu?
 
(is that a girl name too?) I meant Qiaochu Yuan
 
1:11 AM
@mixedmath It's actually predominantly a girl's name, from what I'm led to believe. And yes, the Qiaochu Yuan who participates on stacexchange is at Berkeley.
@mixedmath I met a guy recently from Brown. Dan Miller?
Is that a person/
Oh wait, that wasn't Brown, that was Cornell
:S
 
I'm afraid I don't know him. I guess he's not a Brown grad student - or maybe he's applied math? We have a sharp schism at Brown
oh - that'd do
 
Ithaca, Providence, they're basically the same place, right? :)
 
anyhow, it was a good chat - but I'm heading out for a bit (I'll probably be back later, though)
before I go, I'd like to make one little plug:
 
@mixedmath Go for it.
 
the math community blog is open and is looking for contributions! anyone is welcome, and I encourage many people to give math exposition a whirl
you learn a lot
 
1:22 AM
@mixedmath What level is it at?
 
@AlexYoucis any level. Most of the current stuff is at low-mid undergraduate. Will Jagy has a post in the process that's research-math, some new stuff. I'll put some research math there sometime (though I have a post in the works that's popmath, essentially)
the rule should be: if it would be of interest to the MSE community, it's reasonable written, and it's not offensive - then it's fair game for the blog
you interested?
 
@mixedmath Perhaps. Maybe something like "The Yoneda Philosophy". But, would I need to begin by explaining what a category is, etc?
 
2:20 AM
@AlexYoucis that's a good question. I dunno - I'd have to see the post. If you're anything like me, the intended audience will become more coherent once you sit down and start writing
(if you're more responsible than I am, then I suppose you might decide beforehand what your audience knows and doesn't know, and then pitch it appropriately)
 
 
1 hour later…
3:36 AM
Oh, noes. I missed @AlexYoucis and @mixedmath !!!
 
@PedroTamaroff (I'm still around, more or less)
rather, I'm back
but still more or less
 
@mixedmath Ha! Hello.
 
hiya @PedroTamaroff
how goes it?
 
@mixedmath Not bad. I'm travelling north on Monday. Going to visit family, and visit UGA.
Actually, I'm going to visit @TedShifrin.
But I'll be probably touring around.
 
my old stomping grounds. That's exciting and cool
 
3:43 AM
@mixedmath You did your undergrad there?
 
@PedroTamaroff I actually did my undergrad at Georgia Tech, but both of my sisters and many of my friends went to UGA
in fact, of the 400 or so people from my high school graduating class, about 90 went to UGA, and about 80 went to Georgia Tech
 
@mixedmath Ah. That's nice. Ted's always pulling Georgia Tech's legs, I think.
Hehhehe
 
 
2 hours later…
5:19 AM
Is UIUC considered good for math? I'm an incoming freshman currently in Physics, but I'm considering doubling in math.
 
5:49 AM
@m1cky22 yep. But that's not really a good reason to double in math. I think that perhaps you should double in math if it's something that you want to do, or that you think will benefit you.
and for what it's worth, if you intend on becoming a physicist, I would recommend learning a good amount of math
 
6:08 AM
Oh I should have clarified. I actually love math, I was thinking of going purely into math but I wasn't sure what I can do with math besides teach. I'm currently self-studying Algebra (I started using D&F) and I love it. What can I do with a math degree though?
@mixedmath^ (forgot to tag)
 
 
1 hour later…
7:20 AM
@robjohn Oh well, at least that one has a deep theory behind it's closeness to an integer.
 
@BalarkaSen There are others of that kind that are not quite as close. That is the best though.
 
r9m
@robjohn you are awake ? isn't it past 12 midnight ?
 
7:35 AM
@r9m it's about 12:35
 
8:08 AM
Greetings
 
Hey. Does anybody here have an interest in Combinatorics or algorithms?
 
8:30 AM
@AidanRocke I have an algorithm that can generate several combinatorial sequences.
 
8:55 AM
@Chris'ssis hey there...
 
@robjohn Hey, did you manage to work on my last series?
$$\sum_{n=1}^{\infty} \frac{(-1)^{n+1}}{n}\left(1-\frac{1}{2}+\cdots + \frac{(-1)^{n+1}}{n}\right)^2=\frac{3}{2}\zeta(2)\log(2) + \frac{1}{3} \log^3(2)-\frac{1}{2} \zeta(3)$$
 
@Chris'ssis haven't looked at that yet.
 
OK
@robjohn this one is really nice.
 
9:12 AM
Hi, could someone give me a hand? I would really like to resolve this tonight and it is too late to ask anyone I know. I am trying to properly cite the following source: http://waset.org/Publications/integer-complexity-breaking-the-θ-n2-barrier/6770

Using the bibtex code. However, I am using the plain bibliography style that does not include the publisher and I am concerned that my citation will be considered poorly written because of that. Is this going to be okay? I looked online to see how others are citing the article, but I don't think it helps me.
 
@Echan URL friendly version: waset.org/Publications/…
 
@robjohn Thank you, I was sitting there trying to figure out how to fix that
 
@Echan I am not sure what you are looking for, so I don't think I can help.
 
9:28 AM
@robjohn For example, one of the citations looks like this, up to some formatting lost:

"K. Mahler and J. Popken, On a maximum problem in arithmetic. (Dutch), Nieuw Arch.
Wiskunde"

Everything follows a name, title, journal, volume, issue, page format, but the bibtex entry given from the source I linked does not include a journal, but a publisher instead. In the plain bibliography style publishers are omitted so the citation just goes author, title, volume, issue, page. I am concerned that it looks like a glaring mistake in the bibliography.
 
Hello
$x^2|x|$isnt differentiable in (-1,1), right?
 
Hi all :)

Having added to it yet again, I'm concerned that this question of mine is too long: http://math.stackexchange.com/questions/873429/a-reflective-subcategory-of-the-category-of-inverse-semigroups. Would it be worth posting a question on the meta site about it?

I'm aware that there are similar questions on there . . .

Thanks :)
 
Since its derivative is $x^3/|x| + 2x|x|$
 
[This is particularly satisfying: meta.math.stackexchange.com/questions/4026/… :) ]
S'pose it answers my question lol.

Never mind. I'd appreciate your thoughts anyway.

See you later, I guess :)
 
9:46 AM
@VibhavPant It looks differentiable to me, at x=0 anyway.
 
Echan The derivative is $\frac{x^3}{|x|} + 2x|x|$
which doesnt exist at 0
 
@robjohn I am not sure if this is the closest. There are lots of such approximations.
 
(The derivative of $|x|$ is $\frac{x}{|x|}$)
 
@VibhavPant i.e., the sign function.
 
@VibhavPant You need to use the newton quotient definition and check whether or not the $\lim_{0^{+}} f(x+h)-f(x)/h = \lim_{0^{-}} ….$ are equal
 
9:50 AM
@VibhavPant Limit doesn't exist at $x = 0$
So the derivative is not defined there.
 
In the case of the absolute value function, the limit at the point zero from the left and the right give 1 and -1 respectively, the derivative you are wrote is already assuming existence.
 
Also, critical points are points where the derivative is zero only, right?
 
Critical points are where the derivative is zero in the domain of the function
 
@Echan That is the only requirement, right?
 
@VibhavPant Only?
Critpoints are the points where the function shows Gaussian development, so yes, that's the only condition.
 
9:55 AM
As far as I am aware, but being in the domain of $f$ is kind of an important requirement imo
 
@BalarkaSen My teacher used to is they are also the points where the derivative doesnt exist
 
@VibhavPant Derivative is not 0 there, surely!
Those points are called kinks.
 
@BalarkaSen So they are not critical points, right
 
@VibhavPant Yep, they are not. Like $x = 0$ of $|x|$
 
I KNEW THAT
 
9:58 AM
=)
 
I cant even try to show him the correct definition
 
@VibhavPant "current definition"? "him"?
 
@BalarkaSen A math teacher of mine says that critical points are points where the derivative is zero OR the derivative is not defined
Teacher as in the one in those IIT-JEE preparation institutes :|
@BalarkaSen Have you attended one?
 
I think I used that definition last time I was involved in an introductory Calculus course, but I can't find any of my old notes on this computer
 
Nope.
@VibhavPant Definitions vary book-to-book.
So I can't be sure either what's the universal definition.
Are cusps considered to be critical?
 
10:04 AM
@BalarkaSen Also, he said that inflexion points are points where the derivative is 0 :|
 
@VibhavPant That is totally not true.
 
Anyways, thanks
@BalarkaSen Here's another example:
 
@VibhavPant As far as I am concerned, it is not terribly important whether an author classifies points where the derivative is not defined, or even end points as critical points or not. You should be keeping in mind that they must be in the domain of $f$ more than anything. There is no point in classifying a point as a candidate for maxima/minima if it isn't in the domain of the thing you are trying to optimize to begin with.
 
This is a differential equation: $[2\sqrt{xy}-x]\mathrm{d}y + y\mathrm{d}x = 0$
Making use of differentials :|
 
Eh?
What does it even mean?
Surely there's a typo? One of the $dx$ must have been $dy$?
 
10:17 AM
oops
 
@VibhavPant Well, it is a diff eqn.
 
@BalarkaSen The solution tells me the divide the entire thing by $dx$
 
Yes, do that.
 
@BalarkaSen My other calculus book says that one shouldnt take the derivative as a quotient
 
Heh.
Leibneiz notations.
One is used in nonstandard calc and another in usual calc. We can treat the diff operator as quotients too.
Make sure you are perfectly comfortable with Leibniz notations before jumping into differential equations.
 
10:20 AM
Like separating variables and stuff?
 
It is not actually the Goldbach conjecture. It is the Goldbar conjecture.
 
@VibhavPant Yes, you can treat differentials as variables.
 
yeah
 
@MatsGranvik So his name is (pronounced?) Christian Goldbar? Never knew that.
 
gotta go
bye
 
10:26 AM
Later :-)
 
@BalarkaSen I will not tell you where I heard this to not emabarrass the person who said it, but it was in a question session after a number theory lecture when a person in the audience asked: "Would you be interested in proving the Goldbar conjecture?"
Maybe it is not a true story, but that is what my ears heard.
 
10:44 AM
@AlexYoucis Heya.
You don't come here much often.
 
10:58 AM
hi
I was wondering if anyone could help me with math.stackexchange.com/questions/867696/… . Is it unclear/badly written?
 
No, it seems fine to me, @Anush :)
 
@Shaun Thanks. Shame no one likes it enough to upvote it, comment or to answer it :)
 
11:50 AM
@Anush What? It has 4 (and now 5) upvotes!

And you're welcome :)
 
12:10 PM
thank you :)
any idea how to approach it?
I mean approach solving it?
 
 
1 hour later…
1:15 PM
laol
 
 
1 hour later…
2:17 PM
I've got a quick limit question. Is this correct?
$$ \displaystyle \begin{aligned} \lim_{h \to 0} \int_{h}^{h + \frac{\pi}{4}} \dfrac{1}{\tan x} \text{ d}x \ & \overset{u = \sin x}= \ \lim_{h \to 0} \int_{\sin (h)}^{\sin (h + \frac{\pi}{4})} \dfrac{1}{u} \text{ d}u \\ & = \lim_{h \to 0} \left( \log \left| \dfrac{\sin (h + \frac{\pi}{4})}{\sin h} \right| \right) \\ & = \log \dfrac{1}{\sqrt{2}} - \lim_{h \to 0} \log | \tan h | \\ & = +\infty \end{aligned} $$
Hey @BalarkaSen!
 
Herro.
 
Hullo.
How've you been?
 
Not bad.
I am thinking about something.
 
What are you thinking about?
 
2:32 PM
@Khallil well, somebody asked whether there might be some connection of RH with Collatz and I gave a rough connection in between them, but i am not happy about my argument. i am trying to see if there's any other argument.
 
This might help to focus your mind:
https://www.youtube.com/watch?v=O4wezNlsxB0
^_^
 
i don't have the internet speed to watch youtube vids, sorry.
 
"Mathematics is not yet ready for such problems."
 
@skullpatrol what problems?
 
Collatz
 
2:35 PM
well, i am not trying to solve it!
just wondering whether there might be a connection with RH.
anyways, gotta go.
 
later pal
 
@BalarkaSen No prob. See ya later!
@skullpatrol Does my limit seem correctly computed?
 
3:26 PM
@Khallil The answer is correct, but the 3rd step seems dubious
 
@Hakim How so? Is it that I cancelled off the $sin(h)$ terms after expanding the numerator with the double angle formula?
I think it might be justified as the limit looks at the value the function approaches and specifically not the value at the point, which is $0$ in this case.
Is that ok, @Hakim?
 
@Khallil You didn't have to complicate things with the double angle formula, just the log property $\log(a/b)=\log a-\log b.$
 
@Hakim Oh right, yea.
So we would've had $$ \displaystyle \lim_{h \to 0} \left( \log \left( \dfrac{1}{\sqrt{2}} \right) + \log |\sin h + \cos h | - \log | \sin h | \right) = \log \left( \dfrac{1}{\sqrt{2}} \right) - \lim_{h \to 0} \log | \sin h | = + \infty $$
 
3:44 PM
@Khallil or simply $$\require{cancel}\lim_{h\to0}{\left[\cancelto{\ln(1/\sqrt2)}{\ln\left(\sin(h+\t‌​frac\pi4)\right)}-\cancelto{-\infty}{\ln\left(\sin h\right)}\right]}.$$
 
@Hakim Yep, I broke it down a bit more to ensure I didn't make any silly errors. ^_^
@Hakim Oh, that's so cool!
 
@Khallil Yep, just use \require{cancel} then \cancelto{}{}
 
@Hakim Let me have a try. $$ \displaystyle \require{cancel} \cancelto{3}{ \int_{0}^{3} \text{d}x} - \cancelto{2}{ \int_{0}^{2} \text{d}x} $$
Oh it's the other way around!
That's wicked. Thanks for teaching me that, @Hakim ^_^
 
You're welcome @Khallil ;) You can find much more here, and here
 
@Khallil Looks good
 
4:15 PM
laol
 
hello
please
if a functional is weakly lower semi continuous and coercive is it automaticaly bounded from below ?
 
@N3buchadnezzar You posted your first 'laol' at 13:15 in my local time and your second 'laol' at 16:15.
 
@Hakim loal
 
@Hakim $\color{olive}{\text{Those links are awesome!}}$
 
$\newcommand{\Khallil}{\text{Not sure if Naruto or Ramunjan}$
Seems they removed the option to define own commands :p
 
4:27 PM
Who's Ramnujan?
^_^
It's funny that you mention Naruto, because I'm currently watching this:
https://www.youtube.com/watch?v=Ok7tnT3aL8M
 
r9m
$$\color{green}{\text{O_O}}$$
@Khallil seen that atleast 10 times :D
 
I've seen the dub twice and the sub a few more times!
Danzo vs Sasuke is another one of my favourites.
Pain vs Naruto is of course, one of the greatest!
 
@N3buchadnezzar :O
 
r9m
4:36 PM
@Khallil Danzo vs Sasuke is awesome :)
 
what we can say about $a^2+b^2+c^2/abc$ minimum or maximum where a,b,c are positive?
 
@r9m y
@Khallil Look up Fengshi view.thespectrum.net/series/…
 
r9m
@N3buchadnezzar o! you watch Naruto too ?! never realized that .. :)
wait .. y = yes or y = why ?
 
@r9m ;) I have watched much anime in my young days, i prefer a tad more mature and adult anime these days. Except the funny ones like OP and fumoffu
@r9m y = y = yes
 
Anyone here know anything about actuarial science?
 
4:46 PM
:16800673 スラッと女 is rated 7.89
 
r9m
@N3buchadnezzar :O .. thanks for letting me know ;)
 
@N3buchadnezzar I'll have a look at it!
Just finished Sasuke vs Itachi. What a battle.
 
Quite funny but been maybe 6-7 years since I read it, I just glossed over my manga list. These days I really like Kingdom and Shamo
@Khallil Indeed. Better not blink, I really like the backstory on Itatchi and Sasuke
Sakura has a much weaker backstory
 
@N3buchadnezzar Does Sakura even have a backstory?
I thought it was just her wanting to catch up to Naruto and Sasuke.
 
Exactly
Wait, I found her backstory. It is just as deep as Naruto and Sasukes.
During her early years in the Academy, Sakura was frequently bullied by others due to her large forehead. To try and combat this, Sakura used her fringe to hide her forehead, fuelling the other kids' teasing by indicating she was sensitive about it. Ino Yamanaka, realising this, helped Sakura by giving her a red ribbon that she used as a way of drawing attention to the cuter features of her forehead, which helped Sakura overcome her insecurity.
 
4:54 PM
@N3buchadnezzar Woah ... that's exceptionally deep.
 
@Khallil =) Shamo is great, during a fight he kicks the other player in the eye. Oh, Berserk is awesome too.
 
5:19 PM
Are there more and more cranks posting "questions" on the site, or am I just cranky? :)
 
@ThomasAndrews Are you referring to those posts about Sierpinski conjecture? (in addition to some that I have missed)
 
Yeah, that one at the moment...
Googled his name and saw he is a pretty aggressive crank :)
But it feels like I've seen a few recently.
 
@ThomasAndrews From one of his publications he tries to prove: "à partir de 11, tous les nombres premiers se terminent par 1, 3, 7 ou 9." which translates to "from 11, every prime numbers ends with 1, 3, 7 and 9"
 
Well, at least that is correct :)
 
@ThomasAndrews He also seems to be making up conspiracy theories, quoting him: "*Si maintenant ce site est infesté de franc-ma-cons *" translates to "if now this site is infested with freemasons.." lol
 
5:27 PM
I got my fill of cranks for a lifetime in the 80s and 90s on Usenet. :)
 
I feel stupid because I have no idea what I am doing with inequalities
if $x\le y$ and $a\le b$ it means that $x+a\le y+b$ right?
Can you reverse this?
 
@Alizter No
 
No, $2+5\leq 4+4$ but $5\not\leq 4$.
 
Good I thought I was crazy
 
Only crazy when you insist that freemasons are preventing you from proving $5\leq 4$.
 
5:34 PM
@ThomasAndrews lol
 
@Alizter Want to work through something with me?
 
@N3buchadnezzar Yes. This inequality is giving me an unwarranted disturbance.
 
We have $\{x\} = x - \lfloor x \rfloor$ since $\lfloor x \rfloor =n$ when $x = \in [n,n+1]$ with $n\in\mathbb{N}$
 
no $[n, n+1)$
 
@N3buchadnezzar That's the floor function on the RHS, right? Is $\{ x \}$ the fractional part? Also, isn't the inequality strict at $n+1$?
 
5:37 PM
Meaning $\{1/x\} = x - \frac{1}{n+1}$ when $x \in [\frac{1}{n+1},\frac{1}{n})$
 
$1/x-\lfloor1/x\rfloor$
 
Should be 1/x yeah
 
$\{2.5\} = 2/5 - \lfloor 2.5 \rfloor$
 
$\lfloor 1/x \rfloor = 0,\;x\in(0, 1)$
 
Hence $$ \int_0^1 \left\{ \frac{1}{x}\right\}^2 \,\mathrm{d}x = \sum_{n=1}^{\infty } \left( \int_{1/(n+1)}^{1/n} \left( \frac{1}{x} - \frac{1}{n+1} \right)^2 \mathrm{d}x \right)$$
 
5:40 PM
@ThomasAndrews come on you understand everything. The real true is that the other part of the solution includes some confidential military and industrial techniques. — Thierno M. SOW 32 mins ago
 
$ \left\{ \frac{1}{2.5} \right\} = \frac{2}{5} - \left\lfloor \frac{2}{5} \right\rfloor = 0.4 - 0 $
 
@N3buchadnezzar That doesn't work. You need to do the 1/x sub
 
@Alizter Why? it looks correct to me...
 
r9m
if the user who started the bounty (not the OP) has answered the question first and has maximum number of upvotes on his answer .. will the bounty be awarded to his answer ?!
 
@r9m You can't get a bounty that you offered. Not possible.
 
5:45 PM
Yeah, that would be unfair, because you could offer a bounty, lots of people could then answer your question, and then you'd essentially be able to "revoke" the offered bounty.
 
@Alizter scratches head
 
@N3buchadnezzar $\displaystyle \int_0^1\left\{\frac1x\right\}^2\,\mathrm dx=\int_1^\infty\frac{\{x\}^2}{x^2}\mathrm dx$
 
r9m
@DanielFischer ic .. and if I was the second to answer (with 2 upvotes), and I edited my answer after a 3rd answer was added .. then who gets 1/2 bounty amount (assuming the one who puts the bounty doesn't award it manually before the grace period ) ?!
 
Hey !
 
Hi @MrWho
 
5:48 PM
Hi @Hakim
 
@Alizter I know that, I just do not see what is wrong with the way I wrote it.
 
Does anyone have time to advise me about my undergraduate program?!
 
$\{1/x\}=1/x-\lfloor 1/x \rfloor=n$ when $1/x\in[n, n+1)$
Yes I guess that would work
 
@r9m If the bounty is not manually awarded, a) if the bounty was by the asker, and (s)he accepted an answer during the bounty period [I don't know whether that answer must have been posted during the bounty period, or if that case also applies for answers posted previously], that gets the full bounty awarded by the system. Otherwise, the system only awards half the bounty, to the highest scoring answer posted during the bounty period, provided that answer has a score of at least 2.
I don't know what happens in case of a tie. Look on meta (meta.stackexchange.com), "How do bounties work" or something similar.
 
@N3buchadnezzar I am too confused
 
5:53 PM
@Alizter Nope.
 
@Alizter So
 
r9m
@DanielFischer okay thanks :D .. I was trying to estimate my chances of bagging +250 bounty :P
 
@r9m They increase if you stop hoping.
2
 
$$ \int_0^1 \left\{ \frac{1}{x}\right\}^2\,\mathrm{d}x = \sum_{n=1}^\infty 2n \log \left( \frac{n}{n+1} \right) + \frac{2n+1}{n+1}$$
Any closed form for this sum?
 
@N3buchadnezzar It is too confusing for me. Evaluate both ways and compare
 
r9m
5:57 PM
@DanielFischer :P .. okay .. LOL
 
@Alizter I have :p They are the same
 
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