Mathematics - 2014-12-03 (page 1 of 6)

teadawg1337

12:00 AM

@David You're welcome for that edit XD

David

Yes, thank you!

Salehen Rahman

My textbook says that if the $n \times n$ matrix $A$ is invertible, then let $I$ be the $n \times n$ identity matrix, the reduced row-echelon form of $[ A | I ]$ will yield $[I | A^{-1}]$

Is this true for all invertible $n \times n$ matrices?

Mike Miller

yes

teadawg1337

Oh no, I made a typo in that edit description.........

Noooo........

David

@teadawg1337, just claim it's the English (UK) version. ;)

teadawg1337

12:07 AM

There's no excuse for spelling "symbol" wrong

"e" and "o" are on opposite sides of the keyboard....

Pedro Tamaroff

@SalehenRahman Yes.

Salehen Rahman

@MikeMiller @PedroTamaroff thanks!

teadawg1337

12:18 AM

I found an intriguing new question here

David

Very intriguing. The guy should invent a new type of bike lock.

Douglas B. Staple

1:11 AM

I have performed a world-record breaking calculation of the prime counting function pi(x), with the double-check completed today. I was considering posting this on MSE in the following fashion: Q: How many primes are there less than or equal to 10^26? A: ... announcement of a new world record for pi(10^n) ...

Mike Miller

It would probably be closed as 'not a question'.

Douglas B. Staple

OK, that's the kind of thing I was worried about. I'm not sure why the "Answer your own question – share your knowledge, Q&A-style" option exists on this site, but I'm not interested in getting into an argument regarding on-topic / off-topic MSE questions.

It would've been in Q/A format, i.e. Question: what is pi(10^26) = ?, Answer: pi(10^26) = ... Anyway, thanks for your opinion. That supports my feeling that such announcements would not be welcome here.

Karl Kronenfeld

1:28 AM

Frankly, it has to do with the content of the question. You're right, those announcements do not make for appropriate questions here.

Anyway, congrats. :P

Committing to a challenge

@DouglasB.Staple What do you mean? You actually computed them all, or you have found a more accurate approximation?

Karl Kronenfeld

Wonders what other relations besides $ax=xa$ work here

teadawg1337

@UserX You're right, I'm gonna have to turn to MO

Committing to a challenge

What ever happened to our guy who was two steps off proving the Riemann hypothesis?

Some 19 year old second year I believe

Mike Miller

I finished that off a while ago

teadawg1337

1:37 AM

LOL

Committing to a challenge

xD

Mike Miller

It'll be in the Annals in about 4-5 months

Now I'm busy working on the Severi-Baum conjecture

teadawg1337

I may have made a new discovery, I'm gonna have to check on MO. I'm really nervous...

Committing to a challenge

Does noone actually remember him though, he was outsourcing every element of it

What is your discovery in regards to @teadawgggggg

Mike Miller

I try to forget

teadawg1337

1:40 AM

@Committingtoachallenge Dilogarithms and the Basel Problem

I encountered it while taking a different route on Tom Apostol's proof of the Basel Problem

It's the question I've been linking in chat for the past day or two

Committing to a challenge

Why declining all his awards? en.wikipedia.org/wiki/Grigori_Perelman

Oh wait he says

"I'm not interested in money or fame; I don't want to be on display like an animal in a zoo."

teadawg1337

@Commit I admire Perelman, he's inspired me to be modest about my skill set

Ugh, I'm afraid of posting on MO... What if it turns out to be a new discovery? I don't want significant attention from a large amount of people....

Mike Miller

I don't understand what you're upset about.

teadawg1337

Is my worrying unfounded?

Mike Miller

I don't even understand what you're worrying about.

teadawg1337

1:55 AM

MO=MathematicsOverflow, I'm afraid of posting this on there because it's either a new discovery or something that's already been found, neither of which are preferable to me

user4215

If A is over a fifth less than B, it means A is less than B times 1/5 ?

Mike Miller

What's your motivation for posting on MO? What question would you post?

Dhondup Tenzing

Hello, so I have a final coming up in 16 days and I'm curious whether anyone would have a few study tips or techniques?

teadawg1337

I've been searching online, and I can't find anything identical to what I've found in the answer I've posted. I'm curious to see if there's been any papers on exactly this, and MO is one of only places I have to turn since I'm not in college yet and I therefore don't have many other resources

Mike Miller

So your question would be "has this proof been written down somewhere before"? Then why is a yes answer bad, and why is a no answer bad?

teadawg1337

2:00 AM

Yeah, I'm kinda thinking irrationally...

Hmm, I wonder if I should make a post on the MO Meta before actually posting on the main

Mike Miller

Note that I'm not commenting either way on whether or not your question is appropriate for MO (since I am not a regular user, and because I haven't looked at your question for more than a second). I just didn't understand your worry.

If you want to do due diligence on whether your question is appropriate, you should search and see if similar questions (in the spirit of 'is this proof written down somewhere') have been asked before, and look through their help center to see what's on topic, &c.

teadawg1337

Oftentimes, even I don't understnad my worry...

@Mike I found two so far: this one and this one

I also can't find anything explicitly disallowing this type of question on the Meta, and I'd say it's worth a shot considering the positive vote count on both of those topics I've linked

Ted Shifrin

2:33 AM

@teadawg, I think that question belongs on SE, not MO. BTW, I have that exercise in my multivariable calculus/analysis book. I guess I don't get your point. I think it's symmetric, whether you do $dv du$ or $du dv$. But some tricky trig substitutions are indeed required ...

Oh, I see, it's not quite symmetric. You're ending up with $\log$ instead of $\arctan$. What happens if you integrate by parts?

teadawg1337

@TedShifrin It actually does turn out to be symmetric. Hang on, I see my intent wasn't entirely clear with the post

By Fubini's theorem, this MUST be true: $$2\int_0^{\arctan{\frac12}}\sec\theta\ln\left(\frac{\cos\theta-\sin\theta+1}{\s‌in\theta-\cos\theta+1}\right)\mathbb{d}\theta-\ln^2\left(\frac{\sqrt5-1}2\right)-‌\ln^2\left(\frac{\sqrt5+1}2\right}$$

Shoot... Editing in chat is a pain

Ted Shifrin

Yeah, it is ... and I see David H's and your answers, so now I'm really confused about what you want.

teadawg1337

At first I was trying to solve it by integrating the other way than Apostol did, and I encountered the integral that I was trying to prove

Maybe this will clear some things up (it's a document I linked in the original question), unless you've already read it

Ted Shifrin

It is a common phenomenon that certain iterated integrals can be done in elementary terms only in one of the two orders ...

The standard sort of example is $$\int_0^1\int_x^1 \frac{\sin y}y\,dy\,dx$$

But I guess I'm still missing your point :P

teadawg1337

2:49 AM

By Fubini's Theorem, the mess of symbols I've written above is equal to $\frac{\pi^2}6$

So I moved the constants to the other side and found an expression for the integral I was trying to prove

Ted Shifrin

Right. And from your question, I thought you and DavidH had it sorted out.

teadawg1337

Yes, we did. But I can't find any papers or articles online showing what I did, and I was going to ask on MO if there were and I just don't have the proper resources

I'm sorry I didn't say that earlier, @Mike and I had a mini-convo about it an hour or two ago

But wait, you said that that problem is in your multivariable calc/analysis book?

beginner

did you prove a knew thing?

teadawg1337

@beginner yes and/or no, that's what I'm trying to figure out

Ted Shifrin

Oh, I see. You'll find that lots of math that we "mortals" do doesn't get published when there's a better way to do it. :P Unless there's a serious reason for independent reasons to be interested in your approach/calculation, it's a wonderful exercise for you but probably not of great impact. :)

Hi @beginner

beginner

2:56 AM

hey professor!

teadawg1337

@Ted Dang, I knew that something like this had been done before

Ted Shifrin

@teadawg: A baby version of this phenomenon is this. I tell you to find the average distance from the origin to points inside the square $[0,1]\times [0,1]$. I tell you to do it in $xy$-coordinates. (The reasonable person would use polar and be done in a few seconds.)

beginner

what does addition of subspaces mean? i know direct sums but it is not one of them

Ted Shifrin

Direct sum is a special case. It just means take all vectors $v+w$ where $v\in V$ and $w\in W$ @beginner

Direct sum is the case where $V\cap W = \{0\}$.

beginner

what about just $U_1 + U_2$? instead of $U_1 \bigoplus U_2$ not sure if that shows cause my mums tablet doesnt render the math

Ted Shifrin

3:00 AM

I just told you $V+W$, @beginner. :)

beginner

oh sorry i miss read the full stop as a comma sorry

Ted Shifrin

Well, I punctuated not at all ... mea culpa :P

OK, I'm out of here for now. :)

teadawg1337

At first, I thought the $du dv$ approach was impossible and went with $dv du$, which was unsatisfyingly simple imo

beginner

okay thank you ted bye

teadawg1337

So I challenged myself and went the other way

It's a shame it's been done before, but it sure feels good to solve it :D

I should share that with my old calc teachers in high school xD

Nobody would solve it as a challenge problem at the end of a test

Thank you @TedShifrin

Will Hunting

3:15 AM

Ted's messages get 7 stars and 3 stars. The people reading the transcript are too serious, lol.

Now maybe they will flag what I just said as well, lol.

teadawg1337

flags Will's message

Will Hunting

In 3 hours, I will be seeing my shrink for the last time.

teadawg1337

And in 3 hours, I will be asleep :P

In all seriousness, congrats!

Will Hunting

I am not well yet. I just decided to stop taking my meds and stop psychotherapy, because the former does not help and the latter I can do on my own.

teadawg1337

@WillHunting Meds help more than you realize, trust me

Will Hunting

3:20 AM

@teadawg1337 Have you been taking them too?

teadawg1337

I was nearly institutionalized a few months ago...

I've been taking antidepressants for about 10 years

Will Hunting

I see. This explains your genius.

teadawg1337

This year is turning into a 5-month-long existential crisis

I just want it to stop already, lol....

Will Hunting

What is your condition exactly?

teadawg1337

major depressive disorder with suicidal ideation, generalized anxiety disorder, major OCD, ADHD, etc.

Will Hunting

3:25 AM

@teadawg1337 I see. I am mainly affected by my OCD. You are free to take your meds if you think they help you. But after taking them for a year, I don't think they help me.

teadawg1337

@WillHunting Meds can't really help with OCD, I'm pretty sure

Will Hunting

@teadawg1337 I went for two sessions of therapy, and I told the therapist that I already knew everything he was telling me.

teadawg1337

@WillHunting Therapy doesn't help me much either

I'm heading to bed, night everyone

beginner

3:57 AM

i wish i could learn faster

do i have to do psychology to learn faster?

Anonymous

NO

Anonymous

I actually got OCPD

beginner

what is that

Anonymous

a personality disorder

beginner

why did you say that all of a sudden

Anonymous

4:04 AM

@beginner LOL I don't know!

Anonymous

@beginner That's perhaps OCPD in action :D

Anonymous

I ctually read OCD,so I continued

beginner

i don't have any disorder i think. how do i learn faster ashwin?

Anonymous

You have to make your mind free of distractions

Anonymous

"You have to be fast only to catch flies"

beginner

4:09 AM

does the second thing you said mean that i have to take my time to learn, and makes you think of a car smashing bugs?

Anonymous

Don't worry about the speed

beginner

i am too young to have coffee but everyone says it is amazing and makes learning easier

Anonymous

LOL @beginner

beginner

what

is it not true??

i have forgotten what a span is, kaj taught me and now i am confused

is the span of $\mathbb{R}^2$ just $(x,y)$

or is it $x(1,0)$ and $y(0,1)$??

do i say $(3,9)\in\operatorname{span}((1,0),(0,1))$

@Ashwin where did you gooo, are you making coffee?!

i think i got it span$((1,0),(0,1))$ is the span of $\mathbb{R}^2$

i think that is one span and cause it is linearly independent it is the basis of $\mathbb{R}^2$

and a non basis of R^2 that is a span would be span((1,0),(0,1),(a,b)) for any a,b

Anonymous

4:26 AM

sorry

Anonymous

@beginner get coffee only if you are tired

Anonymous

@beginner it doesn't make learning easier

Anonymous

@beginner it just increases the time you can spend studying

beginner

i want to study less and learn more

well i mean i want to study a lot but i want to learn faster when doing it

Anonymous

meditation?

beginner

4:30 AM

is that the thing monks do where they sit down and hum for days

Anonymous

not only monks,most people do

beginner

does it make you faster at learning?

Anonymous

not for days lol

Anonymous

15-30 minutes is more than enough

beginner

oh i will look it up then, i will do it if it makes me learn faster :)

Anonymous

4:31 AM

@beginner why are you so obsessed with learning faster?

beginner

just because it seems good to learn faster

i get sad when i take a long time to learn stuff

Anonymous

In the long run,it isn't always

beginner

and it makes me want to give up

Anonymous

I will give a link to an article

Anonymous

wait searching

beginner

4:33 AM

ok thank you

Anonymous

arxiv.org/pdf/math/0503081v1.pdf

Anonymous

Point 6 is especially for you @beginner

Anonymous

read the entire thing if you can

beginner

point 6 is good. i will read all of them but i like point 6 you make a good point

Anonymous

Not me,it's William Thurston

beginner

4:38 AM

im only 11 so i am already ahead i think doing vector space stuff. maybe i should slow down and do the pages multiple times and i wont have trouble learning the next stuff

oh okay thank you for showing me though really cool!

Anonymous

yes sir

beginner

why am i sir?

i have never been a sir before hehe

Mike Miller

Thurston's a great writer.

beginner

mike can you look at my span and basis thing above is it right?

after 'or is it' i think is right

Anonymous

@MikeMiller Yes

beginner

4:43 AM

my parents say coffee is bad for me at my age, is that true or are they lying

Anonymous

It is true!

beginner

ok i thought they just wanted me not to be hyperactive or something

are video games bad they banned me from them too

Anonymous

if you get addicted to them,thy are bad

beginner

ok my friends play them all the time so i guess it makes sense

Anonymous

then they are loosers!

Mike Miller

4:45 AM

I was probably spending most of my times playing video games at your age, and I have a rotten brain now.

Anonymous

@MikeMiller Same goes here!

beginner

they play outside too but i cant show them math cause it is lame

Anonymous

@MikeMiller which was the game that you specialized?

Mike Miller

Ah, I don't remember anymore. That was a long time ago. And my brain is too rotten to remember :)

Anonymous

I ruined my past 5 years coz of games

beginner

4:47 AM

@mike is a basis a linearly independant span? like $span((1,0),(0,1),(3,3))$ spans R^2 but since the first two vectors make the third, the basis is $span((1,0),(0,1)$ because i cant make one into the other

what game? my friends play league of legeends

legends*

Anonymous

mine was San Andreas,COD,...

beginner

what is good for the brain for fun other than the maths?

Anonymous

that is not not absolute,I must mention!

beginner

i always ask other people to make sure things are true :)

especially if someone disagree i ask more people

Anonymous

I am afraid I do not know @begineer

beginner

4:52 AM

ok thank you for all your help :)

Anonymous

I gtg bye

beginner

5:06 AM

cya @ash

Balarka Sen

@UserX you need a bit graph theory to understand how that works.

beginner

balarka is the message about basis and spans 10 up to mike correct?

Balarka Sen

more than that, you need to recognize groups, @UserX, which you haven't done yet.

@beginner ?

beginner

i cant copy and past on my mums tablet pc, but it is just above ashwin saying San Andreas thing, that one @mike

Balarka Sen

basis elements are by definition linearly independent, yes, @beginner

beginner

5:14 AM

and the basis of R^2 is $span((1,0),(0,1))$?

Balarka Sen

basis of a vector space doesn't really make much sense. i'd rather you read the correct definitions first.

beginner

i mean of a field then

Balarka Sen

a basis of a vector space V over some field F, you mean

right, in that case the basis B of R^2 over R is {(1, 0), (0, 1)}

beginner

yeah sorry, i got them confused

so it is $\{(1,0),(0,1)\}$ not $span((1,0),(0,1))$?

Balarka Sen

no. i told you to read the definitions first.

beginner

5:17 AM

so it is a set with two elements(vectors here) and not a span of those two vectors ok

yeah ill reread them when i get the book again

Balarka Sen

yikes, i gotta go. @anon ping so you keep in mind the analogy between gal(\bar q/q) representation and monodromy.

beginner

thank you cya balarka

beginner

5:32 AM

can i simplify $\frac{(2n)!}{n!n1}$ somehow??

my brother texted me it as a challenge problem if i am to get chocolate from him

$n!=n(n-1)(n-2)\dots(n-n+1)(n-n)$

DanZimm

6:16 AM

@beginner hint: binomial coefficients

Integrator

6:42 AM

@beginner $$\binom{2n}{n}$$

DanZimm

7:29 AM

Good, and?

Balarka Sen

hello @DanZimm

DanZimm

Howdy, how's it going?

Balarka Sen

so-so. what about you?

DanZimm

hanging in there - unfortunately have a paper to write and no time to learn what I want to learn mathwise ;P

Martin Sleziak

7:47 AM

@Raff I did not know where to ping you (I cannot ping you on a deleted answer), so I tried here. I wonder whether it was necessary to delete your answer here. Mainly because the other answer references your answer: "and, as another answer says ...". Feel free to ping me here if some further discussion is needed.

Committing to a challenge

7:58 AM

Hey guys

Anonymous

8:51 AM

@BalarkaSen Are you there?

Committing to a challenge

9:06 AM

Hey @Ashwin, I don't think we have talked before

Balarka Sen

9:19 AM

@AshwinGokhale Yes

Daniel Amaya

given random numbers, without knowing each individual number, only the sum of the entire set, is there any way to calculate the absolute value of the sum of their differences? pastebin.com/R8GsEhzF

All I have is the sum of set A, and the sum of set B, and the knowledge that each set will always contain 50 numbers.

Now, it deviates from the standard definition of a set in that numbers can repeat themselves.

It differs from sequence in that they're not ordered

Probably better to call each a sequence though

Committing to a challenge

9:36 AM

@DanielAmaya Have you asked this on main? This chat isn't very active these days.

Will Hunting

9:46 AM

I am done with all meds and shrink appointments for now, yay!

Committing to a challenge

@WillHunting Now you are back in control of everything

Will Hunting

@Committingtoachallenge My one year challenge will start soon, lol.

Committing to a challenge

9:58 AM

@WillHunting Will you document it :)?

@WillHunting I would be interested to read how you are going honestly, especially with some of the books I have taken from you

Balarka Sen

@Committingtoachallenge Are you studying group theory?

Committing to a challenge

@BalarkaSen Now, or eventually?

user147163

Hello guys, I'm having trouble solving a fifth-degree polynomial, which has no solution in closed form. I is a polynomial of two variables, but one of them is made a parameter, as it is bounded with 0<a<<1. The paper, I am reading, states: "simplifying a to the lowest order, we find..."
What does it mean to simplify something to the lowest order? Thank you

Balarka Sen

Now @Comitting.

Committing to a challenge

@BalarkaSen I have done some group theory before in my courses, but I was still thinking like an engineer at the time, so I barely remember any of it. But yes I am just reaching some group theory again now in my texts

@BalarkaSen Why do you ask?

Balarka Sen

10:07 AM

How much have you learned, @Committing?

Committing to a challenge

@BalarkaSen In classes I had done rings and fields etc. Now I am just learning the term Monoid now

Much of the words used in Cohn aren't what we would use in an Australian uni

Balarka Sen

monoid is a well know term

Committing to a challenge

It appears to just be a semigroup

Balarka Sen

right, with an identity

Committing to a challenge

We never covered them for some reason in class

Balarka Sen

10:11 AM

@user147163 can you care to be explicit? what is the quintic you want to "solve"? what do you mean buy "solve"? which paper?

Committing to a challenge

We just did Binary operation -> Semi group -> Group -> Abelian group -> Ring -> Morphisms, if I remember correctly

Balarka Sen

how much have you studied about groups in particular? upto Lagrange's theorem? further? group actions?

Committing to a challenge

@BalarkaSen Some group actions, permutation groups, orbits, stabilisers, all in class, but I was graded a 4/7(pass), so I really do need to relearn it all in my texts

user147163

@BarlakaSen I sure can. The quintic is this one: http://math.stackexchange.com/questions/1046774/approximate-solutions-for-quintic-equation
And the paper is this one: http://www.physics.montana.edu/faculty/cornish/lagrange.pdf
By "solve" I mean finding zeros (at least that's what I think I mean...)

Committing to a challenge

Next semester I will be doing Abstract Algebra 2

Balarka Sen

10:15 AM

what do you mean by approximating solution where the quintic is not even on Q[x], @user147163?

the best you can do is to write down a series solution. is that what you want?

in that case, simplify the quintic to a standard form and reduce to Bring-Jerrard normal form, after which you can apply Lagrange inversion to get your "approximate solution".

user147163

I would like if you would read 10 lines in the paper i linked to. It's on page 4 - just from the quintic and down to the L1, L2, L3.
At least to make sure, I'm not understanding it wrong, when I ask you.

Balarka Sen

it seems like a whole bunch of words from physics. i can't read that sorry.

user147163

It is. Okay, well thanks for your help, then.

Balarka Sen

if you want to approximate the solutions, google with the keywords given above

or here's an algorithm to do it explicitly : math.stackexchange.com/questions/540964/… you can approximate the p-functions using their laurent expansions (google and you'll find them on wiki)

user147163

I will try that, thanks.

Committing to a challenge

10:29 AM

Are groups part of your primary interest @Balarka

Balarka Sen

yes and no @Committingtoachallenge. my (primary? probably) interest are about some "special" type of groups called galois group and it is conjectured that every group is a galois group (roughly).

don't take what i have said above literally.

DanZimm

@BalarkaSen are you working on proving such a conjecture?

(I'm familiar with it)

Balarka Sen

nah

i'd be mad to try to prove any of that.

i am not even familiar with the approaches out their, some of which has been successful to resolve some weaker cases

Committing to a challenge

@BalarkaSen Maybe in a years time I could discuss such things with you haha

I will have done atleast two third year courses in Algebra within the next year, and much of my textbooks

Balarka Sen

no hurries.

Committing to a challenge

10:48 AM

@ZachSaucier Thanks for that link, that is amazing.

@ZachSaucier I would be interested in seeing this merged with the game slay

Chris's sis

Greetings

Committing to a challenge

Hey @Chris'ssis

How are you?

Chris's sis

Not bad, thanks. I develop the little master theorem of Ramanujan (well, it doesn't belong to Ramanujan). You?

Committing to a challenge

@Chris'ssis Pretty bad actually haha, I slept for 11 hours for the first time in years since I stayed up for my grade release, and I have gotten little done as a result

Chris's sis

I see.

Committing to a challenge

10:57 AM

What is this theorem?

Chris's sis

@Committingtoachallenge Something inspired from this one mathworld.wolfram.com/RamanujansMasterTheorem.html. If things go well, I'm going to create an article with it.

Committing to a challenge

Wait hold on, I need to restart my browsers

Chris's sis

OK

Committing to a challenge

Why don't you have a website? I would be interested in reading some of your work. Or you want to put it all in the book?

Chris's sis

@Committingtoachallenge Well, maybe I'll have sometime. In my book I only wanna put some gems, I wanna my readers do not regret any of the money spent on it, but to deeply love it.

Committing to a challenge

11:06 AM

@Chris'ssis I am looking forward to it personally ;)

Chris's sis

@Committingtoachallenge :D

$$\int_0^{\pi/2} x\cot(x) \log(\sin(x)) \ dx$$

this is nicely connected to another series I love ...

Committing to a challenge

@Chris'ssis After next semester I should be able to talk to you about such problems haha.

Chris's sis

$$1+\frac{1}{3^3}\left(\frac{1}{2}\right)+\frac{1}{5^3}\left(\frac{1\cdot 3}{2\cdot4 }\right)+\frac{1}{7^3}\left(\frac{1\cdot 3 \cdot 5}{2\cdot4 \cdot 6}\right)+\cdots$$

@Committingtoachallenge I think you have to work hard then :D

Committing to a challenge

@Chris'ssis Definitely haha. I mean talk, not necessarily be able to solve many of these things

Chris's sis

@Committingtoachallenge Do you study at some mathematics uni?

Committing to a challenge

11:14 AM

@Chris'ssis Yes, I just finished my second year. But this semester was the only semester I worked with the mindset of a Math student, instead of as an Engineering student, like I was previously

Chris's sis

I see.

Committing to a challenge

I have done two years of math, with many passes and credits, but this semester was two high distinctions and two distinctions

Chris's sis

Still 2 years?

Committing to a challenge

I have one year until I complete a bachelor of science (pure mathematics), but the last year is the hardest, and then I may do honours year

The third year is pretty much all of the math

They throw in: Complex Analysis, Functional Analysis, Abstract Algebra II, Applied Mathematics II, PDEs, Differential Geometry and a few application ones. Also Optimisation theory, but I did that this semester for fun

Chris's sis

@Committingtoachallenge It would be interesting to see what books you have in your contry on integrals, series and limits. I'd be very curious about that. Maybe you also have such books at the library of your uni.

Balarka Sen

11:21 AM

@Committingtoachallenge Cool beans. Complex analysis is fun.

Hippalectryon

Beans ?

Oh nvm

Balarka Sen

:P

Committing to a challenge

@Chris'ssis I could see when Uni starts again in a few months xD

@BalarkaSen Yeah next semester seems a little intense haha. Functional Analysis, Complex Analysis, Abstract Algebra II, Coding and Cryptography and Operations research overload)

Balarka Sen

better finish this semester quickly. do lot of exercises though, @Committing, keep the theory level as minimal as possible.

Integrator

Knock Knock!

Committing to a challenge

11:23 AM

@BalarkaSen Minimise theory?

@BalarkaSen Isn't that the opposite of normal advice? Also my semester is done until March

@Integrator Who is there?

Balarka Sen

It is the opposite of normal advise, but it should be the ideal advise.

Integrator

@Committingtoachallenge Nobody!

Balarka Sen

In any case, we mathematicians are... nowhere near normal.

Hippalectryon

@BalarkaSen Depends

Balarka Sen

@Committing If you just read a bunch of theories, you might not know how they come up naturally and end up just remembering a bunch of names. If you do exercises, the theories would come up naturally, making you really understand that stuff.

Hippalectryon

11:25 AM

@BalarkaSen We're orthogonal to many people

Committing to a challenge

@BalarkaSen So exercises first and then the theory

Balarka Sen

@Hippa I guess we need to be tensored by Q to rationalize.

Hippalectryon

It depends @Committingtoachallenge

Balarka Sen

@Committingtoachallenge Not really.

Hippalectryon

Doing exercises first takes more time and can be a bit useless sometimes

Balarka Sen

11:26 AM

How about taking the theorems you have in your book as exercises?

Hippalectryon

However, it isn't good either to learn by heart things whose use/origin we don't know

Balarka Sen

I second @Hippa

Hippalectryon

I second @Hippa too :D

Committing to a challenge

My study method usually involves doing all the exercises until I can do them instantly, and then working out why

Hippalectryon

@Committingtoachallenge If you can do them instantly, they're probably not hard enough :-)

Committing to a challenge

11:28 AM

@Hippalectryon 'Until' xD

Hippalectryon

Even if you know your theorems.... well, some exercises will take some time to solve

Balarka Sen

Hippa has more expertise in mathematical pedagogy than me. zips lip

Committing to a challenge

I mean for example solving a time optimal control, the first time you do the problem can take over an hour, do the same problem the next day and it can still take half an hour, do it the third day and you can do it in <10 min

Chris's sis

There is only one way to get on top: you need to work crazy hard and be driven by a completely crazy passion.

Committing to a challenge

@Chris'ssis That is true

Hippalectryon

11:36 AM

@Chris'ssis Maybe in 10 years people will use your book in classrooms :D

Balarka Sen

another 10 years there will be no book on mathematics except @Chris'ssis's book, @Hippa

Chris's sis

@Hippalectryon That's a good joke. :-) I doubt people will be very serious as regards the book of an amateur with no background in math (there might be some exceptions though :-)).

Hippalectryon

Hehe

@Chris'ssis That's up to you to prove they're wrong :-)

Chris's sis

:D

Hippalectryon

That is, supposing you do not take 10 years to publish your book :c

Chris's sis

11:41 AM

@Hippalectryon lol, not really. The problem is that I'm waiting for some articles to be published.

Hippalectryon

I've probably said it 15 times already, but do notify me when they get published :D @Chris'ssis