Mathematics

I don't think this is an issue, but I AM allowed to print everything published on arXiv, right?

that would take a lot of paper. also they do look out for mass downloading.

But they look out for mass downloading mainly because of robots.

12:12 AM

There's this set of notes that like 800 pages long. I just want to print that one.

That's okay right?

Yes.

Jonas Teuwen

Good night.

thats great. copyright law is really weird so i got worried

@JonasTeuwen Good night.

good night

12:13 AM

@acassatt9 From wikipedia:
Files on arXiv can have a number of different copyright statuses:[18]

Some are public domain, in which case they will have a statement saying so.
Some are available under either the Creative Commons 3.0 Attribution-Share alike license or the Creative Commons 3.0 Attribution-non-commercial-Share Alike license.
Some are copyright to the publisher, but the author has the right to distribute them and has given arXiv a non-exclusive irrevocable license to distribute them.

if arXiv has a distribution license, that means I can print them out on my own since I was distributed them in pdf form, yes?

IANAL, but I am sure there should be no problem about it.

Well I'm contacting a printing & binding service to print and bind the article, so I don't want them to freak out because it's from a academic publishing website.

Ohh. In that case, I cannot help you because I am not even a US citizen.

haha

12:49 AM

zzzzZZzZZzZzZz

math101

1:09 AM

Hey @Charlie

@math101 hey

math101

So you are a mystery? lol

@math101 yes I am :)

kritzikratzi

1:57 AM

hey! i'm trying to find out if there are methods to have a runge kutta method yield same results on different timescales. e.g. stepping 1+1+1+1 or stepping 3+0.1+0.9 usually gives different results.

i'm quite sure the problem is known, i just have no idea how to phrase it properly

2:20 AM

@anon is ghost in the shell good?

"good"?

yes, good

you're asking someone who has a gits avatar. what could you hope to gain from asking me?

yes, I like the series and movies. not the manga.

is it famous?

yes

user19161

2:24 AM

I am now back to "blue". Today is a very sad day...

...

what is the character you have in the picture?@anon

lol

its mem right?

yes

user19161

2:26 AM

Haha, my god laughs.

what?

@anon is it the laughing man?

@Khromonkey he worships anon

It's not really a character, it's a sex doll from the second movie poster.

nope, laughing man (aka aoi) is a different avatar I have.

although it's debatable if the anonymous author of the email with the criticism of the murai vaccine is the true "laughing man" - this individual is only mentioned once in the entire series, in passing, though

is the laughing man the villain?

antagonist, sure. (in the first season) villain is presumptuous a word to throw around.

2:30 AM

Who is the major antagonist?

the Puppet Master?

user19161

@charlie I hope you are not upset by us. We did not mean to ignore you. I just don't feel like replying to every occurrence of hi in a chat room.

ok

in the first movie, the puppet master (aka project 2501) is the antagonist. in the second movie, it's the sex dolls (they become sentient and revolt). in the third movie, it is a different kind of "puppet master," and it is at first unknown if Motoko (usually the protagonist) is in this case the antagonist.

in the first season, it's apparently the laughing man, but then it is revealed there are actual villainous elements behind the micromachine therapy approval. in the second season, it is apparently a team of revolutionaries, then just one of the revolutionaries, then it is revealed there is an actual villain mastermind behind the scenes.

(I should have said criticism of the micromachine therapy approval decision over the murai vaccine earlier, not "criticism of the murai vaccine")

nice

well, good night all

user19161

@Khromonkey Good night.

user19161

2:37 AM

@anon Did you watch the movie series Death Note?

movie series? I watched the anime series and the manga, both good.

I have not seen the live-action movies.

user19161

I watched them all, the movies.

@Khromonkey Good Night

Donald Duck gets embarrassed when loses his tshirt? He doesn't wear bottoms!

2:59 AM

@math101 hello.

hi, can you help me show that the ideals ( a + b sqrt(-5) ) and ( a - b sqrt ( - 5 ) ) only intersect at the ideal generated by their norm? i.e. when the conjugates are multiplied. I think this is true, and it's true at least in the case I have to prove ( a = 2, b = 1 ). But i'm having trouble with it

ideals of what

one generated by a + b sqrt( - 5 ) and the other generated by its conjugate a - b sqrt( - 5 ) , a and b are integers

I tried to work out equations by brute force but I end up with two equations and four variables

haha

no, it's not

but I am out of ideas

oh I think I can do something here

I can reduce the number of variables

but saying that if p = (a + b sqrt ( - 5 ) )* k1 = ( a - bsqrt(-5) )* k2

then norm ( k 1 ) = norm ( k 2 ) and k1 and k2 should be conjugate

or is a unit

i'm asking ideals of which ring

Z [ sqrt ( - 5 ) ]

sorry

3:15 AM

i mean, am i being silly here or can't you just map a + b sqrt(-5) to a - (-b) sqrt(-5)

what do you mean?

are you saying the ideals are { a + b sqrt(-5) : a,b in Z } and { a - b sqrt(-5) : a,b in Z } ?

the principal ideals generated by ( a + b sqrt( -5 ) ) and ( a - b sqrt(-5) )

so all R-multiples of those two conjugates

ah so a and b are fixed?

yea

amWhy

3:23 AM

Slow night on Math.SE!

ah right ok. so you want to know how it can happen that $\left(c + d \sqrt(-5)\right)\left(a + b \sqrt(-5)\right)\in \langle a - b \sqrt{-5}$, thus $\left(c + d \sqrt(-5)\right)\left(a + b \sqrt(-5)\right)=\left(e + f\sqrt{-5}\right)\left(a + b \sqrt(-5)\right)$ for some $e$ and $f$.

sorry I can't parse latex in the chat

but yeah

you should get chatjax

just to make notation look nicer writing a + b sqrt( -5 ) as (a,b )

just when does (x,y) * ( a , b ) = (h,k ) *( a, -b )

should be only when (x,y) = (a, -b) and (h,k) = ( a,b )