Side note: If you have a variable @something in Perl 6, $something doesn't give you the number of arguments. They changed it so you need to access @something in a scalar context to get the count.
@Powerlord The Perl 5 book did mention that every sigil is basically a separate namespace, but then it also tells you that if @foo is a list, $foo is the number of elements therein
so I guess that if you assign both to @foo and $foo they become completely distinct variables, but if you only assign to @foo but not $foo then Perl tries to be smart?
Apparently, you can create a shortcut when first installing a game using GoG Galaxy. I forgot to enable that option for Witcher 3 when installing it, so I don't have a shortcut on my desktop.
According to their forums (http://www.gog.com/forum/general/desktop_shortcut/post4), you can enable an o...
@KevinvanderVelden Keep in mind that I don't routinely use C/C++. I know there are "safe" versions of it as well, but I couldn't tell you what the names of them are.
As for the last thing I did that needed to do a strcpy type operation, the devs switched over to some internal library of their own for common operations like that
That and they weren't allowing std::string, probably because it was a Valve Server Plugin and so it's based on some pre-2003 version of C++
I'm trying to make a vanilla spleef arena, with a redstone clock attached to a /setblock command. No matter how I tried, I could not get the command to set the block under the player air. this was the closest I got: /setblock ~ ~-1 ~ air is there some way I can attach the ~ ~-1 ~ to @p? If not wh...
Basically, we changed it so that our internal version of FindMap takes const char*, char*, size_t while Valve's took char*, int and modified the string you passed to it.
Hah, look at all these rubes who don't know the answer. Anyway, I'll let someone else explain why you're all fools because I'm laughing too hard. At your expense!
If you give it a utf8 encoded string then you're violating the contract (if you're casting a wide string to a narrow string and passing it to strlen I will smack you)
That's not "a function doing the wrong thing", it's "pretending that you're asking a different question, and being surprised that you're getting the same answer"
My team consisted of additonal three members:
Cassius
Athena
August
Yet it is shown that there could have been more.
How do I get the possibility to recruit them all?
@fredley The proper response to all forms of this riddle is to give them the finger and point out "Hangry" exists in at least the Collins English Dictionary.
My team consisted of additonal three members:
Cassius
Athena
August
Yet it is shown that there could have been more.
How do I get the possibility to recruit them all?
