How do I write $\ce{C_{2}{v}}$ properly in Latex so that the "2" and the "v" are both subscripted on the same subscript line? If I write it as $\ce{C_{2v}}$ (\ce{C_{2v}), I get an down-arrow symbol replacing the "v".
1 ml of $H_3PO_4$ was diluted to $250$ mL. $25$ mL of this solution required $40$ mL of $0.1$ N $NaOH$ for neutralisation. The density of the acid is $\dots$?
Here's my attempt: milliequivalents of NaOH = 0.1 * 40 = 4 = milliequivalents of H3PO4 = 25 * Normality of H3PO4. So the normality of H3PO4 = 0.16. I'm not sure what I'm supposed to do with this information.
The process to determine oxidation numbers is almost the same as for formal charges
The only difference is that for formal charges you cleave all bonds in the middle, while for oxidation numbers you drag both bond electrons to the more electronegative atom